In the rhombus, m<1=18x, m<2-x+y, and m<3=30z. Find the value of x+y+z. The diagram is not drawn to scale.(1point)

Answers

Answer 1
Answer: x + y = 18x  y = 17x18x = 30z  x = 30z/1830z = 18x  z = 18x/30 hope that helps

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Complete answer choices

In hoping to make it onto the school's Gold Team, Bryan, Eli,and Damien took golf lessons over the summer.Bryan signed up to take 4 lessons with a semi-pro instructor, and each lesson cost $32.00 for a 45-minute session. The instructor advised Bryan to buy a bag of bulk practice balls to use during his lessons. After buying a bag of 32 golf balls, the total cost for his lessons and golf balls is $132.48.
Eli signed up to take 6 lessons with a pro instructor, and each lesson cost $52.00 for a 1-hour session. Eli bought a bag of bulk practice balls to use during his lessons. After buying a bag of 40 golf balls, the total cost for his lessons and golf balls is $319.20.
Damien signed up to take 5 lessons with pro instructor, and each lesson cost $28.00 for a 30-minute session. Based on the instructor's advise, he bought a bag of 24 golf balls to use during his lessons. The total cost for his lessons and golf balls is $144.08.
Place the students in order from the least amount to the greatest amount that they paid per golf ball.

Answers

bryan: 32*4 = 128

132.48 - 128 = 4.48

4.48 /32 = 0.14 per golf ball

Eli: 52 *6 = 312

319.20 - 312 = 7.20

7.20 / 40 = 0.18 per golf ball

Damien: 28*5 = 140

144.08 - 140 = 4.08

4.08 / 24 = 0.17 per ball


 least to greatest:

Bryan, Damien, Eli

I know it is simple, but my mind is overloaded right now. Help would be appreciated

Answers

OK.  Don't blow a fuse.

Remember:  The interior angles of every triangle always add up to 180 degrees.

So ' x ' is whatever you need to add to (60+70) to reach 180.

     60 + 70 = 130 .

Make up the difference between 130 and 180, and you'll have ' x '.

Solve the following equation: 6y – 20 = 2y – 4.A. y = 3
B. y = 16
C. y = 4
D. y = 2

Answers

6y - 20 = 2y - 4

Add 20 on both sides

6y - 20 + 20 = 2y - 4 + 20
6y = 2y - 4 + 20
6y = 2y + 16

Subtract 2y on both sides.

6y - 2y = 2y - 2y + 16
6y - 2y = 16
4y = 16

Divide 4 on both sides.

4y/4 = 16/4
y = 16/4

y = 4.

Your final answer is C. y = 4.
6y-20 =2y-4
  
ans: y=4

hope it would help

What is the sum of the angle measures in a 22-gon?360°
2,200°
3,600°
3,960°

Answers

Answer:

Option 3rd is correct

the sum of the interior angles measures in a 22-gon is, 3600°

Step-by-step explanation:

Sum of the interior angles of a polygon of n -sides is given by:

\tetx{Sum} = (n-2) * 180^(\circ)        ....[1]

As per the statement:

Given that:

n = 22-gon

Substitute in [1] we have;

\text{Sum} = (22-2) * 180^(\circ)

\text{Sum} = 20 * 180^(\circ)

\text{Sum} =3600^(\circ)

Therefore, the sum of the interior angles measures in a 22-gon is, 3600°

The sum of the angle measures in a 22-gon is 3600° (option c).

The sum of the angle measures in an n-gon (polygon with n sides) can be calculated using the formula:

Sum of interior angles = (n - 2) * 180°

For a 22-gon, n = 22, so the sum of the interior angles is:

Sum = (22 - 2) * 180°

Sum = 20 * 180°

Sum = 3600°

Therefore, the correct answer is option C: 3,600°.

To know more about angle:

brainly.com/question/31818999


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John can service a television and a cable box in one hour. It took him four hours yesterday to service two televisions and ten cable boxes. How many minutes does John need to service a cable box?

Answers

For this item, we let x be the number of minutes he can service a television and y be the minutes he can service a cable box. Then, the system of linear equation that would best represent the given above is,
                                x + y = 60 
                                2x + 10 y = (4)(60)
The values of x and y from the equations are 45 and 15 minutes, respectively. Therefore, John needs 15 minutes to service a cable box. 

Two road crews, working together, repaired 1 mile of road in 4 hours. working separately, one of the crews takes about 6 hours to repair a similar road. how much time would the other crew, working alone, need to repair a similar road?

Answers

see the attached photo