Name four rays that have Point e as an endpoint
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Answer:
EF, ED, EG and EA
Step-by-step explanation:
We know that, a ray is a line segment having one end point and reaches infinity on the other side.
It is required to find rays having E as an end point.
So, we can see from the figure that,
EF, ED, EG and EA are the four rays having E as an end point.
EB is not a ray as it has two end point, which is not possible in a ray.
Hence, we have that four rays having E as end point are EF, ED, EG and EA.
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What is he GCF of -14 and 28
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Answer:
960, 160 for each face / base
Step-by-step explanation:
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percent: 80%
decimal: 0.8
would be the fraton
various supplies. They still plan to purchase balloons to decorate the room at a cost of $0.65 per balloon. Which of the following inequalities represents the total number of
balloons, b, they can purchase and not spend over their budgeted amount?
Answers
Answer:
There are two inequalities that represent the total number of
balloons, b, they can purchase and not spend over their budgeted amount:
0.65b ≤ 70
0.65b + 225 ≤ 295
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
Budget to plan the event = $ 295
Expenses on supplies so far = $ 225
Cost of each balloon = $ 0.65
2. Which of the following inequalities represents the total number of
balloons, b, they can purchase and not spend over their budgeted amount?
1. Let's find how much of the budget is still available:
Budget available = Budget to plan the event - Expenses on supplies so far
Budget available = 295 - 225
Budget available = $ 70
2. Let's find the inequality that represents the total number of
balloons, b, they can purchase and not spend over their budgeted amount.
Number of balloons ≤ Budget available/Cost of each balloon
Replacing with the values we know, we have:
b ≤ 70/0.65
0.65b ≤ 70
or we can write it also including the total budget this way:
Number of balloons ≤ Budget to plan the event - Expenses on supplies so far /Cost of each balloon
Replacing with the values we know, we have:
b ≤ (295 - 225)/0.65
0.65b ≤ 295 - 225
0.65b + 225 ≤ 295
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10^ 8 is 100 million
10^8 is closer, it is only 130 million away while 10^7 is 220 million away