Ball A has mass 5.0 kg and is moving at -3.2 m/s when it strikes stationary ball B, which has mass 3.9 kg, in a head-on collision. If the collision is completely inelastic, what is the common velocity of balls A and B?

Answers

Answer 1

Answer: Momentum conservation in a completely inelastic collision works like this:
mA*vA+mB*vB=v(mA+mB)

Since B was initially stationary pB=0.
Plugging in numbers gives:
5*(-3.2)=v(5+3.9)
v= -1.79 m/s to the left.

Answer 2

Answer:

Answer:

A.) -0.40 m/s

B.) -3.60 m/s

C.) -1.80 m/s

Explanation:

By the law of momentum conservation:-

=>m1u1 + m2u2 = m1v1 + m2v2

=>5 x (-3.2) + 0 = 5v1 + 3.9v2

=>1.28v1 + v2 = -4.10 ---------------(i)

for elastic collision:-

=>v1 - v2 = u2 - u1

=>v1 - v2 = 0 - (-3.2)

=>v1 - v2 = 3.2 ------------------(ii)

by (i) + (ii) :-

=>2.28v1 = -0.90

=>v1 = -0.40 m/s

=>v2 = -3.60 m/s

=>m1u1+m2u2 = (m1+m2)v

=>5 x (-3.2) + 0 = (5 + 3.9) x v

=>v = -1.80 m/s

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Newton’s third law of motion says that for every action there is a(n) and opposite reaction.

Think about what subsequently happens to the ketchup, which is initially at rest, and use newton's first law to explain why this technique is so successful.

Answers

Newton's first law of ketchup is if the bottle of ketchup is smacked upward, the contents (the ketchup) will tend to remain in place, and it will be closer to the opening in the bottle.

Further explanation

If we are trying to get ketchup out of the bottle, the best way to do it is to turn the bottle upside down and give the bottle a upward smack which force the bottle rapidly upward.

Newton first law said that every object tries to continue in its state of rest or uniform motion unless an external force acted upon it (In an inertial frame of reference, an object either remains at rest or continues to move at a constant velocity, unless acted upon by a force). Newton first law describe the relationship between a body and the forces acting upon it, and its motion in response to those forces.

Inertia explained by Sir Isaac Newton in his first law of motion (Newton law of motion). The law states that an object at rest stays at rest and an object continues its state of motion until an external force acts on it. The examples are one's body movement to the side when a car makes a sharp turn

Learn more

Learn more about newton's first law https://brainly.in/question/4978079

Answer details

Grade: 9

Subject: physics

Chapter: newton's first law

Keywords: newton's first law

The ketchup inside the bottle is take out by shaking the bottle up and down. This process of bringing out the ketchup from the bottle make use of Newton’s Law of Inertia or the Newton’s first law.

Further Explanation:

The Newton’s first law of motion or the Newton’s law of Inertia states that a body continues to be in its state of rest or motion until and unless an external force is applied on the body that forces the body to change its state.

This law states that there needs to be a force in order to change the state of a body whether it is in motion or it is at rest.

The ketchup inside the bottle always settles down towards the bottom of the bottle. Now when it is required to take out the ketchup from the bottle, we hold the bottle upside down and shake it to bring the ketchup out of the bottle.

As the bottle is turned and shaken, the ketchup bottle suddenly comes into state of motion whereas the ketchup inside the bottle still remains in its state of rest. As the bottle goes up, the ketchup slides down to the neck of the bottle as it wants to remain in its initial position.

In this manner, when the bottle is shaken several times, the ketchup comes out of the bottle slowly. This process of taking out the ketchup from the bottle is due to the Newton’s law of Inertia.

The Newton’s first law or Law of Inertia has its several other applications in day to day life.

• The passenger tend to fall forward in a moving bus when the driver slams the brake suddenly. It happens because due to brakes, the bus comes to rest suddenly but the passenger’s body still remains in its state of motion and therefore, it tends to fall forward.

• The dust particles come out from a mattress when it is beaten up by a stick. The beating up the mattress sets up the mattress into motion but the dust particles remain in their state of rest and therefore, they fall out of the mattress.

Thus, the technique of bringing out the ketchup from the bottle by shaking it is an application of the Newton’s first law or the Newton’s Law of Inertia.

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3. A 700kg car driving at 29m/s hits a brick wall brainly.com/question/9484203

Answer Details:

Grade: High school

Subject: Physics

Chapter: Newton’s Laws of Motion

Keywords:

Ketchup, bottle, inertia, law of motion, first law, Newton’s law, Law of inertia, upside down, bring out ketchup, motion, rest, state, passenger fall forward, shake.

Can Someone Help ? !5 Points!!!If the weight of displaced water is greater than the weight of an object, then the object will:

A. float
B. sink
C. sink, then float

An object will float when:

A. buoyant force is equal to the weight of the object
B. buoyant force is less than the weight of the object
C. density is equal to the weight of the object
D. density is greater than the weight of the object

What is the buoyancy force on a 15 g object which displaces 60 mL of water? (Remember to change mL of water to grams and grams to kg)

A. 900 N
B. 25 N
C. 0.59 N
D. 0.25 N

An object has a density of 20 g/cm3. When placed in a cylinder, it displaces 5 mL of water. What is the mass of the object?

