Sherlock Holmes discovers some hair fiber at a crime scene. He view the hairs through his magnifying glass from a distance of 6 cm. If the hairs are magnified 4.0 times, what is the distance to the magnified image?

Answers

Answer 1
Answer:

This question involves the concept of magnification.

The distance to the magnified image will be "24 cm".

Image Distance

The magnification of the magnifying glass is given by the following formula:

M=(q)/(p)\n\nq=Mp

where,

  • q = image distance = ?
  • M = Magnification = 4
  • p = object distance = 6 cm

Therefore,

q = (4)(6 cm)

q = 24 cm

Learn more about magnification here:

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A 15 kg box is sliding down an incline of 35 degrees. The incline has a coefficient of friction of 0.25. If the box starts at rest, how fast is it moving after it travels 3 meters?

The angle between the two vectors A=3i^+4j^​+5k^ and B=3i^+4j^​−5k^ will be: a. 90 degree b. 0 degree . 60 degree d. 30 degree

Answers

Answer:

Both vectors have the same X and Y components therefore

the angle between the two vectors is zero

(B) is correct

Which technology allows doctors to evaluate whether an athlete has broken a bone?

Answers

Answer;

X-ray scanners

Explanation;

  • Diagnostic imaging techniques in the field of medicine help in determination of the causes of an injury or illness and also ensures accurate diagnosis.
  • X-rays are examples of these diagnostic imaging techniques.
  • X-ray scanners are commonly used to diagnose fractured bones or joint dislocation. X-rays are the fastest and easiest way for doctors to view and assess bone fractures, injuries and joint abnormalities.
  • X-ray used for the bones uses small amount of ionizing radiation to generate pictures of bones in the body.
The technology that is used is an X-ray.

A small piece of Styrofoam packing material is dropped from a height of 1.90 m above the ground. Until it reaches terminal speed, the magnitude of its acceleration is given by a = g − Bv. After falling 0.400 m, the Styrofoam effectively reaches terminal speed, and then takes 5.40 s more to reach the ground.(a) What is the value of the constant B?s-1(b) What is the acceleration at t = 0?m/s2 (down)(c) What is the acceleration when the speed is 0.150 m/s?m/s2 (down)

Answers

Answer:

Explanation:

If a small piece of Styrofoam packing material is dropped from a height of 1.90 m above the ground and reaches a terminal speed after falling 0.400m, the Change in distance will be 1.90m - 0.400 = 1.50m

If it takes 5.4secs fo r the Styrofoam to reach the ground, the terminal velocity will be expressed as;

Vt = change in distance/time

Vt = 1.5m/5.4s

Vt = 0.28m/s

Note that the Styrofoam reaches its final velocity when the acceleration is zero.

To get the constant value B from the equation a = g-Bv

a = 0m/s²

g = 9.81m/s²

v = 0.28m/s

Substituting the parameters into the formula.

0 = 9.81-0.28B

-9.81 = -0.28B

Divide both sides by -0.28

B = -9.81/-0.28

B = 35.04

b) at t = 0sec, the initial terminal velocity is also zero.

Substituting v = 0 into the equation to get the acceleration.

a = g-Bv

a = g-B(0)

a = g

Hence the acceleration at t =0s is equal to the acceleration due to gravity which is 9.81m/s²

c) Given speed v = 0.150m/s

g = 9.81m/s²

B = 35.04

Substituting the given data into the equation a = g-Bv

a = 9.81-35.04(0.15)

a = 9.81 - 5.26

a = 4.55m/s²

Answer:

a

    v  =  0.28 \  m/s

b

    a =  9.8  m/s^2

c

a =  4.55 \  m/s^2

Explanation:

From the question we are told that

The fall height is h  =  1.90 \  m

The magnitude of the acceleration is a =  g -Bv

The height at which terminal speed is attained is h_t  =  0.400 \  m

The time taken to reach the ground from the terminal velocity height is t = 5.40 s

Generally the height which object traveled with terminal velocity is

H  =  h- h_t

=> H  =  1.90 - 0.400

=> H  =  1.50 \ m

Generally the terminal velocity is mathematically represented as

v  =  (H)/(t)

=>        v  =  (1.50)/(5.40)

=>       v  =  0.28 \  m/s

Generally at terminal velocity , acceleration is zero  so

       g -Bv = 0

substituting

       9.8 \ m/s^2

=>    9.8 -B (0.28) = 0

=> v = 35 \  m/s

Generally at t =  0 s the velocity v = 0  (That no motion at time zero)

So  from acceleration equation

    a =  9.8  -35(0)

=>   a =  9.8  m/s^2

Generally when the speed v  =  0.150 m/s

The acceleration is

      a =  9.8  -35(0.150)

=>    a =  4.55 \  m/s^2

   

   

Julie finds a snail on the sidewalk and wants to know whether or not the snail moves throughout the day. She places a single mark on the sidewalk next to the snail.What will Julie use the mark for initially?

Answers

To make a base line mark to know where she started measuring the snails movement, at the end of the day she can measure from her first line to her last to see how far the snail went.
Hope this helped!

 

Answer:

To check the movement of the snail.

Explanation:

the answer was right :)

A wave front has the form of a

Answers

Your answer is "surface of a sphere"

Hope this helps.

A scientist is conducting research to determine how much pressure a dam can withstand. Why are good observations important to his research?

Answers

The things that a scientist should consider while observing the force is the environmental conditions,the force that is expected to act on the dam, the means to contain that force,  and compare different types of designs in accordance with the location of the dam