What is The equation of the line passing through (0,6) and (3,0)A) y= -1/2x+6
B) y=-1/2x+3
C) y=-2x+6
D) y=-2x+3

Answers

Answer 1

Answer: slope of that line would be
(0-6)/(3-0) = (-6)/3 = -2

then slope intercept form is
y = mx + b
where m = slope and b is the y intercept
so now we have y = -2x + b

and the y intercept is when x = 0
so b = 6 from that point (0,6)

so we have the equation
y = -2x + 6

which is option C

Related Questions

If the probability that the Seahawks will win any given game is 0.6, the probability that they will lose three games in a row is _? Write your answer as a decimal.
In scientific notation, 330 is written?
Which of the following could not be true for a function?Domain is {2}, Range is {2} Domain is {2, 3}, Range is {2} Domain is {2}, Range is {2, 3} Domain is {2, 3}, Range is {2, 3}
Mr. Willett was taking 3 students on a hiking excursion. He had 2 2⁄3 pounds of trail mix to split between the students. How many pounds trail mix did each student get?
In what order do numbers go?

Arrange the circles (represented by their equations in general form) in ascending order of their radius lengths.x2 + y2 − 2x + 2y − 1 = 0
x2 + y2 − 4x + 4y − 10 = 0
x2 + y2 − 8x − 6y − 20 = 0
4x2 + 4y2 + 16x + 24y − 40 = 0
5x2 + 5y2 − 20x + 30y + 40 = 0
2x2 + 2y2 − 28x − 32y − 8 = 0
x2 + y2 + 12x − 2y − 9 = 0

Answers

The correct answer is:

x²+y²-2x+2y-1 = 0;
x²+y²-4x+4y-10 = 0;
5x²+5y²-20x+30y+40 = 0;
x²+y²-8x-6y-20 = 0;
x²+y²+12x-2y-9 = 0;
4x²+4y²+16x+24y-40 = 0; and
2x²+2y²-28x-32y-8 = 0

Explanation:

For each of these, we want to write the equation in the form
(x+h)²+(y+k)² = r².

To do this, we evaluate the terms 2hx and 2ky in each equation. We will take half of this; this will tell us what h and k are for each equation.

For the first equation:
2hx = -2x and 2ky = 2y.

Half of -2x = -1x and half of 2y = 1y; this means h = -1 and k = 1:
(x-1)² + (y+1)² + ___ - 1 = 0

When we multiply (x-1)², we get
x²-2x+1.
When we multiply (y+1)², we get
y²+2y+1.

This gives us 1+1 = 2 for the constant. We know we must add something to 2 to get -1; 2 + ___ = -1; the missing term is -3. Add that to each side (to have r² on the right side of the equals) and we have
(x-1)² + (y+1)² = 3
This means that r² = 3, and r = √3 = 1.732.

For the second equation, 2hx = -4x and 2ky = 4y; this means h = -4/2 = -2 and k = 4/2 = 2. This gives us
(x-2)² + (y+2)² -10 + ___ = 0.

Multiplying (x-2)² gives us
x²-4x+4.
Multiplying (y+2)² gives us
y²+4x+4.
This gives us 4+4= 8 for our constant so far.

We know 8 + ___ = -10; this means the missing term is -18. Add this to each side of the equation to have
(x-2)²+(y+2)² = 18; r² = 18; r = √18 = 3√2 = 4.243.

For the third equation, 2hx = -8x and 2ky = -6y. This means h = -8/2 = -4 and k = -6/2 = -3. This gives us:
(x-4)²+(y-3)²-20 = 0

Multiplying (x-4)² gives us
x²-8x+16.
Multiplying (y-3)² gives us
y²-6y+9.

This gives us 16+9 = 25 for the constant. We know that 25+___ = -20; the missing term is -45. Add this to each side for r², and we have that
r²=45; r = √45 = 3√5 = 6.708.

For the next equation, we factor 4 out of the entire equation:
4(x²+y²+4x+6y-10)=0.
This means 2hx = 4x and 2ky = 6y; this gives us h = 4/2 = 2 and k = 6/2 = 3. This gives us
4((x+2)²+(y+3)² - 10) = 0.

