A car traveling with constant speed travels 150 km in 7200 s. What is the speed of the car?

Answers

Answer 1
Answer: 75 km/hr, so  in other words 75 km per hour.

7200 s / 60 = 120 min
120 min / 60 =2 hr
so 150 km / 2 hr = 75 km per hour
Answer 2
Answer:

Answer:

The speed of the car is \boxed{75\,{{{\text{km}}} \mathord{\left/{\vphantom {{{\text{km}}} {{\text{hr}}}}} \right.\kern-\nulldelimiterspace} {{\text{hr}}}}} or \boxed{20.83\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}} .

Further Explanation:

Given:

The distance covered by the car is 150\,{\text{km}}.

The time taken by the car to cover the distance is 7200\,{\text{s}} .

Concept:

The speed of a car is the ratio of the distance covered by the car to the time taken by the car in covering the distance.

The expression for the speed of the car is:

v = (d)/(t)       …… (1)                                      

Here, v is the speed of the car, d is the distance covered and t is the time taken by the car.

Substitute the value of distance and time in the above expression.

 \begin{aligned}v &= \frac{{150\,{\text{km}}}}{{7200\,{\text{s}}\left( {\frac{{1\,{\text{hr}}}}{{60 * 60\,{\text{s}}}}} \right)}}\n&= \frac{{150}}{2}\,{{{\text{km}}} \mathord{\left/{\vphantom {{{\text{km}}} {{\text{hr}}}}} \right.\kern-\nulldelimiterspace} {{\text{hr}}}}\n&= 75\,{{{\text{km}}} \mathord{\left/{\vphantom {{{\text{km}}} {{\text{hr}}}}} \right.\kern-\nulldelimiterspace} {{\text{hr}}}}\n\end{aligned}

The speed of the car in terms of {{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}  can be expressed as.

\begin{aligned}v&=75\,{{{\text{km}}} \mathord{\left/{\vphantom {{{\text{km}}}{{\text{hr}}}}} \right.\kern-\nulldelimiterspace} {{\text{hr}}}}\left( {\frac{{1000\,{\text{m}}}}{{3600\,{\text{s}}}}} \right)\n&=75 *\frac{5}{{18}}\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}\n&= 20.83\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}\n\end{aligned}

Thus, the speed of the car is \boxed{75\,{{{\text{km}}} \mathord{\left/{\vphantom {{{\text{km}}} {{\text{hr}}}}} \right.\kern-\nulldelimiterspace} {{\text{hr}}}}} or \boxed{20.83\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}}\right.\kern-\nulldelimiterspace} {\text{s}}}}.

Learn More:

  1. A test car travels in a straight line along the x axis, the graph in the figure shows brainly.com/question/10772739
  2. A 1500-kg car accelerates from rest to 25 m/s in 7.0 s. What is the average power delivered by the brainly.com/question/7956557
  3. If no friction acts on a diver during a dive, then which of the following statements is true brainly.com/question/4633609

Answer Details:

Grade:Middle School

Chapter:Speed and distance

Subject:Physics

Keywords:Speed, velocity, distance, time, distance of 150 km, in 7200 s, speed of the car, ratio of distance, rate of change of distance.


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A 60 kg person walks up a 75 m tall hill. How much gravitational potential energy do they have at the top of the hill?

Answers

Answer:

45,000 J

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

GPE = 60 × 10 × 75

We have the final answer as

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Hope this helps you

You try to hit an annoying pigeon by throwing a ball straight up into the air with a velocity of 16 m/s. What is its velocity 0.5s into flight?

Answers

Answer:

20.9 m/s

Explanation:

Given that,

Initial velocity, u = 16 m/s

We need to find its velocity 0.5 s into flight when a ball straight up into the air. Let it is v. It will move under the action of gravity. Using first equation of motion to find it as follows :

v=u+at

Here, a = g

v = 16 + 9.8(0.5)

v = 20.9 m/s

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John can travel to atlanta 560 miles in 9 hours what is his velocity

Answers

Answer:

132

Explanation:

The steering wheel of a certain vehicle has a diameter of 34.6 cm, and it turns a shaft that is 8.9 cm in diameter. If a 94.8 N force is needed to turn the steering wheel, what torque is exerted on the wheel

Answers

Answer: 164Nm

Explanation: the torque exerted on the wheel is given by the expression

Torque=force*radius(of steering wheel )

Given force =94.8N

Diameter of wheel=34.6cm

Radius =34.6/2 =17.3cm

to metre 17.3/10= 1.73m

Torque =94.8*1.73

=164Nm

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Answers

Answer:

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Explanation:

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Answers

One pound is (around, actually it's a little more, but you have to round it down to make the number practically usable) 0.45 kilograms, so 120 pounts is 120* 0.45, which is around 54kg.