What is the smallest value of the force F such that the 8.0 kg block will not slide down the wall? The coefficient of static friction between the block and the wall is 0.4.Select one:

a. 10N

b. 100N

c. 200N

d. 98N

Answers

Answer 1
Answer:

The smallest value of the force that will make the block not to slide down is 10 N.

We'll begin by calculating the normal reaction. This can be obtained as follow:

  • Mass (m) = 8 Kg
  • Acceleration due to gravity (g) = 10 m/s²
  • Normal reaction (N) =?

N = mg

N = 8 × 10

N = 80 N

Finally, we shall determine the frictional force.

  • Coefficient of friction (μ) = 0.4
  • Normal reaction (N) = 80 N
  • Frictional Force (F) =?

F = μN

F = 0.4 × 80

F = 32 N

Since the frictional force is 32 N, therefore, a force lesser than the frictional force will make the blocknot to slide down.

From the options given above, only option A has a force that is lesserthan the frictional force.

Therefore, the correct answer to the question is Option A. 10 N

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Answer 2
Answer:

Final answer:

The smallest value of the force that will not slide the 8.0 kg block down the wall is 31.36 N.

Explanation:

To determine the smallest value of the force such that the 8.0 kg block will not slide down the wall, we need to consider the static friction between the block and the wall. The formula for static friction is fs = μs * N, where μs is the coefficient of static friction and N is the normal force. In this case, the normal force is equal to the weight of the block, which is mg = 8.0 kg * 9.8 m/s^2 = 78.4 N. Therefore, the smallest value of the force is equal to the maximum static friction force, which can be calculated as fs = 0.4 * 78.4 N = 31.36 N. So the correct answer is 31.36 N.

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Answers

Answer:

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Explanation:

Units such as Kilogram, Mass and Time are said to be fundamental units because they are independent.

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Physics question WILL GIVE BRAINLIEST!!! A 1,600 kg train car rolling freely on level track at 16 m/s bumps into a 1.0 x 10^3 kg train car moving at 10.0 m/s in the same direction, and the two latch onto each other and continue together. What is their final speed?10 m/s
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6.0 m/s
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Answers

Answer:

v'\approx 14\ m/s

Explanation:

Linear Momentum

Two objects of masses and moving in a linear path at speeds and respectively have a total momentum of

p=m_1v_1+m_2v_2

When the objects collide, a change of conditions occurs and they start to move at different speeds. The necessary condition to find the after-colliding speeds is the conservation of linear momentum that states the total momentum of an isolated system doesn't change regardless of the internal interactions of the objects. Thus, the new momentum is

p'=m_1v_1'+m_2v_2'

And they must be the same, thus

m_1v_1'+m_2v_2'=m_1v_1+m_2v_2

We know both cars stick together after the collision, so the final speed is common to both, and the above formula becomes

(m_1+m_2)v'=m_1v_1+m_2v_2

Solving for v'

\displaystyle v'=(m_1v_1+m_2v_2)/((m_1+m_2))

Plugging in the values, we have

\displaystyle v'=((1600)(16)+(1000)(10))/((1600+1000))

\boxed{v'=13.69\ m/s}

Correct option (closest to the computed speed): 14 m/s

During which period did the first large herbivores and carnivores appear?

Answers

The first large herbivores and carnivores appeared during the Mesozoic Era, which is divided into three periods-- Triassic, Jurassic and Cretaceous. The herbivores and and carnivores increased in size during the Jurassic Period. And some of the largest dinosaurs emerged during this period as well.

As you move toward a warning siren, the pitch _____.increases
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stays the same
disappears

Answers

Answer: Increases.

Explanation:

Warning siren is generally used to make people alert of danger. Danger can be anything associated with the health and hazard.

Warning siren can be due to tsunami, earthquake, fire, flood, et cetera. The pitch of siren is low when a person is afar from the siren.

As the person moves close to the siren, the pitch of siren increases.

Answer:

As you move toward the siren the pitch should get louder

Explanation:

Magnesium is a metal that is commonly used in products that needed to be light weight. Suppose a 2.00kg piece of magnesium has 8160 j of entertainment added to it it's temperature increases 4K what is the specific heat of magnesium

Answers

Given that,

Mass of magnesium, m = 2 kg

Heat added to it, Q = 8160 J

Increase in temperature, \Delta T=4\ K

To find,

The specific heat of magnesium.

Solution,

Th formula that is used to find the heat required to raise the temperature in terms of specific heat is given by :

Q=mc\Delta T\n\nc=(Q)/(m\Delta T)\n\nc=(8160\ J)/(2\ kg* 2\ K)\n\nc=2040\ J/kg-K

So, the specific heat of magnesium is 2040\ J/kg-K.

Peregrine falcons frequently grab prey birds from the air, as BI0 in Example 9.10. Sometimes they strike at high enough speeds that the force of the impact disables prey birds. A 480 g per- egrine falcon high in the sky spies a 240 g pigeon some dis- tance below. The falcon slows to a near stop, then goes into ve-called a stoop-and picks up speed as she falls. The n reaches a vertical speed of 45 m/s before striking the pigeon, which we can assume is stationary. The falcon strikes the pigeon and grabs it in her talons. The collision between the falco birds lasts 0.015 s. a. What is the final speed of the falcon and pigeon? b. What is the average force on the pigeon during the impact?

Answers

A) 30 m/s

The problem can be solved by using the law of conservation of momentum. In fact, the total momentum falcon+pigeon before the collision must be equal to the total momentum falcon+pigeon after the collision:

p_i = p_f

m_f u_f + m_p u_p = (m_f + m_p) v

where

mf = 0.480 g is the mass of the falcon

uf = 45 m/s is the initial velocity of the falcon

mp = 0.240 g is the mass of the pigeon

up = 0 is the initial velocity of the pigeon

v is the final combined velocity of pigeon+falcon

Solving the equation for v, we find

p=(m_f u_f)/(m_f +m_p)=((0.480 kg)(45 m/s))/(0.480 kg+0.240 kg)=30 m/s

B) 480 N

The average force on the pigeon during the impact is given by

F=(\Delta p)/(\Delta t)

where

\Delta p is the change in momentum of the pigeon

\Delta t is the duration of the collision

here we have:

- Change in momentum of the pigeon:

\Delta p = m (v-u)=(0.240 kg)(30 m/s-0)=7.2 kg m/s

- Duration of the collision:

\Delta t=0.015 s

So the average force is

F=(7.2 kg m/s)/(0.015 s)=480 N

Final answer:

To determine the final speed of the falcon and pigeon, we need to use the principles of conservation of momentum. To calculate the average force on the pigeon during the impact, we can use the equation for impulse. The primary topic of this question is conservation of momentum and impulse.

Explanation:

To determine the final speed of the falcon and pigeon, we need to use the principles of conservation of momentum. Since the pigeon is assumed to be stationary, its initial momentum is zero. The final momentum of the falcon and pigeon combined must also be zero, according to the law of conservation of momentum. Using the equations for momentum and rearranging, we can solve for the final speed of both the falcon and pigeon.

To calculate the average force on the pigeon during the impact, we can use the equation for impulse, which is the change in momentum. Impulse is equal to force multiplied by the time of impact. Rearranging the equation, we can solve for force.

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