Stuart earns $7.50 an hour plus tips. Select the equation that describes m, the amount of money he earns in one day if he works h hours and receives t dollars in tips.

Answers

Answer 1

Answer: the equation is
7.50h+t

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HELP!!!! WILL MARK BRAINLIEST!!!!!!

Answers

Answer: The answer is 9 because the equations represent the same expression but just in different forms.

Step-by-step explanation:

Staci is attending a music festival. The ticket to the festival costs $87.96. Staci plans to purchase $30.00 t-shirts from the event for close friends. She is taking $200.00 to the festival. What is the maximum number of t-shirts Staci can purchase?

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since stacy is bringing $200, and the initial cost is $87.96 you would have to subtract $200-87.96 which equals $112.04 this is the money left that stacy could buy shirts with, to figure out how many she needs you would have to do $112.04÷$30.00 this equals a decimal of 3.734666666666667 which would have to round down to 3 because stacy cant make it 4 shirts because she doesn't have enough money. So stacy can purchase a maximum of 3 shirts.
hope this helped:))

Is it true or false an angle bisector cannot be a median

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False, if youre talking about the median/bisector of a triangle, an angle bisector can be a median if and only if the bisected angle is the apex of an isosceles or equilateral triangle.

lucas and erick are factoring the polynomial 12x3 – 6x2 8x – 4. lucas groups the polynomial (12x3 8x) (–6x2 – 4) to factor. erick groups the polynomial (12x3 – 6x2) (8x – 4) to factor. who correctly grouped the terms to factor? explain.

Answers

Answer:

Both the students were correct.

Step-by-step explanation:

Given : The polynomial is - $12 x^3 - 6 x^2 + 8 x - 4$

To find : Who correctly grouped the terms to factor.

Lucas group the polynomial - $( 12 x^3 + 8 x ) + ( - 6 x^2 - 4 )$

Now, we solve the Lucas polynomial

$(12x^3+8x) + (-6x^2-4)= 4x(3x^2+2 )-2(3x^2+2)$

$(12x^3+8x) + (-6x^2-4)= (3x^2+2 )(4x-2)$

$(12x^3+8x) + (-6x^2-4)= 2(3x^2+2)(2x-1)$

Erick group the polynomial - $(12x^3-6x^2) + (8x- 4)$

Now, we solve the Erick polynomial

$(12x^3-6x^2) + (8x- 4)=6x^2(2x-1)+4(2x-1)$

$(12x^3-6x^2) + (8x- 4)=(6x^2+4)(2x-1)$

$(12x^3-6x^2) + (8x- 4)=2(3x^2+2)(2x-1)$

The factors of Lucas and Erick are same.

Each grouping leads to the same result.

Therefore, Both students are correct.

Answer:

Sample Response: Both students are correct because polynomials can be grouped in different ways to factor. Both ways result in a common binomial factor between the groups. Using the distributive property , this common binomial term can be factored out. Each grouping results in the same two binomial factors.

What did you include in your response? Check all that apply.

Polynomials can be grouped differently to factor.

Each way results in common binomials.

Each can be factored as a product of prime polynomials.

Step-by-step explanation:

as a car drives down the road, its tires spin on their axles. how many times does a tire on a car spin around before needing replacement?

Answers

The number of times a tire on a car spins around before needing replacement depends on various factors such as the type of tire, driving conditions, maintenance, and the lifespan of the tire. It is not possible to provide an exact number without considering these factors. However, we can estimate the lifespan of a tire based on the tire manufacturer's specifications. Tire manufacturers typically provide an estimated mileage rating, such as 40,000 miles or 60,000 miles. This rating indicates the expected mileage before the tire may need replacement. For example, if a tire has an estimated mileage rating of 60,000 miles, we can assume that it will rotate approximately 60,000 times before needing replacement. This assumes that the tire wears evenly and is properly maintained. It's important to note that other factors, such as driving habits, road conditions, and tire maintenance, can affect the lifespan of a tire. Regular inspections, proper tire pressure, and rotation can help extend the life of the tire. The number of times a tire on a car spins around before needing replacement is variable and depends on factors such as the type of tire, driving conditions, maintenance, and the tire's estimated mileage rating provided by the manufacturer.

X2+4x+3=0 what is the quadratic

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$\sf\ For\ ax^2+bx+c=0\ the\ quadratic\ formula\ is\ x=\frac{-b\± \sqrt{b^(2)-4ac} }{2a}.\nYou\ can\ use\ this\ formula\ to\ solve\ the\ problem.\n\n\n\nI'm\ presuming\ that\ your\ equation\ is\ x^2+4x+3=0\n\n\n\na=1\n\n\ b=4\n\n c=3\n\n\n\nPlug\ it\ in\ the\ quadratic\ formula.\n\n\n\nx=\frac{-b\± \sqrt{b^(2)-4ac} }{2a}\n\nx=\frac{-(4)\± \sqrt{(4)^(2)-4(1)(3)} }{2(1)}\n\nx=(-4\± √(16-4(3)) )/(2)\n\nx=(-4\± √(16-12) )/(2)\n\nx=(-4\± √(4) )/(2)\n\nx=(-4\±2)/(2)$

$\sf\ So\ now\ we\ have\ x=(-4+2)/(2)\ and\ x=(-4-2)/(2).\n\n\n\nx=(-4+2)/(2)\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=(-4-2)/(2)\n\nx=(-2)/(2)\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=(-6)/(2)\n\nx=-1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=-3\n\n\n\n{\boxed{\sf\ x=-1\ \ or\ \ x=-3}$

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