Answer:
We conclude that it is a Bronsted-Lowry acid.
Explanation:
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According to Bronsted-Lowry an acid is a chemical species that is capable of yielding protons and a Bronsted-Lowry base is a chemical species capable of accepting protons.
In this case we see that sulfuric acid (H2SO4) loses a proton to become HSO4.
We conclude that it is a Bronsted-Lowry acid.
Explanation:
To find the takeoff speed of the long jumper, we can utilize the physics principles of projectile motion. Given that the long jumper leaves the ground at a 30-degree angle and travels a distance of 8.50 m, we need to find the initial velocity (takeoff speed) of the jumper.
In projectile motion, we can break down the motion into horizontal and vertical components. The horizontal component remains constant, while the vertical component is affected by gravity.
To solve for the takeoff speed, we can focus on the vertical component of motion. The equation that relates the vertical displacement, initial velocity, launch angle, and acceleration due to gravity is as follows:
Δy = v₀y t + (1/2) g * t²,
where:
- Δy is the vertical displacement (8.50 m),
- v₀y is the vertical component of initial velocity (takeoff speed),
- t is the total time of flight, and
- g is the acceleration due to gravity (approximately 9.8 m/s²).
Since the vertical displacement at the peak of the jump is zero (the jumper is at the highest point), we can rewrite the equation as:
0 = v₀y * t + (1/2) g t².
However, we can derive a relation between the time of flight t and the initial velocity v₀y by using the launch angle θ. The time of flight is given by:
t = (2 v₀y sin(θ)) / g.
Substituting this expression for t in the above equation, we have:
0 = v₀y [(2 v₀y sin(θ)) / g] + (1/2) g [(2 v₀y sin(θ)) / g]².
Now, we can solve for v₀y:
0 = v₀y² (2 sin(θ) + sin²(θ)) / g.
Rearranging and isolating v₀y, we get:
v₀y = √[(g Δy) / (2 * sin(θ) + sin²(θ))].
With the given values:
Δy = 8.50 m,
θ = 30 degrees,
g ≈ 9.8 m/s²,
we can substitute these values into the formula:
v₀y = √[(9
Answer:
The new length is 1.20138 m
Explanation:
1- We get the increase in length:
The old length = 1.2 m
The coefficient of expansion of of aluminum is 23 * 10⁻⁶ /K.
The old temperature is 15°C.
The new temperature is 65°C
The increase in length= old length * coefficient of expansion *change in temperature
The increase in length = 1.2 * 23 * 10⁻⁶ * (65-15)
The increase in length = 0.00138 m
2- getting the new length:
new length = old length + increase in length
new length = 1.2 + 0.00138
new length = 1.20138 m
Hope this helps :)
Answer:
Valence electrons
Explanation:
The valence electrons are found in the outermost shell of an atom. They are the most loosely held electrons found within an atom. These valence electrons are involved and are used to form bonds when atoms combines together.
The energy required to remove these loosely held electrons is relatively low compared to electrons located in the inner orbitals. This is why when atoms combines, they use the outermost electrons to form bonds and mimic stable atoms like those of the noble gases.
Answer:
Raindrops are considered damaging to the soil in the following ways:
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b. The flow of air is neither toward the warm air mass nor toward the cold air mass.
c. Air moves so rapidly upward that hurricanes form.
d. Wind stops completely.
Answer: b. The flow of air is neither toward the warm air mass nor toward the cold air mass.
A stationary front forms between two air masses. A stationary front results when the warm front or cold front air stops moving. This occurs due to the fact that warm front and cold front air masses being opposite to each other but neither of them are able to repel the other. This affects the climatic conditions of the region. The weather is often cloudy along a stationary front and also supported with fall of rain and snow especially if the air in the front is cold with low atmospheric pressure.
Therefore, along a stationary front the flow of air is neither toward the warm air mass nor toward the cold air mass.
A stationary front is formed when a cold air mass and a warm air mass meet, but neither is strong enough to displace the other. The air flow is generally neither towards the cold nor warm air mass, often resulting in prolonged cloudiness and precipitation
Along a stationary front, option b best describes what happens. Generally, stationary fronts occur when a cold air mass and a warm air mass meet, but neither is strong enough to move the other. As a result, the flow of air is typically neither toward the warm air mass nor toward the cold air mass. Instead, both air masses essentially stay where they are, often resulting in prolonged periods of cloudiness and precipitation in the area surrounding the front.
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