You have to prepare some 2 M solutions, with 10 g of solute in each. What volume of solution will you prepare, for each solute below? (Ar:H51,Li57,N514,O516,Mg524,S532.)a lithium sulfate, Li2SO4

Final answer:

HCl is the most polar bond, as greater the difference in electronegativity, the more polar the bond. Here, Chlorine is more electronegative than Hydrogen, Bromine, and Iodine, making the HCl bond most polar.

Explanation:

The most polar bond in the list provided is HCl. Polarity in bonds is determined by the difference in electronegativity between the two atoms in the bond. The greater the electronegativity difference, the more polar the bond. Chlorine (Cl) is more electronegative than Hydrogen (H), Bromine (Br), and Iodine (I), and so the bond between Cl and H is the most polar. The other three options (Cl2, HBr, HI) are either bonds between atoms of the same element (and therefore nonpolar because the electrons are shared equally) or are less polar due to the lower electronegativity difference.

Learn more about Polarity of Bonds here:

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MC₂H₄O₂ = 2 * 12 g/mol + 4 * 1 g/mol + 2 * 16 g/mol = 60 g/mol

c = 0.5 mol/L

V = 1 L

n = c * V

n = 0.5 mol/L * 1 L = 0.5 mol

m = n * M

m = 0.5 mol * 60 g/mol = 30 g/mol

answer E

(-_-(-_-)-_-)

Answer:

It's true I got it wrong.

Explanation:

Answer : The incorrect option is, Condensation occurs at .

Explanation :

Absolute zero on Kelvin scale is .

This statement is correct because at the temperature in degree Celsius will be,

Liquefaction of the gas occurs at approximately .

This statement is correct. From the given graph the liquification of gas occurs at .

The gas follows a linear relationship between volume and temperature.

This statement is correct. According to the Charles law, the volume of gas is directly proportional to the temperature of the gas. So, gas follow the linear relationship between the volume and temperature.

Condensation occurs at .

This statement is incorrect because condensation occurs at . and the condensation is a process in which the phase changes from the gaseous state to liquid state at constant temperature.

As we know that condensation is a reverse process of vaporization. Both the process occurs at constant temperature .

Hence, the incorrect option is, Condensation occurs at .

Answer:

Explanation:

Pb(NO3)2 (aq) + 2 NaI (aq) --> PbI2 (s) + 2 NaNO3 (aq)

MM for each compound -

Pb(NO3): 207 + 14x2 + 16x3x2 = 331

PI2: 207 + 127x2 = 461

NaI: 23 + 127 = 150

NaNO3: 23 + 14 + 16x3 = 85

Moles of Pb(NO3)2 = 50/331 = 0.15

Moles of NaI = 30/150 = 0.2

Ratio of moles is 1:2

So NaI is limiting

Limited to 0.2/2 = 0.1 mole of Pb(NO3)2

Excess = 0.15 - 0.1 = 0.05 mole

Mass remains = 0.05x331 = 16.55 grams

Moles of NaNO3 formed = Moles of NaI reacted = 0.2

Mass = 0.2x85 = 17 grams

Moles of PbI2 formed = Moles of Pb(NO3)2 reacted = 0.1

Mass = 0.1x461 = 46.1 grams

If 12 grams of NaNO3 actually formed in the reaction,

percent yield = 12/17x100% = 70.6%

Answer:

Explanation:

Moles of Pb(NO3)2 =  mass/molecular mass

= 50.0 grams/(207.20*1 + 14.01*2 + 16*6)

= 50.0 grams/331.22

= 0.15 moles

Moles of NaI

= 30/(22.99+126.9)

= 30/149.89

= 0.2 Moles

A. NaI is less 2x Pb(NO3)2 so NaI is the limiting reagent.

B. The ratio is 1 to 2 so there is 0.15 - 0.2/2 = 0.05 mole

or 16.78 grams of Pb(NO3)2 left.

C. As NaI is limiting, only 0.2 Moles of NaNO3 is formed.

Mass =  Moles * Molecular Mass

Molecular Mass of NaNO3 can be calculated as:  

Na - 22.99

N - 14.01

O - 3(16) = 48

23+14+48 = 85gram / mole

Thus, Mass =  0.2*85  = 17 gram of NaNO3

Mass is conserved in a chemical reaction.

Mass of PbI2 can be calculated as:

50+30-16.78-17

= 46.3 gram of PbI2

Mass =  

12.75

Thus, 12.75g of Sodium Nitrate can be formed