MATHEMATICS HIGH SCHOOL

4. Find the range of f(x) = -x + 4 for the domain {-3, -2, -1, 1}.O {7, 6, 5, 3}
O {-7, -6, -5, -4}
O {7, 6, 5,4}
O {-7, -6, -5, 3}

Answers

Answer 1
Answer: It’s this first one- 7,6,5,3
You can get this by plugging each of the x values into the expression -x+4
Hope that helps

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Which of the following represents the zeros of f(x)=3x^3-10x^2-81x 28? Answer choices: A.) 7, -4,1/3 B.) 7,-4, -1/3 C.) 7,4,1/3 D.) 7,4,-1/3
80% of what number is 35.
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1500 soldiers in a fort have provision for 48 days.After 13 days few soldiers join them and the food lasts 25 days how many soldiers join

Answers

Answer: This is a problem of inverse variation, where the number of days that the food lasts is inversely proportional to the number of soldiers in the fort. We can use the formula:

d = k / s

where d is the number of days, s is the number of soldiers, and k is a constant of proportionality. We can find the value of k by using the initial information:

48 = k / 1500 k = 48 * 1500 k = 72000

Now we can use the information after 13 days to find the new number of soldiers. Let x be the number of soldiers who joined the fort. Then we have:

25 = 72000 / (1500 + x) 25 * (1500 + x) = 72000 37500 + 25x = 72000 25x = 34500 x = 1380

Answer: The number of soldiers who joined the fort after 13 days is 1380.

Why is it so hard for people to learn math?

Answers

Answer:

I don't know, I kind of wonder the same thing sometimes. But everyone understands things at a different rate, so that's why I'm here helping people by answering their questions and doing my best to explain how I got there.

thank you for the free points though :)

Answer:

because they are over thinking easy thing and getting stressed out.

Step-by-step explanation:

this is what happened to me

MDM4U11. Avery and Bradley work at a large electronics manufacturer that produces DVD players. The
defective rate on the assembly line has gone up to 12% and the manager wants to know the
probability that a skid of 50 DVD players will contain at least 3 defective units.
a) Help Avery use the binomial distribution P(x)=, C.pqrs to answer this question

Answers

Answer:

0.9487

Step-by-step explanation:

a) The probability of having a defective product = p = 12% = 0.12

The probability of not having a defective product = q = 1 - p = 1 - 0.12 = 0.88

The number of DVD players = n = 50

X is the number of defective products.

The  probability that a skid of 50 DVD players will contain at least 3 defective units = P(X ≥ 3) = 1 - P(X ≤ 2)

P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)

Using binomial:

P(X = 0) = C(n,x)p^xq^(n-x)=C(50,0)p^0q^(50-0)=(50!)/((50-0)!0!)*0.12^0*0.88^(50-0)=0.0017

P(X = 1) = C(n,x)p^xq^(n-x)=C(50,1)p^1q^(50-1)=(50!)/((50-1)!1!)*0.12^1*0.88^(50-1)=0.0114

P(X = 2) = C(n,x)p^xq^(n-x)=C(50,2)p^2q^(50-2)=(50!)/((50-2)!2!)*0.12^2*0.88^(50-2)=0.0382

P(X ≤ 2)= 0.0017 + 0.0114 + 0.0382 = 0.0513

P(X ≥ 3) = 1 - P(X ≤ 2) = 1 - 0.0513 = 0.9487 = 94.87%

What is the area of a circle with a diameter of 200cm? Use 3.14 for pie.

Answers

Answer:

A≈31415.93cm²

Step-by-step explanation:

During every soccer game that Ronald plays, he runs all over the field. In his last game, he played on a soccer field that was 69,300 square feet. There are 3 feet in a yard. What is the area, in square yards (sq yd), of the soccer field where Ronald played his last game? Group of answer choices 7,700 sq yd 23,100 sq yd 207,900 sq yd 623,700 sq yd

Answers

Answer:

The area of the soccer field where Ronald played his last game is 7,700 sq yd.

Step-by-step explanation:

From the question,

The area of the soccer field where Ronald played his last game was 69,300 square feet.

To determine the area, in square yards (sq yd), of the soccer field where Ronald played his last game, we will convert 69,300 square feet to square yards.

Also, from the question

There are 3 feet in a yard, that is, 3 feet = 1 yard

If 3 feet = 1 yard

∴ 3² square feet (ft²) will be equal to 1² square yard (yd²)

That is,

9 square feet = 1 square yard

Now,

If 9 square feet = 1 square yard

Then, 69,300 square feet will be

(69,300 square feet × 1 square yard) / 9 square feet = (69300/9 )square yards

= 7700 square yards (sq yd)

Hence, the area of the soccer field where Ronald played his last game is 7,700 sq yd.

The sides of a ladder are parallel. Since the rungs are perpendicular to one side of the ladder, what conclusion can be made?The sides are parallel to the rungs.
The rungs are perpendicular to the other side.
The sides are perpendicular to each other.
The rungs are parallel to the sides.

Answers

When a line passes through two parallel lines, then we can use corresponding angles and alternate interior and exterior angles to determine the congruent angles. In this set-up, it is understood that B. The rungs are perpendicular to the other side. 
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