Jason jumped of a cliff into the ocean . His height as a function off time could be models as h(t)=16tsquared + 16t + 480 where t is the time in seconds and h is height in feet. How long did it take Jason to reach his maximum height

Answers

Answer 1
Answer:
I see that you are in high school, and I'm hoping that you've been introduced
to differential calculus, because I don't know how to answer this question without
using it.

We're told that Jason's height above the water is  H(t) = -16t² + 16t + 480 .
We can observe many things from this equation:
-- Up is the positive direction; down is the negative direction.
-- The acceleration of gravity is 32 ft/sec² .
-- Jason jumps upward from the cliff, at 16 ft/sec .
-- The cliff is 480-ft above the water.
(This tells us why the question is only concerned with his maximum height,
and then it ends ... 480-ft is one serious cliff, and what happens after the
peak of his arc is too gruesome to contemplate.)

In any case, his vertical velocity is the first derivative, with respect to time,
of his height above the water.

         V = -32 t + 16

At the peak of his arc, where gravity takes over, his velocity changes from
upward to downward, and it's momentarily zero.

                                           0 = -32t + 16

Add  32t  to each side:    32t = 16

Divide each side by  32:      t = 1/2 second

His height at that instant is     H(0.5) = -16(0.5)² + 16(0.5) + 480 =

                                           4-ft above the cliff,  484-ft above the water,

and then he begins falling from that altitude.

The duration of his dive is      484 = 16 t²
                                                   t = √(484/16) = 5.5 seconds

and he hits the water at      V = a t = (32) x (5.5) = 176 ft/sec = exactly 120 mph

Jason was good man ... a good student, and always kind to everyone he met.
He will certainly be missed.



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Answers

Answer:

D

Step-by-step explanation:   hope this helps

Solve the following equations.X^2 + 5x + 6 = 0
(Factorise)

X^2 + 7x + 11 = 0
(Use the quadratic formula)

Answers

facotr
ax^2+bx+c=0
find what 2 number multiply to c and add to b
what 2 numbers multiply to 6 and add to 5
2 and 3
(x+2)(x+3)=0
set to zero
x+2=0
x=-2
x+3=0
x=-3
x=-2 or -3



other one
for ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}

we are given
x^2+7x+11=0
a=1
b=7
c=11

sub
x=\frac{-7+/- \sqrt{7^(2)-4(1)(11)} }{2(1)}
x=(-7+/- √(49-44) )/(2)
x=(-7+/- √(5) )/(2)
x=(-7+ √(5) )/(2) or (-7- √(5) )/(2)



The perimeter of a rhombus is 28 centimeters. What is the length of each side of the rhombus?

Answers

All sides of a rhombus are congruent. 28/4 (four sides) =7

Each side is 7 cm long

Answer:

Each side is 7 cm long

the product of 8 and a number x is equal to 32. write an algebraic expression, an equation, or an inequality

Answers

The product of 8 and a number x is equal to 32 is 4.

What is product?

A product is the result of multiplication or an expression that identifies the objects (numbers or variables) to be multiplied, called factors.

The order of multiplication of real or complex numbers does not affect the product. this is called the commutative law of multiplication. When multiplying matrices or terms of several other associative algebras, the product usually depends on the order of the factors. For example, matrix multiplication is noncommutative, as is multiplication in other algebras in general.

Given:

so the  product of the two numbers (8 and x) IS equal to 32,

8x=32

x = (32)/(8)

x = 4

To learn more about product, refer;

brainly.com/question/11927706

#SPJ2

The product means multiply, so the PRODUCT of the two numbers (8 and x) IS equal to 32, so...
8x=32
(-Divide 8 on both sides to isolate the variable)
x=4
(Your result is x=4) :-)

Simplify the expression. q+12q

a. -13q

b. -11q

c. 11q

d. 13q

Answers

Answer:

13q

Step-by-step explanation:

q is the same as 1q

1q + 12q = 13q

What is the measure of angle p?

Answers

the answer to the question is 67.38