The object falling near the Earth's surface is rarely under free fall because of the air resistance experienced by the body.
Explanation:
According to the Newton's law of gravitation, each and every body applies an attractive force on another body kept at a particular distance. This force experienced by the body is directly proportional to the product of the masses of the body and inversely proportional to the square of distance between them.
The Earth also pulls the body towards it by the action of the attractive gravitational force. When a body falls towards the Earth under the action of the gravitational force, it moves with an acceleration. The acceleration of the body when it falls freely under the action of gravity is termed as the free fall.
The earth's atmosphere plays a significant role in the motion of the object as it falls under the gravity. The air resistance experienced by the object reduces the acceleration of the object and therefore, the object is no longer under the free fall.
Thus, The object falling near the Earth's surface is rarely under free fall because of the air resistance experienced by the body.
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Answer Details:
Grade: High School
Subject: Physics
Chapter: Acceleration
Keywords:
object, acceleration, gravitation, rarely, free, fall, gravitation, newton's, air, resistance, atmosphere, object.
Answer:
C
Explanation:
B. an unstable arrangement of electrons
C. more than eight electrons in their valence shell
D. fewer than eight electrons in their valence shell
Answer:
The torque about the origin is 5.0 N.
Explanation:
To calculate the torque (τ) about the origin, you need to know both the force (F) and the position vector (r) from the origin to the point where the force is applied. The formula for torque is:
τ = r × F
Where:
- τ is the torque vector.
- r is the position vector.
- F is the force vector.
In this case, you're given the force vector F = 5.0 y N, where "y" represents the unit vector in the y-direction.
Assuming that the particle is located at a position where the position vector r is given as (x, y), you need to express the position vector in terms of unit vectors. Since the force is applied along the y-axis, you can write the position vector as:
r = x i + y j
Now, you can calculate the torque:
τ = r × F
τ = (x i + y j) × (5.0 y N)
When you take the cross product, the component of the position vector along the direction of the force will contribute to the torque. In this case, only the y-component of the position vector (y j) is along the direction of the force (5.0 y N).
So, the torque about the origin is:
τ = y (5.0 y N)
Now, you can calculate the magnitude of the torque:
|τ| = |y (5.0 y N)| = 5.0 |y|^2 N
The magnitude of the unit vector "y" is 1, so:
|τ| = 5.0 N
The torque about the origin is 5.0 N.
Answer:
The temperature of the Aluminium plate 44.84⁰C
Explanation:
Number of transistors = 4
Since the heat dissipated by each transistor is 12W
Total heat dissipated, Q = 4 * 12 = 48 W
Q = 48 W
Cross sectional Area of the Aluminium plate, A = 2(l * b)
l = Length of the aluminium plate = 22 cm = 0.22 m
b = width of the aluminium plate = 22 cm = 0.22 m
A =2( 0.22 * 0.22 )
A = 0.0968 m²
From the heat balance equation, Q = hAΔT
h = 25 W/m²·K
A = 0.0968 m²
ΔT = T - T(air)
T(air) = 25°C
ΔT = T - 25°C
Q = 25 * 0.0968 * ( T - 25)
Q = 2.42 (T - 25)
Substitute Q = 48 into the equation above
48 = 2.42 (T - 25)
T - 25 = 19.84
T = 25 + 19.84
T = 44.84 ⁰C
Answer:
B. The surface of the Earth heats the air that contacts it.
Explanation:
Conduction is a mode of heat transfer in which energy is transferred from a hot molecule to the neighboring molecules due to contact. Thus, heat energy is transferred from one molecule to another in the process.
Therefore, the air that comes in contact with the surface of the earth heats up by conduction. Since the surface of the earth is heated up due to the radiation from the Sun.
Answer: B.
Explanation: I took the test. Also, after my diagnostic I just wanted to see if my answers were correct lol.