7x - 3y = 4 2x - 4y = 1 Which of the following system of equations is not equal to the system of equations shown above?

Answers

Answer 1

Answer: This is the system given by you: a) 7x - 3y = 4 and b) 2x - 4y = 1

I will compare it with these three systems:

1) -28x + 12 = -16 and 28x - 56y = 14

You can check that if you mulitply the equation a) times - 4 and the equation b) times -14, you get the equations of this new system. Then the two systems are equal.

2) 28x - 12y = 16 and -6x + 12y = - 3

You can check that if you multiply the equation a) times 4 and the equation b) times - 3 you get the same equations of this system, then the two systems are equals.

3) 14x - 6y = 4 and -14x + 28y = 1

You can check that these equations cannot not be obtained from a) and b) then the systems are different.

You can solve both systems and you will obtaind different values for the xs and the ys.

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Find the x intercept and y intercept for the graph of 2x-3y=6

Answers

xintercept is where the line crosses the x axis or where y=0
yintercept is where the line crosses the y axis or where x=0

2x-3y=6

xint
y=0
2x=6
x=3
xint is x=3 or (3,0)

yint
x=0
-3y=6
divide by -3
y=-2
yint is y=-2 or (0,-2)

xint is (3,0) or at x=3
yint is (0,-2) or at y=-2

2x - 3y = 6
-3y = 6 - 2x
y = -2 + 2/3x

What numerical or variable expression represents the number of days in 3 weeks

Answers

I don't think we will need to use a variable expression for this one.

3 weeks have 7 days, we know that.

So, the numerical expression would be 3 x 7 = 21

3: weeks
7: days
21: days in 3 weeks.

Hope this helped

since there are 7 days in one week
so 3 weeks = 3 X 7 = 21 days
so, 21 is the answer.

dalanay enlarges a photograph tahst is 3 inches long and 2 inches wide. the length of the enlarged photograph is 15 inches. what is the width of the enlarged photograph, in inches?

Answers

Answer:

10 inches

Step-by-step explanation:

Length of photograph, L1 = 3 inches; Length of enlarged photograph, L2 = 15 inches; Width of photograph, W1 = 2 inches; Width of photograph, W2 = ?

Hence, L1/L2 = W1/W2

∴ W2 = (L2*W1)/L1 = (15 X 2)/3 = 10 inches

Use the Factor Theorem to determine whether the first polynomial is a factor of the second polynomial. x - 5; 3x2 + 7x + 40

Answers

Answer:

The polynomial (x -5) is not a factor of second polynomial $3x^2 + 7x + 40$

Step-by-step explanation:

Factor theorem states that if you divide a polynomial p(x) by a factor x -a of that polynomial, then you will get a zero remainder.

i.,e $p(x) = (x-a)q(x)$ which means that if x - a is a factor of p(x), then the remainder, when we do synthetic division by x= a, will be zero.

Determine whether the first polynomial is a factor of the second polynomial.

Given the polynomial: $f(x)=3x^2 + 7x + 40$

For $x-5$ to be a factor of $f(x)=3x^2 + 7x + 40$ , the factor theorems implies that x = 5 must be a zero of f(x).

Now, to test whether $x-5$ is a factor;

Set x -5 = 0

⇒x = 5

Then,

we will use synthetic division method to divide f(x) by x =5

you can see the figure as shown below in the attachment.

Since, the remainder is 150 which is not equal to zero, then Factor theorem says that (x-5) is not a factor of $3x^2 + 7x + 40$

Answer:

No,(x-5) is not a factor of $3x^2+7x+40$

Explanation:

Factor theorem states that if (x-a) is a factor of the function f(x) then f(a) = 0.

We can use this theorem to check whether a polynomial is a factor of other polynomial or not.

Further Explanation:

Here, we have to check if (x-5) is a factor of $3x^2+7x+40$ or not.

For this we can use the above mentioned factor theorem.

In our case,

a = 5

and $f(x)=3x^2+7x+40$

So, we find f(5) and see if it is zero or not. If f(5) = 0 then (x-5) must be the factor the polynomial.

$f(5)=[tex]3(5)^2+7(5)+40\n\n=75+35+40\n\n=150\neq0$

Since, f(5) is not zero. Hence, from factor theorem, (x-5) is not a factor of $3x^2+7x+40$

Learn More:

brainly.com/question/12482195 (Answered by Kudzordzifrancis)

brainly.com/question/11378552 (Answered by Alinakincsem)

Keywords:

Factor theorem, Remainder theorem.

Alfred is taking a trip. He drove 150 mi and then stopped to refuel. He will drive 60 mph to finish his trip. Let x represent the hours it takes for Alfred to complete the rest of his trip, and let y represent the total distance traveled.Complete the function equation that relates Alfred’s total distance traveled to his time.

y =
x +

Answers

Initial distance was 150miles, final distance was 60mph * x(hours it takes for Alfred to complete the rest of his trip)
Therefore y=150 + 60 x

What is ³√16 simplified?

Answers

$\sqrt[3]{16}= \sqrt[3]{8\cdot 2}=\sqrt[3]{8}\cdot \sqrt[3]{2}=2\sqrt[3]{2}$

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