A. 0.25 g
B. 4.0 g
C. 100.0 g

Substance has a mass of 16.2 grams. It displaces 8.1 grams of water. What is its specific gravity?

A. 2.0
B. 5.5
D. 131.22

Answers

1) A. float

There are two forces acting on an object in the water: the weight of the object (downward) and the buoyancy (upward), which is equal to the weight of displaced water. If the weight of displaced water is greater than the weight of the object, it means that there is a net force directed upward, so the object will float.

2) A. buoyant force is equal to the weight of the object

As stated in the previous question, there are only these two forces acting on an object in the water (buoyant force and weight of the object), so if the two forces are equal, then the object is in equilibrium, so it will float.

3) C. 0.59 N

The buoyancy force is given by:

$B=\rho_L V_d g$

where

$\rho_L = 1000 kg/m^3$ is the density of the liquid (water)

$V_d=60 mL=6 \cdot 10^(-2) L=6 \cdot 10^(-5) m^3$ is the volume of displaced water

$g=9.8 m/s^2$ is the acceleration of gravity

Substituting numbers into the formula, we find

$B=(1000 kg/m^3)(6 \cdot 10^(-5) m^3)(9.8 m/s^2)=0.59 N$

4) C. 100.0 g

The density of the object is 20 g/cm^3, which is greater than the density of the water (1 g/cm^3): this means that the object will sink, so its volume is equal to the volume of displaced water.

Therefore, we have:

- object's density: $\rho=20 g/cm^3$

- object's volume: $V=5 mL=5 cm^3$

so, the mass of the object is

$m=dV=(20 g/cm^3)(5 cm^3)=100.0 g$

5) A. 2.0 g

The specific gravity of an object is given by the ratio between its density ( $\rho$ ) and the density of a reference substance ( $\rho_W$ ), in this case water:

$SG=(\rho)/(\rho_W)$

whe can rewrite each density as the ratio between mass and volume:

$SG=(m_o /V_o)/(m_w/V_w)$

where the suffix o refers to the object, while the suffix w refers to the water. However, if we assume that the object is completely in the water, the two volumes are equal, so we can simplify the formula:

$SG=(m_o)/(m_w)=(16.2 g)/(8.1 g)=2.0$

Explain why solar energy is considered an inexhaustible source of energy

Answers

-- The amount of energy radiated by the sun is not affected at all by how much
of it we use or don't use.

-- The sun is not expected to quit shining on us, or to change its rate of energy
output, at any time within the next several many human lifetimes.

Solar energy is going to keep arriving here, continuously, at the same rate,
free of charge, for a long long time, whether we feel like using it or not. It's
the closest thing to manna from heaven that has been seen around here for
thousands of years.

A bicyclist steadily speeds up from rest to 11.0m/s in 3.40s. How far did she travel during this time?

Answers

Answer:

To find the distance traveled by the bicyclist during the given time, we can use the formula:

Distance = (Initial Velocity * Time) + (0.5 * Acceleration * Time^2)

Since the bicyclist starts from rest, the initial velocity is 0 m/s.

Given:

Initial velocity (u) = 0 m/s

Final velocity (v) = 11.0 m/s

Time (t) = 3.40 s

Using the formula, we can calculate the distance traveled:

Distance = (0 * 3.40) + (0.5 * Acceleration * 3.40^2)

To find the acceleration, we can use the equation:

Acceleration = (Final Velocity - Initial Velocity) / Time

Acceleration = (11.0 - 0) / 3.40

Acceleration = 11.0 / 3.40

Now, we substitute the value of acceleration into the distance formula:

Distance = (0 * 3.40) + (0.5 * (11.0 / 3.40) * 3.40^2)

Simplifying further:

Distance = 0 + (0.5 * (11.0 / 3.40) * 11.56)

Distance = (0.5 * (11.0 / 3.40) * 11.56)

Distance = (0.5 * 11.0 * 3.40)

Distance = 0.5 * 37.4

Distance = 18.7 meters

Therefore, the bicyclist traveled a distance of 18.7 meters during the given time of 3.40 seconds.

A gyre is a set of currents that form:a. a line
b. a loop
c. weather
d. climate zones

Answers

A gyre is a set of currents that form b. a loop. The circulation of gyres are affected by global wind patterns, landmasses, and the planet's rotation. The circulation is also affected by temperature, as warm water goes up and cold water sinks. There are five major gyres in the world: North Atlantic, South Atlantic, Indian, North Pacific, and South Pacific.

Answer:

The answer is B. a loop hopefully this helps!

Where is the field of each charge the strongest ?(A. positive charge arrows pointed out)
(B.negative charge arrows pointed inward)

Answers

First we have to agree on what you mean by "strongest".

To me, "strongest" means the place where it exerts the greatest
force on another charge that happens to be passing by.

In both cases ... 'A' and 'B' ... that's going to be right smack on top
of the charge itself, or as close to it as you can get.

On drawings, it's the spot where the field 'lines' are closest together.

It makes no difference whether the original charges are positive or negative.

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