A pharmaceutical manufacturer is concerned that the impurity concentration in pills should not exceed 3%. It is known that from a particular production run impurity concentrations follow a normal distribution with a standard deviation of 0.4%. A random sample of 64 pills from a production run was checked, and the sample mean impurity concentration was found to be 3.07%. Testing at the 5% level the null hypothesis that the population mean impurity concentration is 3% against the alternative that it is more than 3%.a. Calculate the p-value for this test.
b. Find the p-value for this test and draw your conclusion.
c. Suppose that the alternative hypothesis in part b had been two-sided rather than one-sided. Conduct your test using either the critical value or the p-value approach.
Answers
The p-value for the given test is 0.0901.
Given that, a pharmaceutical manufacturer is concerned that the impurity concentration in pills should not exceed 3%.
What is a standard deviation?
Standard deviation is the degree of dispersion or the scatter of the data points relative to its mean, in descriptive statistics.
Given, Mean = 3.07, μ=3%, σ =0.4% and n=64.
Hypothesis test ;μ=3 and
;μ>3
We need to test the null hypothesis against the alternative hypothesis, we reject the null hypothesis and accept the alternative hypothesis.
When x>x critical
x critical = μ+Z+σ
Z = (x-μ)/(σ/√n)
= (3.07-3)/(0.4/√64)
= (0.07)/0.05
= 1.4
α = 5 and = 1.645
If Z>
1.4 > 1.645
Therefore, we do not reject null hypothesis at 5% significant level.
There is sufficient evidence that the mean impurity in concentration pills is 3% or less than 3%.
p-value
p−value=P(Z>1.4)
=1−P(Z<1.4)
=1−0.90988
=0.0901
Therefore, the p-value for the given test is 0.0901.
To learn more about the standard deviation visit:
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c
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Marl me as brainliest answer c
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