MATHEMATICS HIGH SCHOOL

What is -a^-2 if a=-5

Answers

Answer 1

Answer:

Answer:

the answer is 25

Step-by-step explanation:

cause -5 times -5 is 25 cause negative times negative is positive, and 5 times 5 is 25.

Answer 2

Answer: Well, -2 times -2 is 4 and 4 times -2 is -8 times -2 is 16 and 16 times -2 is -32 and -32 times -2 is 64 and -64 times -2 is 128

So 128

Related Questions

The graph of the following system of equations is (4 points)-2x + y = 34x + 2y = 2a. overlapping linesb. parallel linesc. intersecting lines
Evaluate the following:Options are:-12/(5)012/(5)The integral diverges.
Line is defined by the equation 2 x + y = 4. Which shows the graph of this line?
8;18;30;44;.... calculate the nth term of the sequence
Solve for x: 2x + 4 ≤ 12

The numbers of bees that visit a plant is 500 times the number of years the plant is alive, where t represents the number of years the plant is alive . what does the expression 500t represent

Answers

For this case, the first thing we must do is define variables.

We have then:

t: the number of years the plant is alive

f (t): the numbers of bees that visit the plant

The equation modeling the problem is given by:

Answer:

the expression 500t represent:

the numbers of bees that visit the plant

500t represents the number of bees that visit the plant.

Doug earns $10.50 per hour working at a restaurant. On Friday he spent 1 & 3/4 hours cleaning, 2 & 1/3 hours doing
paperwork, and 1 & 5/12 hours serving customers. What were
Doug’s earnings?

Answers

First, add all of the working hours.
1 $(3)/(4)$ + 2 $(1)/(3)$ + 1 $(5)/(12)$

Since the denominators are different, make them all the same.
1 $(9)/(12)$ + 2 $(4)/(12)$ + 1 $(5)/(12)$

Add everything together.
4 $(1)/(12)$ + 1 $(5)/(12)$ = 5 $(6)/(12)$

Then, simplify.
5 $(1)/(2)$ or 5.5

Multiply the time by the salary.
5.5*10.5= Doug earned $57.75

1. what is the GCF of the terms of 8c^3+12c^2+10c? A.2
B.4
C.2c
D.4c

2. How can the polynomial 6d^4+9d^3-12d^2 be factored l?

Answers

Answer:

1. C. 2c

2. $3d^2(2d^2+3d-4)$

Step-by-step explanation:

A. We have been given an expression and we are asked to find the GCF of our given expression.

$8c^3+12c^2+10c$

Let us find factors of each of our given terms.

Factors of $c^3$ are $c*c*c$ ,

Factors of $c^2$ are $c*c$ ,

We can see that c is the greatest common factor of $c^3$ , $c^2$ and $c$ .

Factors of 8 are: 1, 2, 4, 8.

Factors of 12 are: 1, 2, 3, 4, 6, 12.

Factors of 10 are: 1, 2, 5, 10.

The greatest common factor of 8,12 and 10 is 2.

So let us factor out 2c from our expression.

$2c(4c^2+6c+5)$

Therefore, the greatest common factor of our given expression is 2c and option C is the correct choice.

2. We have been given a polynomial and we are asked to factor our given polynomial.

$6d^4+9d^3-12d^2$

We will pull out the greatest common factor of the terms of our given polynomial.

We can see that GCF of $d^4$ , $d^3$ and $d^2$ is $d^2$ .

The GCF of 6, 9 and 12 is 3.

So let us factor out $3d^2$ from our polynomial.

$3d^2(2d^2+3d-4)$

Therefore, the factored form of our given polynomial is $3d^2(2d^2+3d-4)$ .

If you pay attention 2 goes into 8, 10, & 12 and it looks like they all have one C. So what do you think it is lol?(:

The base of a solid in the xy-plane is a circle with a radius of 3. cross sections of the solid perpendicular to the x-axis are squares. set up the integral to arrive at the volume of the solid and solve.

Answers

Answer:

$\large \boxed{144}$

Step-by-step explanation:

1. Set up the integral.

The equation for the circle is

x² + y² = 9

The bottom corners of the square are at

$(x, \sqrt{9 - x^(2)})\text{ and } (x, -\sqrt{9 - x^(2)})$

The length (a) of a side is

$a = 2\sqrt{9 - x^(2)}$

and the area (A) of the square cross-section is

A = a² = 4(9 - x²)

The volume (V) of the solid is

$V = \displaystyle \int_(-3)^(3) {4(9 - x^(2))} dx$

2. Solve the integral

$\displaystyle \int_(-3)^(3) {4(9 - x^(2))} dx = 4\begin{bmatrix}9x - (1)/(3)x^(3)\end{bmatrix}_(-3)^(3)= 4[(27 - 9) - (-27 +9)] = 4[18 - (-18)]\n= 4[18 + 18] = 4 *36 = \mathbf{144}\n\n\text{The volume of the solid is $\large \boxed{\mathbf{144}}$}$