MATHEMATICS HIGH SCHOOL

7. A cargo train covers 375 km in 15 hours. Find: b) time taken to travel 770 km.

Answers

Answer 1

Answer:

Answer:

30 hours 48 minutes

Step-by-step explanation:

Using the relationship

average speed = $(distance)/(time)$ = $(375)/(15)$ = 25 Km / hour

Then

time = $(distance)/(speed)$ = $(770)/(25)$ = 30.8 hours = 30 hours 48 minutes

Answer 2

Answer:

Answer:

30.8 or 30 hours and 48 mins

Step-by-step explanation:

375 km > 15 Hours

Divide 375 and 15, equals to 25.

So, to proof that 375 is equals to 15 hours, divide 375 and 25 then you will get the answer 15. :)

Now, divide 770 and 25 to get the time taken to travel 770km.

And the answer is 30.8 hrs or... 30hrs and 48mins

Welcome ;)

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Order the following from least to greatest.

Answers

Answer:

Hi there!

Your answer is:

-26/5 , -5.17 , √33 , 37/6

Step-by-step explanation:

-26/5 = -5.2

-5.17 = -5.17

✓33= 5.7

37/6 = 6.16

you and your mom enter a drawing with 3 different prizes. a total of 10 people entered the drawing, and prizes are awarded randomly. there are 720 ways to award the prizes

Answers

Answer:

The correct option is A.

Step-by-step explanation:

Number of people who entered the drawing = 10

Number of prizes = 3

Number of ways to award the prize = 720 ways

The total number of ways that 3 prizes can be awarded to the 10 people can be determined as:

10*9*8 = 720

The total number of ways in which I win the first prize and my mom wins the second prize would be 1*1*8 = 8

Thus the probability that i win the first prize and my mom wins the second prize would be 8/720 ....

Can somebody solve using elimination method algebra2

Answers

For the first one, you just add them and you obtain an equation in y. Solve for y, then substitute y for the solution in either of the equations, then solve for x.
In the second one, multiply the first by -2, then do the addition and something similar to the first one.

Which expression is equivalent to 7a2b + 10a2b2 + 14a2b3?

Answers

The given expression can be simplified in many ways by grouping like terms. The simplest form is obtained by factoring out a²b which gives us the following expression.

a²b(7 + 10b +14b²)

Answer:

a²b(7 + 10b +14b²)

Step-by-step explanation:

$7a^2b + 10a^2b^2 + 14a^2b^3$

To find out equivalent expression we need to factor the given expression

To factor it first we find out GCF(greatest common factor)

7 a^2b -------> 7*a*a*b

10a^2b^2 ----->5*2 * a*a*b*b

14a^2b^3 -------> 7*2 *a*a*b*b*b

To get GCF we look at the factors that are in common

GCF = a*a*b that is a^2b

We factor out GCF a^2b, write a^2b outside and divide all the terms by a^2b

$a^2b(7 +10b +14b^2)$

7+10b+14b^2 cannot be factor . its prime

2/7m-1/7=3/14 help this is so confusing

Answers

Solution for $(2)/(7)m - (1)/(7) = (3)/(14) \ is \ m = (5)/(4) \ or \ m = 1(1)/(4) \ or \ m = 1.25$

Further explanation

A case about one variable linear quations. We have to solve the equation to get the variable m. Let's isolate the variable m alone at the end of the process on one side of the equation, until the variable will be equal to a value on the opposite side.

We add $(1)/(7)$ to both sides:

$(2)/(7)m - (1)/(7) + (1)/(7) = (3)/(14) + (1)/(7)$

$(2)/(7)m = (3)/(14) + (1)/(7)$

On the right side for the addition operation, we equate the common denominator by multiplying $\ (1)/(7) \ by \ (2)/(2)$

$(2)/(7)m = (3)/(14) + (2)/(14)$

Then we combine terms to get:

$(2)/(7)m = (5)/(14)$

We divide by the coefficient of m, or in other words, multiply both sides by $(7)/(2)$ :

$(2)/(7)m * (7)/(2) = (5)/(14) * (7)/(2)$

Finally, the solution is obtained as follows

$m = (35)/(28)$

We simplify fractions, both the numerator and denominator are divided equally by 7.

$\boxed{ \ m = (5)/(4) \ }$

In the form of mixed fractions, we get:

$\boxed{ \ m = 1 (1)/(4) \ }$

In decimal form, we get

$m = 1 (25)/(100) \rightarrow \boxed{ \ m = 1.25 \ }$

Check the solution into the equation:

$\big( (2)/(7) * (5)/(4) \big) - (1)/(7) = (3)/(14)$

$(10)/(28) - (1)/(7) = (3)/(14)$

$(5)/(14) - (2)/(14) = (3)/(14)$

$(3)/(14) = (3)/(14)$

Both sides show the same value, so the solution is correct.

Quick steps in summary:

$(2)/(7)m - (1)/(7) = (3)/(14)$

$(2)/(7)m = (3)/(14) + (1)/(7)$

$(2)/(7)m = (3)/(14) + (2)/(14)$

$(2)/(7)m = (5)/(14)$

$m = (5)/(14) * (7)/(2)$

$m = (35)/(28)$

$\rightarrow \boxed{ \ m = (5)/(4) \ }$

$\rightarrow \boxed{ \ m = 1 (1)/(4) \ }$

$\rightarrow \boxed{ \ m = 1.25 \ }$

Note:

The important thing to do is how to manipulate both sides of the equation with the algebraic properties of equality such as:

adding,
subtracting,
multiplying, and/or
dividing both sides of the equation with the same number.

All these processes can occur repeatedly until the isolated variables are obtained on one side of the equation. In the form of fractions, the steps that must be considered are

equate the denominator,
simplify fractions, and
turn fractions into mixed fractions or decimal forms.

Let's practice a lot until you get used to and know which operations should be done first.

Learn more

A word problem that forms a single variable linear equation brainly.com/question/1566971
Learn more about single variable linear equation that has no solution, has one solution, and has infinitely many solutions brainly.com/question/2595790
Questioning the stages of solving a word problem about one variable linear equations brainly.com/question/2038876

Answer details

Grade : Middle School

Subject : Mathematics

Chapter : Linear Equation in One Variable

Keywords : solve, solution, variable, coefficient, 2/7m - 1/7 = 3/14, 5/4, 1 1/4, 1.125, algebraic properties of equality, one, linear equation, isolated, manipulate, operations, add, substract, multiply, divide, fraction, equate, denominator, numerator, both sides, decimal, brainly

Tom conducted a drawing competition at school. He bought 5 boxes of colored pencils and spent $5.25 on drawing paper. However, more contestants entered than he expected, and he had to buy 2 more boxes of colored pencils. The total cost of the paper and pencils was $82.95. Identify the equation and solution that would help to find the cost of each box of pencils.