Multiplying (x+2)² gives us
x²+4x+4.
Multiplying (y+3)² gives us
y²+6y+9.

This gives us a constant of 4+9 = 13. We know 13+__ = -10; this missing value is -23. Since we had factored out a 4, that means we have 4(-23) = -92. Adding this to each side for r², we have
r²=92; r = √92 = 2√23 = 9.59.

For the next equation, we factor out a 5 first:
5(x²+y²-4x+6y+8) = 0. This means that 2hx = -4x and 2ky = 6y; this gives us h = -4/2 = -2 and k = 6/2 = 3:

5((x-2)²+(y+3)²+8) = 0.

Multiplying (x-2)² gives us
x²-4x+4.
Multiplying (y+3)² gives us
y²+6y+9.

This gives us a constant of 4+9 = 13. We know that 13+__ = 8; the missing value is -5. Since we factored a 5 out, we have 5(-5) = -25. Adding this to each side for r² gives us
r²=25; r = √25 = 5.

For the next equation, we first factor a 2 out:
2(x²+y²-14x-16y-4) = 0. This means 2hx = -14x and 2ky = -16y; this gives us h = -14/2 = -7 and k = -16/2 = -8:

2((x-7)²+(y-8)²-4) = 0.

Multiplying (x-7)² gives us
x²-14x+49.
Multiplying (y-8)² gives us
y²-16x+64.

This gives us a constant of 49+64=113. We know that 113+__ = -4; the missing value is -117. Since we first factored out a 2, this gives us 2(-117) = -234. Adding this to each side for r² gives us
r²=234; r = √234 = 3√26 = 15.297.

For the last equation, 2hx = 12x and 2ky = -2; this means h = 12/2 = 6 and k = -2/2 = -1:
(x+6)²+(y-1)²-9 = 0

Multiplying (x+6)² gives us
x²+12x+36.
Multiplying (y-1)² gives us
y²-2y+1.

This gives us a constant of 36+1 = 37. We know that 37+__ = -9; the missing value is -46. Adding this to each side for r² gives us
r² = 46; r=√46 = 6.78.

Find the radius of each equation:

1.
$x^2 + y^2-2x+2y-1 = 0, \n x^2-2x+1-1 + y^2+2y+1-1-1 = 0, \n (x-1)^2+(y+1)^2=3$ , then $r_1= √(3)$ .

2.
$x^2 + y^2-4x + 4y- 10 = 0, \n x^2 -4x+4-4+ y^2 + 4y+4-4- 10 = 0, \n (x-2)^2+(y+2)^2=18$ , then $r_2= √(18)=3 √(2)$ .

3.
$x^2 + y^2-8x- 6y- 20 = 0, \n x^2-8x+16-16+ y^2- 6y+9-9- 20 = 0, \n (x-4)^2+(y-3)^2=45$ , then $r_3= √(45) =3 √(5)$ .

4.
$4x^2 + 4y^2+16x+24y- 40 = 0, \n 4x^2+16x+16-16+ 4y^2+24y+36-36- 40 = 0, \n 4(x+2)^2+4(y+3)^2=92,\n (x+2)^2+(y+3)^2=23$ , then $r_4= √(23)$ .

5.
$5x^2 + 5y^2-20x+30y+ 40 = 0, \n 5x^2-20x+20-20+ 5y^2+30y+45-45- 40 = 0, \n 5(x-2)^2+5(y+3)^2=105,\n (x-2)^2+(y+3)^2=21$ , then $r_5= √(21)$ .

6.
$2x^2 + 2y^2-28x-32y- 8= 0, \n 2x^2-28x+98-98+ 2y^2-32y+128-128- 8= 0, \n 2(x-7)^2+2(y-8)^2=234,\n (x+2)^2+(y+3)^2=117$ , then $r_6= √(117)=3√(13)$ .

7.
$x^2 + y^2+12x-2y-9 = 0, \n x^2+12x+36-36+ y^2-2y+1-1- 9 = 0, \n (x+6)^2+(y-1)^2=46$ , then $r_7= √(46)$ .

