A line intersects the points(4, 3) and (6,9).
What is the slope of the line in
simplest form?
m = [?]

Answers

Answer 1
Answer: Slope = 9-3 / 6-4
= 6/2
= 3

Your answer is m = 3
Answer 2
Answer:

Answer:

6 / 2   or   3

Step-by-step explanation:

y2 - y1

_____      =     (9 - 3) / (6 - 4) = 6 / 2 = 3

x2 - x1


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HELP ITS DUE IN 15 mins!!!!! and i need help:(

How do you show work for 604.8 divided by 36

Answers

By multiplying the two numbers when u multiply pretend like the decimals are not there then when u are done the answer has to match the divisor hope it helped

System of equations PROBLEM/QUESTION:
A school band ordered hats for $3 and large T-shirts for $5. They bought 150 items in all for $590. Graph a system of equations to find how many hats and T-shirts the band ordered.

**PLEASE HELP I DONT UNDERSTAND SYSTEM OF EQUATIONS

Answers

The number of hats ordered is; 80 and the number of shirts ordered is; 70.

What is a system of equations?

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Given that  the Cost of hats = $3

The Cost of shirts = $5

The total cost of all the items = $590.

Total number of items bought = 150 items.

Let us assume that the number of hats ordered be x.

The number of shirts ordered be y

The equation can formed as;

x+y = 150  -------(1)

3x+5y = 590  ---------(2)

Multiply and subtract eq(2) from eq(1),

3x+3y = 450

-(3x+5y = 590)

    -2y = - 140

y = 140/2

y = 70.

Thus, the number of shirts ordered is; 70.

Now Substitute y=70 in eq(1),

x+70 = 150

x = 150-70

x = 80.

Thus, the number of hats ordered is; 80.

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You would make a system of equations, so the first would be "x+y=150" (x is the number of hats and y is the number of shirts). The second equation would be "3x+5y=590". You would solve the system by either substitution, elimination, or graphing it. 
   If you do it by substitution, you would solve one equation for either variable (the first equation would be easier to solve for either variable) and plug it into the other equation and solve it. So it would look like:  y=150-x      3x+5(150-x)=590    
   If you did it by elimination, you would line the variables in the equations up and make one variable (We'll use x) the opposite of the same variable in the other equation and add the equations together to make the chosen variable cancel out so you could solve for the other variable. So it would look like:   3x+5y=590
                                                                                           + -5x- 5y=-150
                                                                                         -----------------
                                                                                            -2x=440
                                                                                              x=-220
After you do that, you would plug that answer into one of the original equations and solve for the other variable. So it would look like:   -220+y=150
                                                                                     y=370
   If you did it by graphing you would simply graph both equations on the same graph and the point that they intersect at would be your answer.

Twice a number increased by 5?? in algebraic expression

Answers

To write this as an algebraic expression, remember that twice a number means that 2 is being multiplied by a number. Since we are not solving, we can just use the variable n to represent the number that is being multiplied by 2. Finally, adding 5 to the number we will get the expression 2n + 5.

2x+5 would be the equation

x is the "number" that is unknown, it's what's called a variable. Because you need two times a number(x) you put a coefficient of 2 in front of it, then simply add 5.

Examples with known variable values:
2(4)+5=13
2(2)+5=9

Find 4 consecutive odd integers whose sum is 232

Answers

4 consecutive odd integers whose sum is 232 are : 55, 57, 59, 61

How to find the sum of consecutive integers?

1 + 2 + 3 + ... + n = (n(n+1))/(2)

Let the first integer be x and x is an odd number.

Let Four consecutive odd integers are;

x, x + 2, x + 4, x + 6

(x) + (x + 2) + (x + 4) + (x + 6) = 232

4x + 12 = 232

4x = 232 - 12

4x = 220

x = 220/4

x = 55

x + 2 = 55 + 2 = 57

x + 4 = 55 + 4 = 59

x + 6 = 55 + 6 = 61

The numbers are : 55, 57, 59, 61

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 4 consecutive odd integers...
x, x + 2, x + 4, x + 6

(x) + (x + 2) + (x + 4) + (x + 6) = 232
4x + 12 = 232
4x = 232 - 12
4x = 220
x = 220/4
x = 55

x + 2 = 55 + 2 = 57
x + 4 = 55 + 4 = 59
x + 6 = 55 + 6 = 61

so ur numbers are : 55, 57, 59, 61

An animal shelter spends $1.50 per day to care for each bird and $8.50 per day to care for each cat. Alexander noticed that the shelter spent $108.00 caring for birds and cats on Tuesday. Alexander found a record showing that there were a total of 30 birds and cats on Tuesday. How many birds were at the shelter on Tuesday?

Answers

Answer:

21 birds.

Step-by-step explanation:

Let B represent the number of birds and C represent the number of cats.

We have been given that an animal shelter spends $1.50 per day to care for each bird, so the amount spent on B birds will be 1.50B.

The animal shelter spends $8.50 per day to care for each cat, so the amount spent on C cats will be 8.50C.

Alexander noticed that the shelter spent $108.00 caring for birds and cats on Tuesday. We can represent this information in an equation as:

1.50B+8.50C=108...(1)

Alexander found a record showing that there were a total of 30 birds and cats on Tuesday. We can represent this information in an equation as:

B+C=30...(2)

We will use substitution method to solve system of linear equations.

From equation (2) we will get,

C=30-B

Substituting this value in equation (1) we will get,

1.50B+8.50(30-B)=108

1.50B+255-8.50B=108

255-7B=108

Let us subtract 255 from both sides of our equation.

255-255+7C=108-255

-7B=-147

Let us divide both sides of our equation by -7.

(-7B)/(-7)=(-147)/(-7)

B=21

Therefore, there were 21 birds at the shelter on Tuesday.

Please show me how to do it.

Answers

(8^(2n - 3) * 2^(n - 3))/(4 * 2^(-n + 2)) = (2^(3(2n - 3)) * 2^(n - 3))/(4 * 2^(-n + 2)) = (2^(3(2n) - 3(3)) * 2^(n - 3))/(4 * 2^(-n + 2)) = (2^(6n - 9) * 2^(n - 3))/(2^(2) * 2^(-n + 2)) = (2^((6n - 9) + (n + 3)))/(2^(2 - n + 2)) = (2^((6n + n) + (-9 + 3)))/(2^(-n + 2 + 2)) = (2^(7x + (-12)))/(2^(-n + 4)) = (2^(7x - 12))/(2^(-n + 4)) = 2^(8n - 16)