Restate newton's third law of motion

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Answer 1
Answer: Newton's third law states that, for every action there is an equal and opposite reaction.

Mathematically, Fa = -Fr

Hope this helps!

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Most asteroids lie between the orbits ofa. Jupiter and Saturn. b. Mars and Jupiter. c. Jupiter and Neptune. d. Mars and Earth.
Which star is closest to our solar system (after the sun)? a. Vega b. Sirius c. Regulus d. Proxima Centauri
If a car decreases from 35m/s to 25/ms after 15 seconds what is its acceleration

Nonuniform positive acceleration

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It means that acceleration changes with time.

What is the velocity of an upward moving 500kg elevator that has 4000 of energy

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Answer:

4 m/s

Step-by-Step Explanation:

E = mgh and h = E/mg

So if you put your numbers in the formula : h = 4000J/500 * 10

you will get h = 4/5 meters

use this , If the elevator moves from top to the ground in a constasnt acceleration you will have all energy (4000 J) transformed into acceleration to speed up its motion.

(All potential energy will be turned into movement energy). As explained in this formula;

mgh = mv²/2 , solve out (v) from the equation

v = √2gh = √2·10·4/5 (digits are together- not related to the problem, just for clarification) = 4 m/s

Answer the velocity of the elevator is

4 m/s

3. An astronaut lands on an alien planet. He places a pendulum (L = 0.200 m) on the surface and sets it in simple harmonic motion, as shown in this graph.Answer the following questions:
a. What is the period and frequency of the pendulum’s motion?
b. How many seconds out of phase with the displacements shown would graphs of the velocity and acceleration be?
c. What is the acceleration due to gravity on the surface of the planet in m/s2? Determine the number of g-forces.
Show any necessary calculations.
Answer:

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All this work for 5 points is a big rip-off, but I'm going to try it anyway,
for myself, just to see if I can do it.

a).  From the graph, I count 9 complete cycles in 5 seconds.
So the frequency is  9/5  =  1.8 per second = 1.8 Hz.
The period is  1/frequency = 5sec / 9 cycles = 0.555... sec .

b).  Velocity = first derivative of displacement = 1/4 cycle behind =
       5/36 sec delayed with respect to displacement = 0.13888... sec.

       Acceleration = first derivative of velocity = 2nd derivative of displacement =
       1/4 cycle behind velocity = 1/2 cycle behind displacement =
       5/36 (0.13888...) sec delayed with respect to velocity, =
       5/18 (0.2777...) sec delayed with respect to displacement.

c).  For small swing angles, the period of an ideal pendulum anywhere is 

                 T = 2pi √(length / local gravity)  .

The astronaut has already done the pendulum and transmitted the data to us, so
we can use his data and this formula to calculate the local gravity where he is.

           P = 2pi √(length / local gravity)

            5/9 sec = 2π √(0.2m / gravity)

         √(0.2m / gravity) =  5/9sec / 2π

Take the reciprocal of each side:    √(gravity) / √(0.2) =  18π / 5

Multiply each side by  √(0.2):    √(gravity) = 18π √(0.2) / 5

Square both sides:      Gravity = (324 π²) (0.2) / 25  =  25.582 m/sec²

This is about  2.608 times  the Earth's gravity.  So it should not surprise us
that the astronaut got fed up playing with his pendulum after only 5 seconds,
and went back to his landing capsule to lie down.

Note:
Even though it's a highly classified secret, closely guarded for reasons of
national security and all that stuff, we can be pretty sure that our man has
landed on Jupiter.  His data and our calculations have produced a value of
25.582 m/s²  for the acceleration of gravity where he is.  This compares with
the value of  24.79 m/s²  measured by previous robotic space-probe missions
to Jupiter.  The difference is less than 3.1% .

The only remaining questions are:

--  How is he managing to sit on top of the planet's gaseous envelope, playing
with his pendulum and staying in radio contact with us, without falling in ?

--  According to the graph, the pendulum was practically at zero displacement
when he released it at Time=0, and the first thing it did when he let go of it
was to swing out to 0.04 radians before turning back.  This troubles me.
Either the pendulum was already swinging before Time=0 on this graph,
or else his data have been seriously doctored.


Describe a situation when you might travel at a high velocity but a low acceleration

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Relaxing in a comfortable seat, reading a book and listening to
some mp3 stored on your pod or your pad, your eyes are getting
heavy, you adjust yourself slightly in the seat, getting slightly more
comfortable, your eyes get so heavy that you can't hold them open,
and you doze off.

Your seat is #24-B in a passenger jet in straight and level flight,
cruising in calm air 35,000 feet above the ground, taking you to
visit your grandmother on the coast, at 500 miles per hour. 

suppose you sit on a rotating stool, holding a big mass in each outstretched hand. if you suddenly drop the masses, will your angular velocity increase, decrease, or stay the same? explain.

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Answer:

When the masses drop, they move with the same angular velocity as you before hitting the ground. i.e., they leave your hand with their angular momentum. So, in one view, you can think the mass decreases, which means the moment of inertia also decreases. Therefore, the angular velocity should increase.

Speakers A and B are vibrating in phase. They are directly facing each other, are 6.69 m apart, and are each playing a 75.0-Hz tone. The speed of sound is 343 m/s. What is the distance from speaker A to the first point on the line between the speakers where constructive interference occurs?

Answers

Answer:

3.117 m

Explanation:

Given that:

the distance of separation between speaker A and speaker B (L) = 6.69 m

Frequency (F) = 750 -Hz tone

Velocity of speed of sound = 343 m/s

The distance from Speaker A to the first point (L₁) on the line can be calculated by using the formula:

L_1=(L-A)/(2)

where A = (Velocity ofthe sound (V))/(Frequency (F))

we have:

L_1=(L-(V)/(F) )/(2)

L_1=(6.69-(343)/(750) )/(2)

L_1=(6.69-0.457 )/(2)

L_1=(6.233 )/(2)

L_1= 3.1165 m

L_1=3.117 m

∴ the distance from speaker A to the first point on the line between the speakers where constructive interference occurs = 3.117 m