Hence
$r_1= √(3)$ , $r_2=3 √(2)$ , $r_3=3 √(5)$ , $r_4= √(23)$ , $r_5= √(21)$ , $r_6= 3√(13)$ , $r_7= √(46)$ and $r_1\ \textless \ r_2\ \textless \ r_5\ \textless \ r_4\ \textless \ r_3\ \textless \ r_7\ \textless \ r_6$ .

Mikaela is competing in a race in which she both runs and rides a bicycle. She runs 5 kilometers in 0.5 hour and rides her bicycle 20 kilometers in 0.8 hour. A. At the rate given, how many kilometers can Mikaela run in 1 hour?
____________________
B. At the rate given, how many kilometers can Mikaela bike in 1 hour?
____________________
c. If Mikaela runs for 1 hour and bikes for 1 hour at the rates given, how far will she travel?
____________________

Answers

As Mikaela is running 5km in 0.5 hours, as you're looking for an hour, you double it. Therefore, she can run 10km in 1 hour.
As she bikes 20km in 0.8 hours- she bikes 5km in 0.2 of an hour, therefore, she bikes 25km per hour.
If she continues at this rate, she will travel 35km in 2 hours.
A) 10km
B) 25Km
C) 35 KM
Hope this helps :)

Mikaela can run 10 kilometers in 1 hour.

Mikaela can bike 25 kilometers in 1 hour.

If Mikaela runs for 1 hour and bikes for 1 hour at the given rates, she will travel a totaldistance of 35 kilometers.

We have,

To find the number of kilometers Mikaela can run in 1 hour, we can set up a proportion using the information given:

5 kilometers / 0.5 hour = x kilometers / 1 hour

Cross-multiplying, we get:

(5 kilometers) x (1 hour) = (0.5 hour) x (x kilometers)

Simplifying:

5 kilometers = 0.5x kilometers

To isolate x, we can divide both sides of the equation by 0.5:

5 kilometers / 0.5 = x kilometers

x = 10 kilometers

Similarly, to find the number of kilometers Mikaela can bike in 1 hour, we can set up a proportion:

20 kilometers / 0.8 hour = x kilometers / 1 hour

Cross-multiplying:

(20 kilometers) x (1 hour) = (0.8 hour) x (x kilometers)

Simplifying:

20 kilometers = 0.8x kilometers

Dividing both sides by 0.8:

20 kilometers / 0.8 = x kilometers

x = 25 kilometers

To find the totaldistance Mikaela will travel if she runs for 1 hour and bikes for 1 hour, we can simply add the distances:

Distance = distance run + distance biked

Distance = 10 kilometers + 25 kilometers

Distance = 35 kilometers

Therefore,

Mikaela can run 10 kilometers in 1 hour.

Mikaela can bike 25 kilometers in 1 hour.

If Mikaela runs for 1 hour and bikes for 1 hour at the given rates, she will travel a totaldistance of 35 kilometers.

Learn more about speed here:

brainly.com/question/7359669

#SPJ6

The answer to the polynomial

Answers

-Polynomials don't have answers.
This question just wants you to add 2 polynomials.
The pencil work under the first one is incorrect.

Here's what you need to do to find the sum of polynomials:

-- Remove parentheses.
(If there's a plus sign before the whole parentheses, then just erase the parentheses. If there's a minus sign before the whole thing, then change the sign of each term inside, and erase the parentheses.)

-- Add up all the x² terms.
Like this ...

x² + x² = 2x²
or
2x² + 7x² = 9x²

-- Add up all the x³ terms the same way.

-- Add up all the 'x' terms the same way.

-- Add up the plain numbers.

-- Write down all the sums as a new polynomial.

Find the slope between the two points (-5,5) and (3,-5)

Answers

the formula is y2 minus y1 over x2 minus x1 or rise (y) over run (x). So you would do (-5) - (5) over (3) - (-5). that would equal -10 over 8, or -5/4 when you simplify. your slope would be -5/4

Ron takes a ribbon thats 48inches long and cuts it in 2pcs, how long is each pcs, 1 pc is 3times as the other how long is each pcs.

Answers

48/4 because it is 3 times as long as the other piece thinking there are 4 pieces. So one piece has to be 12 because 48/4 is 12 and 12 x 3 is 36 so then we double check 12+36=48 so the pieces are 12inc and 36inc

HELP PLS WILL GIVE BRAINLISTE