4. A 1500 kg car is rolling at 2.0 m/s. You would like to stop the car by firing a 10 kg blob ofsticky clay at it. How fast should you fire the clay?
Answers
The clay must be 300 m/s fast in other to stop the car.
For the car to stop, The momentum of the car must be equal to the momentum of the clay.
Formula:
- MV = mv................. Equation 1
Where:
- M = mass of the car
- V = Velocity of the car
- m = mass of the clay
- v = velocity of the clay
Make v the subject of the equation.
- v = MV/m................... Equation 2
From the question,
Given:
- M = 1500 kg
- V = 2 m/s
- m = 10 kg
Substitute these values into equation 2
- v = 1500(2)/10
- v = 300 m/s.
Hence, The clay must be 300 m/s fast in other to stop the car.
Learn more about momentum here: brainly.com/question/7973509
Final answer:
To stop the car rolling at 2.0 m/s with a blob of clay, you should fire the blob of clay at a speed of 300 m/s. This is based on the principle of conservation of momentum.
Explanation:
The question involves a principle of Physics called the law of conservation of momentum. The law states that the total momentum of a system remains constant if no external forces act on it. Here, the car and the clay are the two objects in the system.
At the start, only the car has momentum, which can be calculated with the equation: momentum = mass x velocity => momentum of car = 1500 kg x 2 m/s = 3000 kg m/s.
After the clay is fired at the car, the total momentum of the system (car + clay) still remains 3000 kg m/s, but now the momentum is shared between them. We want to stop the car, so it will now have no momentum, meaning all momentum must be with the clay.
The equation again turns to momentum = mass x velocity => velocity = momentum/mass => velocity of clay = 3000 kg m/s / 10 kg = 300 m/s.
You should fire the clay at 300 m/s to stop the car.
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Answers
Answer:
8.57 m/s
Explanation:
let's list out available parameters:
Initial velocity, u = 20 m/s
Time = 15 - 1 = 14 s
Distance, s = 200 m
Final velocity = ?
We are assuming a uniformly accelerated motion.
Using one of the equations of motion
m/s
Final answer:
To stop just as the light turns green, the motorist needs to decelerate in a controlled manner. The effective time to cover the distance after seeing the red light is 14 seconds, disregarding the 1 second it takes to react and press the brakes. Therefore, as she reaches the traffic signal when it turns green, her speed is 0 m/s.
Explanation:
This situation can be approached using the concept of kinematics in Physics. To solve it, we need to consider total time and total distance traveled. The motorist is driving towards the traffic light, which is 200m away, and the light stays green for 15 seconds. However, since it takes her 1 second to step on the brakes, effectively, she has 14 seconds to travel to the light.
Since she starts braking the car, she begins to decelerate. While decelerating, time is the only determinant of the distance covered, not the speed. As she reaches the light, the speed would be zero regardless of the initial speed or distance if the deceleration is constant. So, when the light turns green, her speed will be 0 m/s.
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b. False
Answers
Answers
b) 1V
c) 0.25V
d) 4V
e) 2V
Answers
Answer:
The electrical potential of the two electrons is 1 V.
(b) is correct option.
Explanation:
Given that.
Electric potential = 1 V
We know that,
The electric potential depends on the distance.
The electric potential does not depend on the charge.
The formula of electric potential
Where, E = electric field
d = distance
Hence, The electrical potential of the two electrons is 1 V.
B) liquid phase
C) solid, liquid and gas phases
D) no phases are present at this point
Answers
Answer:
The answer is C) solid, liquid and gas phases
Explanation:
This point is called the triple point bc solid, liquid, and gas phases can exist together.
hope this helps :)
B. diodes.
C. electrons.
D. neutrons.
Answers
THE ANSWER IS *ELECTRONS* I toojk the pen foster exam! <3 hope this helps