HELPPPPP ASAP PLSSSS !!!!!!!!!

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Answer 1

Answer:

Answer:

maybe i can help for you where the question

Related Questions

The liquid substances mercury (density = 13.6 g/mL), water (1.00 g/mL), and cyclohexane (0.778 g/mL) do not form a solution when mixed; instead, they separate in distinct layers. List how the liquids would position themselves in a test tube. Rank the liquids from the top of the tube to the bottom.
Ice is put into a glass of coke energy flows from ______________to________________.
Given the parent compound, give the mass fragment that is evident in m/z 71. Include any hydrogen atoms and the charge.
When forces attracting solvent particles to each other are broken what is provided for a solution. 1. Energy for the solute to precipitate 2. Space for the solute in the solvent3.Inertia for the solute to move into the solvent4. Nothing is provided
A radioactive nuclide is used to detect eye tumors. An atom of this radionuclide contains 15 protons, 15 electrons, and 17 neutrons. Which is symbol of this radionuclide?

As the first five elements in Group 15 areconsidered in order of increasing atomic number,
first ionization energy
(1) decreases
(2) increases
(3) decreases, then increases
(4) increases, then decreases

Answers

The correct answer is option 1. The first ionization energy, in group 15 elements in increasing atomic number, decreases. Ionization energy is the amount of energy requires to detach one electron from the atom. In the periodic table, the ionization energy decreases as one goes down.

Answer: The first ionization energy for the first five elements of Group 15 decreases.

Explanation:

Ionization energy is defined as the energy required to remove an electron from the outermost shell of an isolated gaseous atom. It is represented as $E_i$

$X(g)\rightarrow X^+(g)+1e^-;E_i$

Ionization energy decreases as we move down the group. This happens because the number of shells increases as we move down the group. The electrons are added in the new shell around the nucleus.

This results in the shielding of outermost electrons more from the inner ones, which decreases the attraction between the outermost electrons and the nucleus. Hence, the removal of electron from the outermost shell becomes easy and requires less energy.

Hence, the first ionization energy for the first five elements of Group 15 decreases.

What is your question? HIGH SCHOOL CHEMISTRY 5+3 pts To ensure that the air in the shuttle remains free of excess CO2, engineers test the air-purification system. They combine 1.000 × 103 g LiOH with 8.80 × 1 02 g CO2. The reaction produces 3.25 × 102 g H2O. What is the limiting reactants in this test reaction

Answers

The balanced reaction is:

2LiOH + CO2 = Li2CO3 + H2O

We are given the amount of the reactants to be reacted. This will be the starting point of our calculations. To determine the limiting reactant, we convert the amounts from grams to moles.

1.000 × 10^3 g LiOH (1 mol / 25.95 g) = 38.54 mol LiOH

8.80 × 10^2 g CO2 ( 1mol / 44.01 g) = 20.00 mol CO2

From the balanced reaction, the molar ratio of the reactants is 2:1. This means that every two mole of lithium hydroxide, 1 mole of carbon dioxide is needed. It is clear that, from the given amounts, CO2 is the limiting reactant.

CO2 is the limiting molecule.

What is the empirical formula for a compound if a sample contains 3.72 g of P and 21.28 g of Cl?

Answers

3.72/30.97=0.120/0.120=1
21.28/35.45=0.600/0.120=5

PCl5

Answer:

PCI5

Explanation:

For a particular reaction, ΔH = -144.6 kJ and ΔS = -301.2 J/K. Calculate ΔG for this reaction at 298 K.

Answers

The Gibbs free energy change for this reaction at 298 K is approximately -54,484.8 J.

Determining the Gibbs free energy change

Calculating the Gibbs free energy change (ΔG) for a reaction at a given temperature using the Gibbs-Helmholtz equation,

ΔG = ΔH - TΔS

ΔG = (-144,600 J) - (298 K)(-301.2 J/K)

ΔG = -144,600 J + 90,115.2 J

ΔG = -54,484.8 J

Converting to kilojoules:

ΔG = -54,484.8 J / 1,000

= -54.48 kJ

Learn more on Gibbs free energy change here brainly.com/question/13765848

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To calculate, I would need to know if the final answer is supposed to be in kJ or in J/K.

Either way, use the Gibb's Formula:
ΔG= ΔH-TΔS

If the final answer is supposed to be in J/K then plug-in your values to the formula and simply solve.

However, if your final answer is supposed to be in kJ, your first step would be to convert ΔS from J/K into kJ.

This is simply done by dividing the given ΔS by 1000 ----> (-301.2/1000).
(we divide by 1000 because by definition that's what a "kilo" is )

New ΔS value= -0.3012 kJ

Now all you have to do is plug-in all the values into the formula.
ΔG= ΔH-TΔS
ΔG= (-144.6 kJ) - 298K(-0.3012kJ)
= -54.84 kJ

Since the ΔG is negative, this means that the reaction is spontaneous.

Hope this helps! :)

Identify the chiral carbon in amphetamine (benzedrine)

Answers

Chiral Carbon is a carbon atom that is attached to 4 different types of atoms or group of atoms

In Amphetamine, there is only 1 carbon that have 4 different types of atoms, so there is only 1 Chiral Carbon in it which have 2 optical isomers :

PhCH2CH(NH2)CH3

A compound that contains both potassium and oxygen formed when potassium metal was burned in oxygen gas. the mass of the compound was 7.11 grams. The mass of the potassium metal was 3.91 grams. What mass of oxygen was involved in this reaction? Justify your answer.

Answers

Answer:
3.2 g of O₂

Solution:
This reaction is for the formation of Potassium Superoxide, The reaction is as follow,

K + O₂ → KO₂

First let us confirm that either the given amount of Potassium produces the given amount of Potassium oxide or not,
So,
As,
39.098 g (1 mole) K produced = 71.098 g of K₂O
So,
3.91 g of K will produce = X g of K₂O

Solving for X,
X = (3.91 g × 71.098 g) ÷ 39.098

X = 7.11 g of K₂O

Hence, it is confirmed that we have selected the right equation,
So,
As,
39.098 g of K required = 32 g of O₂
So,
3.91 g of K will require = X g of O₂

Solving for X,
X = (3.91 g × 32 g) ÷ 39.098 g

X = 3.2 g of O₂

The mass of oxygen that was involved in the reaction is calculated as below

mass of the oxygen =mass of the compound- mass of the potassium

that is 7.11 grams -3.91 grams= 3.2 grams of oxygen is involved

This is because the mass of the compound composes the mass of potassium + mass of the oxygen

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