PLEASE HELP I MISSED A WHOLE WEEK AND IM SO CONFUSED WHAT THIS IS

Answers

Answer 1

Answer: The value of x is given by the pythagoras theorem
X^2 = 17^2 - 15^2
X^2 = 289-225
X^2 = 64
X = sqrt64
X= 8cm

Related Questions

What is the sum of two solutions of the quadratic equation ax^2+bx+c=0
Sarina has some ribbon. After she used 24.7 cm of it, she had 50 cm left. How much ribbon did Sarita start with?
between which two numbers is the whole number qoutient of 88 divided by 5 write the numbers in the boxes (the number choices: 5, 10, 15, 20, 25)
A restaurant in a fast food franchise has determined that the chance a customer will order a soft drink is 0.88. The probability that a customer will order a hamburger is 0.53. The probability that a customer will order french fries is 0.49. Complete parts a and b below.a. If a customer places an order, what is the probability that the order will include a soft drink and no fries, if these two events are independent? (Round to four decimal places as needed.) The probability is____________. b. The restaurant has also determined that, if a customer orders a hamburger, the probability the customer will order fries is 0.71.Determine the probability that the order will include a hamburger and fries. (Round to four decimal places as needed.) The probability is________
Consider the following 8 numbers, where one labelled x is unknown. 26, 33, 46, x , 9, 7, 10, 11 Given that the range of the numbers is 60, work out 2 values of x .

ComeQuestion 14
8.0 x105 +6.0 x107 =
A
14,000,000,000,000
B
140,000,000
с
60,800,000
D
68,000,000

Answers

Answer:

с 60,800,000

Step-by-step explanation:

Any scientific or graphing calculator can evaluate this expression for you.

When adding numbers in scientific notation, they need to have the same multiplier exponent. Here, it is convenient to use 10^6:

8.0×10^5 = 0.8×10^6

6.0×10^7 = 60×10^6

Then the sum is ...

(0.8 +60)×10^6 = 60.8×10^6 = 60,800,000

Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]

Answers

Answer:

The answer is " $\bold{\left[\begin{array}{cc}a&b\nc&d\end{array}\right] = \left[\begin{array}{cc}7&-2\n -(1)/(2)&(7)/(2)\end{array}\right]}$ ".

Step-by-step explanation:

$\bold{\left[\begin{array}{cc}1&2\n3&4\end{array}\right] \left[\begin{array}{cc}a&b\nc&d\end{array}\right] = \left[\begin{array}{cc}6&5\n 19&8\end{array}\right]}$

Solve the L.H.S part:

$\left[\begin{array}{cc}1&2\n3&4\end{array}\right] \left[\begin{array}{cc}a&b\nc&d\end{array}\right]\n\n\n\left[\begin{array}{cc}a+2c&b+2d\n3a+4c&3b+4d\end{array}\right]$

After calculating the L.H.S part compare the value with R.H.S:

$\left[\begin{array}{cc}a+2c&b+2d\n3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\n 19&8\end{array}\right]} \n\n$

$\to a+2c =6....(i)\n\n\to b+2d =5....(ii)\n\n\to 3a+4c =19....(iii)\n\n\to 3b+4d = 8 ....(iv)\n\n$

In equation (i) multiply by 3 and subtract by equation (iii):

$\to 3a+6c=18\n\to 3a+4c=19\n\n\text{subtract}... \n\n\to 2c = -1\n\n\to c= - (1)/(2)$

put the value of c in equation (i):

$\to a+ 2 (- (1)/(2))=6\n\n\to a- 2 * (1)/(2)=6\n\n\to a- 1=6\n\n\to a =6 +1\n\n\to a = 7\n$

In equation (ii) multiply by 3 then subtract by equation (iv):

$\to 3b+6d=15\n\to 3b+4d=8\n\n\text{subtract...}\n\n\to 2d = 7\n\n\to d= (7)/(2)\n$

put the value of d in equation (iv):

$\to 3b+4 ((7)/(2))=8\n\n\to 3b+4 * (7)/(2)=8\n\n\to 3b+14=8\n\n\to 3b =8-14\n\n\to 3b = -6\n\n\to b= (-6)/(3)\n\n\to b= -2$

The final answer is " $\bold{\left[\begin{array}{cc}a&b\nc&d\end{array}\right] = \left[\begin{array}{cc}7&-2\n -(1)/(2)&(7)/(2)\end{array}\right]}$ ".

