What enzyme splits the hydrogen bonds?

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Answer 1
Answer:

Answer: Helicase Can split hyrdrogen bonds


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A 26-year-old woman is in the clinic today for evaluation of weight gain and fatigue. She is 5 feet 6 inches and weighs 175 pounds. Prior to her pregnancy, she weighed 130 pounds and her maximum weight during pregnancy was 155 pounds. She is now 18 months postpartum and continuing to gain weight despite no change in diet or activity. She reports that the fatigue is getting worse even though her daughter is sleeping reliably through the night and the patient feels she is getting plenty of rest. She takes no other medications and has no significant medical history. Her vital signs today are HR 68, BP 108/60, RR 10, temperature 97° F. The nurse practitioner orders a CBC, TSH, and T4.1. What sources of fatigue is the nurse practitioner evaluating with the CBC, T4, and TSH?2. What other history or clinical findings would be indicative of hypothyroidism?3. The patient’s laboratory values show an elevated TSH and a low T4. What does this mean?4. After starting the patient on thyroid hormone replacement, the nurse practitioner asks the patient to return in 8 weeks to check her TSH level. What is the purpose of this test? What should be done if the test result is abnormal?
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Where do most organisms that live in water get oxygen from? Give a word, not a formula.

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The organism that live in water get oxygen from the oxygen that is dissolved in water.

What is oxygen?

Oxygen is a gas, that is present 18% in the environment. The oxygen is an important for living beings because all are activities of our body is run by oxygen.

The water also contain oxygen in the dissolved form, which is used by the water organism.

Thus, the oxygen that is dissolved in water.

Learn more about oxygen

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Answer:

Most organisms that live in water get oxygen from the dissolved water in the oxygen.

If your goal is to characterize the ETPUM, whose results are more informative: yours or your boss’s? Why? What do your results indicate about the nature of this microbe? Does its biochemical composition most closely resemble that of a prokaryote or a eukaryote? Gram-positive or Gramnegative? Do you agree with your boss’s conclusion that the ETPUM is a prokaryotic-eukaryotic hybrid? Why or why not?

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Answer:

I would say that mine would be more informative in the sense that my results could present only one microorganism because it can be studied in an individual culture. On the contrary,  my boss could be investigating about other microorganism present and the composition can resemble that of prokaryote and eukariote as well.

Explanation:

One true-breeding line of mice is obese and dark and another is lean and light. Dark is dominant to light, but obese and lean exhibit incomplete dominance. What proportion of offspring from a dihybrid cross should be both dark and intermediate between obese and lean

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Answer:

6/16 Intermediate and dark ⇒ 2/16 OoDD + 4/16 OoDd

Explanation:

Due to technical problems, you will find the complete explanation in the attached files

According to the graph shown above, what temperature results in the highest level of enzyme activity?PLZ HELP ASAP

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Correct answer is C. It's really simple.

In peas, the round allele (r) is dominant to the wrinkled allele (r), and tall (t) is dominant to short (t). a pure-breeding round, tall strain is crossed to a wrinkled, short strain, and the f1 plants are crossed back to the wrinkled, short strain. what proportion of the offspring will be wrinkled and tall

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The round allele is dominant (R)
The wrinkled allele is recessive (r)
The tall allele is dominant (T)
The short allele is recessive (t)

The genotype of the f1 generation would be RrTt.So if you cross that back to the wrinkled short then the Punnet of that cross would look like this:

RrTt x rrtt

      RT           Rt           rT          rt
rt   RrTt       Rrtt          rrTt        rrtt
rt   RrTt       Rrtt          rrTt        rrtt
rt   RrTt       Rrtt          rrTt        rrtt
rt   RrTt       Rrtt          rrTt        rrtt

The genotype for a wrinkled tall should be rrTt at least in this case because neither of the parents are pure-breed. 

The proportion would then be then 4/16 or 1/4. There is a 25% chance of  yielding a wrinkled tall. 

Final answer:

When crossing a heterozygous round, tall F1 pea plant with a homozygous wrinkled, short pea plant, the probability of the offspring being wrinkled and tall is 1/4.

Explanation:

In pea plants, we have two traits where round seed shape (R) is dominant to wrinkled seed shape (r), and tall height (T) is dominant to short height (t). When a homozygous round, tall plant (RRTT) is crossed with a homozygous wrinkled, short plant (rrtt), the resulting F1 generation will all have the genotype RrTt (heterozygous for both traits). If these F1 plants are then crossed back to the wrinkled, short strain (rrtt), we need to look at each trait separately to determine the phenotype ratios.

For the seed shape, the F1 plants (Rr) crossed with the wrinkled, short (rr) can produce offspring with either Rr or rr genotype. Therefore, the probability of having a wrinkled (rr) offspring is 1/2. For height, the F1 plants (Tt) crossed with the wrinkled, short (tt) can also produce offspring with either Tt or tt genotype. The probability of having a tall (Tt) offspring is 1/2 as well. To find the proportion of offspring that are wrinkled and tall, we multiply the probabilities of the independent events: 1/2 (chance of being wrinkled) × 1/2 (chance of being tall) which equals 1/4.

Therefore, the proportion of offspring that will be wrinkled and tall from this cross is 1/4.

Through which process do producers make food

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Answer:photosynthesis

Explanation:

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Answer:Producers make food for the rest of the ecosystem through the process of photosynthesis, where the energy of the sun is used to convert carbon dioxide and water into glucose