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prove triangle PAB is an equilateral triangle

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Answers

Answer 1

Answer:

Answer:

If three sides of a triangle are equal and the measure of all three angles is equal to 60 degrees then the triangle is an equilateral triangle. Therefore it is an equilateral triangle.

Answer 2

Answer:

In ∆PAM and ∆PBM

$\because\pink{\sf\begin{cases} \sf AM=BM(Bisected\:by\:PM)\n \sf PA=PB(Given)\n \sf PM(Common\:side)\end{cases}}$

$\n \sf\longmapsto ∆PAM\cong ∆PBM(SSS)$

$\n \sf\longmapsto PA+AM=PB+BM$

Put AM =BM

$\n \sf\longmapsto PA+AM+AM=PB+BM+BM$

Put PA=PB

$\n \sf\longmapsto PA+AB=PB+AB$

Hence

∆APB is a equilateral triangle

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Answers

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Step-by-step explanation:

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Answers

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Answers

Answer:

Step-by-step explanation:

Answer:
GCF = 18
Explanation:

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Answers

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