What is the slope of the line represented by the equation 10x + 5y = 4?What is the slope of the line represented by the equation y = x/3 - 5
1. Which ordered pairs make the equation true?
3x + 2y = –7
Choose all answers that are correct.
(Points : 1)
(–3, 1)
(–2, –1)
(1, –4)
(3, –8) this one has two answers
I already have the answers I just want to make sure its correct.
Answers
Answer 1
Answer:
1.
Convert the equations into the slope-intercept form y=mx+b.
2.
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The ordered pairs (-3,1) and (3,-8) make the equation true.
Convert the equations into the slope-intercept form y=mx+b.
2.
The ordered pairs (-3,1) and (3,-8) make the equation true.
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What is the answer to 16 x 2
Answers
The answer is (.5,-1)
Answers
10 kilograms are bigger.
None are bigger than the other since they are both weight measures and not size measures. If you were asking which is heavier than your answer is 10 kilograms.
100
360
600
Answers
100
From 5 men you can form 5x4x3x2 /(4!) different committes of 4 men = 5 different committes.
From 6 women, you can form 6x5x4 / (3!) different committes of 3 women = 20 different committes.
Total combinations: 5 x 20 = 100.
From 5 men you can form 5x4x3x2 /(4!) different committes of 4 men = 5 different committes.
From 6 women, you can form 6x5x4 / (3!) different committes of 3 women = 20 different committes.
Total combinations: 5 x 20 = 100.
Answers
The answer is
56/0.04=1400
56/0.04=1400
Answers
first, add hours until the difference is less than an hour. You can add 3 hours on to make it 9:32 p.m. Then, add minutes on until it's the exact time. from 9:32 to 9:48, you can add 16 minutes, so the total time in the movie was 3 hours, 16 minutes.
Answers
(a).
The product of two binomials is sometimes called FOIL.
It stands for ...
the product of the First terms (3j x 3j)
plus
the product of the Outside terms (3j x 5)
plus
the product of the Inside terms (-5 x 3j)
plus
the product of the Last terms (-5 x 5)
FOIL works for multiplying ANY two binomials (quantities with 2 terms).
Here's another tool that you can use for this particular problem (a).
It'll also be helpful when you get to part-c .
Notice that the terms are the same in both quantities ... 3j and 5 .
The only difference is they're added in the first one, and subtracted
in the other one.
Whenever you have
(the sum of two things) x (the difference of the same things)
the product is going to be
(the first thing)² minus (the second thing)² .
So in (a), that'll be (3j)² - (5)² = 9j² - 25 .
You could find the product with FOIL, or with this easier tool.
______________________________
(b).
This is the square of a binomial ... multiplying it by itself. So it's
another product of 2 binomials, that both happen to be the same:
(4h + 5) x (4h + 5) .
You can do the product with FOIL, or use another little tool:
The square of a binomial (4h + 5)² is ...
the square of the first term (4h)²
plus
the square of the last term (5)²
plus
double the product of the terms 2 · (4h · 5)
________________________________
(c).
Use the tool I gave you in part-a . . . twice .
The product of the first 2 binomials is (g² - 4) .
The product of the last 2 binomials is also (g² - 4) .
Now you can multiply these with FOIL,
or use the squaring tool I gave you in part-b .
The product of two binomials is sometimes called FOIL.
It stands for ...
the product of the First terms (3j x 3j)
plus
the product of the Outside terms (3j x 5)
plus
the product of the Inside terms (-5 x 3j)
plus
the product of the Last terms (-5 x 5)
FOIL works for multiplying ANY two binomials (quantities with 2 terms).
Here's another tool that you can use for this particular problem (a).
It'll also be helpful when you get to part-c .
Notice that the terms are the same in both quantities ... 3j and 5 .
The only difference is they're added in the first one, and subtracted
in the other one.
Whenever you have
(the sum of two things) x (the difference of the same things)
the product is going to be
(the first thing)² minus (the second thing)² .
So in (a), that'll be (3j)² - (5)² = 9j² - 25 .
You could find the product with FOIL, or with this easier tool.
______________________________
(b).
This is the square of a binomial ... multiplying it by itself. So it's
another product of 2 binomials, that both happen to be the same:
(4h + 5) x (4h + 5) .
You can do the product with FOIL, or use another little tool:
The square of a binomial (4h + 5)² is ...
the square of the first term (4h)²
plus
the square of the last term (5)²
plus
double the product of the terms 2 · (4h · 5)
________________________________
(c).
Use the tool I gave you in part-a . . . twice .
The product of the first 2 binomials is (g² - 4) .
The product of the last 2 binomials is also (g² - 4) .
Now you can multiply these with FOIL,
or use the squaring tool I gave you in part-b .
a. (3j - 5)(3j + 5)
3j(3j + 5) - 5(3j + 5)
3j(3j) + 3j(5) - 5(3j) - 5(5)
9j² + 15j - 15j - 25
9j² - 25
b. (4h + 5)²
(4h + 5)(4h + 5)
4h(4h + 5) + 5(4h + 5)
4h(4h) + 4h(5) + 5(4h) + 5(5)
16h² + 20h + 20h + 25
16h² + 40h + 25
c. (g - 2)²(g + 2)²
(g - 2)(g - 2)(g + 2)(g + 2)
(g(g - 2) - 2(g - 2))(g(g + 2) + 2(g + 2))
(g(g) - g(2) - 2(g) + 2(2))(g(g) + g(2) + 2(g) + 2(2))
(g² - 2g - 2g + 4)(g² + 2g + 2g + 4)
(g² - 4g + 4)(g² + 4g + 4)
g²(g² + 4g + 4) - 4g(g² + 4g + 4) + 4(g² + 4g + 4)
g²(g²) + g²(4g) + g²(4) - 4g(g²) - 4g(4g) - 4g(4) + 4(g²) + 4(4g) + 4(4)
g⁴ + 4g³ + 4g² - 4g³ - 16g² - 16g + 4g² + 16g + 16
g⁴ + 4g³ - 4g³ + 4g² - 16g² + 4g² - 16g + 16g + 16
g⁴ - 12g² + 4g² + 16
g⁴ - 8g² + 16
3j(3j + 5) - 5(3j + 5)
3j(3j) + 3j(5) - 5(3j) - 5(5)
9j² + 15j - 15j - 25
9j² - 25
b. (4h + 5)²
(4h + 5)(4h + 5)
4h(4h + 5) + 5(4h + 5)
4h(4h) + 4h(5) + 5(4h) + 5(5)
16h² + 20h + 20h + 25
16h² + 40h + 25
c. (g - 2)²(g + 2)²
(g - 2)(g - 2)(g + 2)(g + 2)
(g(g - 2) - 2(g - 2))(g(g + 2) + 2(g + 2))
(g(g) - g(2) - 2(g) + 2(2))(g(g) + g(2) + 2(g) + 2(2))
(g² - 2g - 2g + 4)(g² + 2g + 2g + 4)
(g² - 4g + 4)(g² + 4g + 4)
g²(g² + 4g + 4) - 4g(g² + 4g + 4) + 4(g² + 4g + 4)
g²(g²) + g²(4g) + g²(4) - 4g(g²) - 4g(4g) - 4g(4) + 4(g²) + 4(4g) + 4(4)
g⁴ + 4g³ + 4g² - 4g³ - 16g² - 16g + 4g² + 16g + 16
g⁴ + 4g³ - 4g³ + 4g² - 16g² + 4g² - 16g + 16g + 16
g⁴ - 12g² + 4g² + 16
g⁴ - 8g² + 16
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