Identify the recursive formula for the sequence 900, 850, 800, 750,…

Answers

The recursive formula for the given sequence as required in the task content is; f(n) = f (n - 1) - 50.

What is the recursive formula for the given sequence?

It follows from the task content that the recursive formula for the given sequence is to be determined.

By observation, the sequence is an arithmetic progression and the common difference, d can be evaluated as;

d = 750 - 800 = 800 - 850 = 850 - 900 = -50

Also, since the recursive formula for an arithmetic sequence takes the form;

f(n) = f (n - 1) + d.

Hence, since the recursive formula as required is;

f(n) = f (n - 1) - 50.

Answers

Answer:

The probability that he or she is high-risk is 0.50

Step-by-step explanation:

P(Low risk) = 40% = 0.40

P( Moderate risk) = 40% = 0.40

P(High risk) = 20% = 0.20

P(At - fault accident | Low risk) = 0% = 0

P(At-fault accident | Moderate risk) = 10% = 0.10

P(At-fault accident | High risk) = 20% = 0.20

If a driver has an at-fault accident in the next year, what is the probability that he or she is high-risk. Hence, We need to calculate P( High risk | at-fault accident) = ?

Using Bayes' conditional probability theorem

P( High risk | at-fault accident) = ( P( High risk) * P(At-fault accident | High risk) ) / { P( Low risk) * P(At-fault accident | Low risk) +P( Moderate risk) * P(At-fault accident | Moderate risk) + P( High risk) * P(At-fault accident | High risk) }

P( High risk | at-fault accident)= (0.20 * 0.20) / ( 0.40 * 0 + 0.40 * 0.10 + 0.20 * 0.20 )

P( High risk | at-fault accident) = 0.04 / 0 + 0.04 + 0.04

P( High risk | at-fault accident) = 0.04 / 0.08

P( High risk | at-fault accident) = 0.50.

Final answer:

The probability that a driver is high-risk given that they had an at-fault accident can be found using Bayes' theorem. Given the probabilities provided in the question, the probability is approximately 0.3333 or 33.33%.

Explanation:

To find the probability that a driver is high-risk given that they had an at-fault accident, we can use Bayes' theorem. Let's define the events:

A: Driver is high-risk
B: Driver has an at-fault accident

We are given the following probabilities:

P(A) = 0.20 (probability of a driver being high-risk)
P(B|A) = 0.20 (probability of an at-fault accident given that they are high-risk)
P(~A) = 0.80 (probability of a driver not being high-risk)
P(B|~A) = 0.10 (probability of an at-fault accident given that they are not high-risk)

Using Bayes' theorem, the probability of a driver being high-risk given that they had an at-fault accident is:

P(A|B) = (P(A) * P(B|A)) / (P(A) * P(B|A) + P(~A) * P(B|~A))

Substituting the given probabilities:

P(A|B) = (0.20 * 0.20) / (0.20 * 0.20 + 0.80 * 0.10) = 0.04 / (0.04 + 0.08) = 0.04 / 0.12 = 0.3333.

Therefore, the probability that a driver is high-risk given that they had an at-fault accident in the next year is approximately 0.3333 or 33.33%.

Learn more about probability here:

brainly.com/question/32117953

#SPJ3

Which expression is equivalent to 10q^5w^7/2w^3•4(q^6)^2/w^-5

Answers

The expression is equivalent to 20q^17w^19.

What is an expression?

Expression in mathematics is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

We are given that;

10q^5w^7/2w^3•4(q^6)^2/w^-5

Now,

To simplify the expression, we can use the following rules of exponents:

To multiply two powers with the same base, add their exponents

$(10q^5w^7)/(2w^3) * (4(q^6)^2)/(w^(-5))$$$$= (10q^5w^7)/(2w^3) * (4q^(12))/((1)/(w^5))$$$$= (10q^5w^7)/(2w^3) * (4q^(12)w^5)/(1)$$$$= (10 * 4 q^5 q^(12) w^7 w^5)/(2 w^3)$$$$= (40 q^(17) w^(12))/(2 w^3)$$$$= 20 q^(17) w^(9)$