4x^2 +28x -32 =0 solve this problem?

Answers

Answer 1
Answer: 4x^2+28x-32=0 \ \ \ |:4 \n\n x^2+7x-8=0 \n\n x^2+8x-x-8=0 \n\n x(x+8)-(x+8)=0 \n\n (x+8)(x-1)=0 \n\n \nx+8=0 \n\n \boxed{x=-8} \n\n\n x-1=0 \n\n \boxed{x=1} \n\n\n \boxed{\boxed{S=\{-8;1 \}}}
Answer 2
Answer: we know that if xy=0 then x or/and y=0


4x^2+28x-32=0
factor out the 4
4(x^2+7-8)=0

factor out the x^2+7-8
we must find out what two numbers multiply to get -8 and add to get 7
the numbers are 8 and -1

so 4[(x-1)(x+8)]=0

we know that if exg 4y=0 then y=0
so
therefor
(x-1)(x+8)=0
set each to zero
x-1=0
x=1
x+8=0
x=-8

x could be 1 or -8

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Decribe how you regroup when you find the sum of 64 + 43

Answers

You would Not have to regroup for this problem
first u add the ones place and you get 7 then you add the tens place which u get ten so your answer is 107

How do I do this?? Help!

Answers

Hi there!

In order to use the elimination method, you have to create one variable that has the same coefficient. This is to be able to eliminate one variable and have a one variable equation (which you can then solve).

In your case, we'll have the "x" have the same coefficient by multiplying the top equation by 4 and the bottom equation by 2 :

4( -2x + 3y = -4) → -8x + 12y = -16

2( 4x - 2y = 16) → 8x - 4y = 32


Now that both of your equation have a variable with the same coefficient, you need to choose rather you need to add or subtract the equations in order to get rid of the variable (in this case we want to get rid of the "x").

In your case, you want to add both equation together which will give you :

8y = 16


Now that you only have one variable, all you need to do now is solve the equation for "y" :

8y = 16

Divide each side of the equation by 8

y = 2 → Your answer


There you go! I really hope this helped, if there's anything just let me know! :)


This is how I did it.

A,B,C,D? Please help meee!!

Answers

C I believe because you multiply a lot in this equation
1 because you they added 7 and 9

OK GUYS I WOULD LIKE SOMEONE TO PLUG IN THE VALUES FOR ME PLEASE FOR X TO MAKE THIS TRUE SO I CAN GRAPH THE EXPONENTIAL GRAPHS. SO Y=-4+ SQAURE ROOT X+2 SO AT LEAST 4 X VALUES TO MAKE THIS TRUE AND FOR THIS ONE PLEASE:Y=2+SQUARE ROOT OF X+1 AT LEAST 4 X VALUES THAT MAKE THIS TRUE SO I CAN PLOT IT ON THE GRAPH

Answers

we see that we have some nasty sqrt signs
try to use x values that yield perfect squares inside the sqrt sign like 1,4,9,16, or ones that make the inside 0


first one

y=-4+√(x+2)
try some nice values for ease of graphing

ok so try x=-2
y=-4
(-2,-4)

x=-1
y=-3
(-1,-3)

x=-1
y=-3
(-1,-2)

if x=7
y=-1
(7,-1)

if x=14
y=0
(14,0)

so we have
(-2,-4)
(-1,-3)
(2,-2)
(7,-1)
(14,0)




second one
y=2+√(x+1)


if x=-1
y=2
(-1,2)

if x=0
y=3
(0,3)

if x=3
y=4
(3,4)

if x=8
y=5
(8,5)

we have

(0,3)
(-1,2)
(3,4)
(8,5)












 
first one
y=-4+√(x+2)
so we have
(-2,-4)
(-1,-3)
(2,-2)
(7,-1)
(14,0)

second one
y=2+√(x+1)
(0,3)
(-1,2)
(3,4)
(8,5)

First question do u have a graphing calculator?? If so, go to the y= menu and type in 2+ (2nd x^2) square root of x+1then hit 2nd and then graph find any coordinate pair you want or just hit the graph button and look at the exponential graph Keep in mind I am explaining the steps to take on a Texas Instruments TI84 plus CE calculator Good luck!!

What is 5 divided by -2/8? Show your work

Answers

The answer is -0.3125.
The answer is -20. See attached picture for work.

What to numbers have the LCM of 48 and GCF of 4?

Answers

12, because if you divide you get 48/4=12 which is your answer