The terminal side of an angle θ in standard position passes through the point (3, 1). Calculate the exact values of the six trig functions for angle θ.

Answers

Answer 1
Answer:

Answer:

sin α = (y)/(r) = (1)/(√(10) )

cos α = (x)/(r) = (3)/(√(10) )

tan α = (y)/(x) = (1)/(3)

cot α = (x)/(y) = (3)/(1)

sec α = (r)/(x) = (√(10) )/(3)

csc α = (r)/(y) = (√(10) )/(1)

Step-by-step explanation:

If the point is given on the terminal side of an angle, then:

Calculate the distance between the point given and the origin:

r = √(x^2+y^2)

Here it is: √(3^2+1^2) = √(9+1) = √(10)

So we have:

x = 3

y = 1

r = √(10)

Now we can calculate all 6 trig, functions:

sin α = (y)/(r) = (1)/(√(10) )

cos α = (x)/(r) = (3)/(√(10) )

tan α = (y)/(x) = (1)/(3)

cot α = (x)/(y) = (3)/(1)

sec α = (r)/(x) = (√(10) )/(3)

csc α = (r)/(y) = (√(10) )/(1)

Answer 2
Answer:

Final answer:

The question involves calculating the six trigonometric functions (Sin, Cos, Tan, Csc, Sec, Cot) for an angle in standard position with its terminal side passing through point (3,1). We find opposite and adjacent sides from the point's coordinates, the hypotenuse from Pythagoras' theorem, and calculate each ratio accordingly.

Explanation:

In the context of the problem, the point (3,1) specifies the terminal side of angle θ in standard position. This point is effectively the definition of your right triangle's opposite (y) and adjacent (x) sides in the trigonometric calculation, with the hypotenuse (h) obtained from Pythagoras' Theorem (h² = y² + x²). In this case, we get h = sqrt(3² + 1²) = sqrt(10).

The six trigonometric functions are defined as follows for this scenario:

  • Sin θ = y/h = 1/sqrt(10).
  • Cos θ = x/h = 3/sqrt(10).
  • Tan θ = y/x = 1/3.
  • Csc θ = 1/sin θ = sqrt(10).
  • Sec θ = 1/cos θ = sqrt(10)/3.
  • Cot θ = 1/tan θ = 3.

Learn more about Trigonometric Functions here:

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HELLLPPP!y = -1/2x^2 + 2
y = -2x^2 + 3
y = -3/4x^2
y = -4/5x^2 - 5

For the quadratic equations shown here, which statement is true?

A) The graphs open upward.
B) The graphs open downward.
C) The graphs are symmetric about the x-axis.
D) The graphs are listed from narrowest to widest.

Answers

The correct answer is this one: "B) The graphs open downward. " Negative quadratic functions will give you a downward graph.

The equations 
y = -1/2x^2 + 2
y = -2x^2 + 3
y = -3/4x^2
y = -4/5x^2 - 5

are all negative. So they are facing downward.

Y varies directly with x, and y=16
in. when x=8 in.

Answers

Answer:

y= 2x

Step-by-step explanation:

To figure out what the equation would be you would set up an equation..

16 = 8z

Then you find z

16/8 = 8z/8

2 = z

Now you can set up a variable expression although it isn't necessary

y = zx

Now you plug in the value of z to complete the equation

y= 2x

I hope this is what you wanted!!!

A car moves at speed v across a bridge made in the shape of a circular arc of radius r. (a) Find an expression for the normal force n acting on the car when it is at the top of the arc. (Use any variable or symbol stated above along with the following as necessary: m and g.) n

Answers

Answer:

n=m(g-(v^(2))/(r))

Step-by-step explanation:

If a car is moving across a circular bridge, made in the shape of a circular arc then the force that balances the car when it is on the top of arc will be

n + F = mg

Where n = normal force acting on the car

F = centripetal force

m = mass of the car

We know centripetal force  F=(mv^(2))/(r)

where m = mass of the car

v = velocity of the car on the top of the arc

r = radius of the arc

Therefore, the expression for the normal force 'n' will be

n+(mv^(2))/(r)=mg

n=mg-(mv^(2))/(r)

n=m(g-(v^(2))/(r))

What is another way to say 345 centimeters?345 mm
345 cm
34.5 dl
345 cg

Answers

non of them are right unless u ment 3450 mm or u could say 3.45 meters

Answer:

3450 mm

Step-by-step explanation:

solve for y.try factoring first,if factoring is not possible or difficult use quadratic formula,(y2  2isabovey -10y+23=0)

Answers

y^2-10y+23=0\n y^2-10y+25-2=0\n (y-5)^2=2\n |y-5|=\sqrt2\n y-5=\sqrt 2 \vee y-5=-\sqrt2\n y=5+\sqrt2 \vee y=5-\sqrt2

One number is six times another number. Their difference is 35. What are the two numbers?

Answers

Answer:

The two numbers are: 42 and 7

Step-by-step explanation:

let x be the one number and y be the other number..

As per the statement:

One number is six times another number. Their difference is 35.

x = 6y               .....[1]

and

x -y = 35               .....[2]

Substitute equation [1] into [2] we get;

6y-y = 35

Combine like terms;

5y = 35

Divide both sides by 5 we get;

y = 7

Substitute the value of y =7 in [1] we get;

x = 6(7) = 42

Therefore, the two numbers are: 42 and 7

7x6=42. 7+35=42. The numbers are 7 and 42.