XYZW is a parallelogram with diagonals and that intersects at point A if YA=2t WA=3t-4 and XZ=5t find XA​

Answers

Answer 1
Answer:

Answer:

  • XA = 10 units

Step-by-step explanation:

Given parallelogram XYZW with:

  • XZ and YW intersect at point A.
  • YA = 2t
  • WA = 3t - 4
  • XZ = 5t
  • XA = ?

First, the diagonals bisect each- other:

  • YA = WA

Substitute values and solve for t:

  • 2t = 3t - 4
  • 3t - 2t = 4
  • t = 4

Find the diagonal XZ:

  • XZ = 5t = 5*4 = 20

Find the length of XA:

  • XA = XZ / 2 = 20 / 2 = 10
Answer 2
Answer:

As Diagonals bisect each other in parallelogram

  • YA=WA
  • 2t=3t-4
  • 3t-2t=4
  • t=4

Diagonal XZ

  • 5t
  • 5(4)
  • 20

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Is this one correct?​

Answers

Answer:

do you expect me to flip sideways just to help you cheat on ur homework

Step-by-step explanation:

It’s f .................

Select the correct answer.A _______ is an inequality of the form where , , and are real numbers and , or any similar form with <, > , or > .

A. funtional

B. linear

C. radical

D. quadratic

Answers

I think the answer is D. Quadratic. It is common. I have heard it before and is more common than the other answers. Hope it is right!

Helen is building a rectangular garden in her backyard and she wants to have a fence around it.The perimeter of her garden is 20 yards. She is buying wood fence panels that cost $2 per foot. How many feet of fence panels does she need

Answers

Based on the calculations, Helen needs to buy 60 feet of fence panels for her rectangular garden in the backyard

How many feet of fence panels does she need

From the question, we have the following parameters that can be used in our computation:

  • The perimeter of her garden is 20 yards.
  • She is buying wood fence panels that cost $2 per foot

This means that

Perimeter = 20 yards

By metrric unit of conversion, we have

1 yard = 3 feet

So, we have

Perimeter = 20 * 3 feet

Evaluate

Perimeter = 60 feet

Hence, she needs to buy 60 feet of fence panels

Read more about perimeter at

brainly.com/question/19819849

#SPJ1

There were 5,317 previously owned homes sold in a western city in the year 2000. The distribution of the sales prices of these homes was strongly right-skewed, with a mean of $206,274 and a standard deviation of $37,881. If all possible simple random samples of size 100 are drawn from this population and the mean is computed for each of these samples, which of the following describes the sampling distribution of the sample mean? (A) Approximately normal with mean $206,274 and standard deviation $3,788
(B) Approximately normal with mean $206,274 and standard deviation $37,881
(C) Approximately normal with mean $206,274 and standard deviation $520
(D) Strongly right-skewed with mean $206,274 and standard deviation $3,788
(E) Strongly right-skewed with mean $206,274 and standard deviation $37,881

Answers

Approximately normal with mean is $206,274 and standard deviation is $3,788 and this can be determined by applying the central limit theorem.

Given :

  • There were 5,317 previously owned homes sold in a western city in the year 2000.
  • The distribution of the sales prices of these homes was strongly right-skewed, with a mean of $206,274 and a standard deviation of $37,881.
  • Simple random samples of size 100.

According to the central limit theorem the approximately normal mean is $206274.

Now, to determine the approximately normal standard deviation, use the below formula:

s =(\sigma )/(√(n) )   ---- (1)

where 's' is the approximately normal standard deviation, 'n' is the sample size, and \sigma is the standard deviation.

Now, put the known values in the equation (1).

s = (37881)/(√(100) )

s = 3788.1

\rm s \approx 3788

So, the correct option is A).

For more information, refer to the link given below:

brainly.com/question/18403552

Answer:

(A) Approximately normal with mean $206,274 and standard deviation $3,788

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = (\sigma)/(√(n)).

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Population:

Right skewed

Mean $206,274

Standard deviation $37,881.

Sample:

By the Central Limit Theorem, approximately normal.

Mean $206,274

Standard deviation s = (37881)/(√(100)) = 3788.1

So the correct answer is:

(A) Approximately normal with mean $206,274 and standard deviation $3,788

Sec (90 -A) sinA = cot (90-A). tan( 90- A)​

Answers

Step-by-step explanation:

sec(90-A) . Sin A = cot (90-A) . tan(90-A)

cosec X sinA = tanA X cotA

1/sinA X sinA = tanA X 1/tanA

1=1

Hence proved

L.H.S=sec(90-A)·sinA

        =cosecA·sinA ;[sec(90-A)= cosecA]

        =1/sinA·sinA ;[cosecA=1/sinA]

        =1

R.H.S=cot(90-A)·tan(90-A)

        =tanA·cotA ;[cot(90-A)=tanA, tan(90-A)=cotA]

        =tanA·1/tanA ;[cotA=1/tanA]

        =1

thus, L.H.S=R.H.S

[Proved]

One seventh of an unknown value

Answers

one seventh of x = (1/7)x
where x is the unknown value