A skier is skiing down a slope on the mountain. Is the mechanical energy conserved? Why or why not?

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Answer 1

Answer: yes, because mechanical energy is your total amount of energy when you add Potential and Kinetic energy together

Related Questions

In a coffee-cup calorimeter experiment, 10.00 g of a soluble ionic compound was added to the calorimeter contained 75.0 g H2O initially at 23.2°C. The final temperature of the solution was 31.8°C. What was the change in enthalpy for the dissolution of this compound?
What is the definition of an unbalanced force?
What is dispersion, and how is it related to diffraction and refraction?
The shifting of the observed wavelength of light due to the motion of the source toward or away from the observer is called the _____________.
how should the charge q be divided into two parts such that they experience maximum electrostatic repulsion

Brody and Ethel are arguing about waves. Brody says that waving his hand back and forth is a scientific wave. Ethel says that it is not. Which statement best describes who is correct?-Brody is correct because the wave involves an input of energy.
-Ethel is correct because energy is not carried from one place to another.
-Brody is correct because the pattern repeats.
-Ethel is correct because the motion has no pattern.

Also...

Khalad is measuring the amplitude of a wave. What can be known about this wave?
-It is a sound wave.
-It is a transverse wave.
-It is an electromagnetic wave.
-It is a mechanical wave.

Answers

The correct answer is:

B. Ethel is correct because energy is not carried from one place to another.

Brody and Ethel are arguing about waves. Brody says that waving his hand back and forth is a scientific wave. Ethel says that it is not. Ethel is correct because energy is not carried from one place to another.

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The correct answer for the question that is being presented above is this one: "-Ethel is correct because energy is not carried from one place to another; -It is an electromagnetic wave." Brody says that waving his hand back and forth is a scientific wave. Ethel says that it is not.

A 0.89 kg ball is moving horizontally with a speed of 3.8 m/s when it strikes a vertical wall. The ball rebounds with a speed of 1.3 m/s. What is the magnitude of the change in linear momentum of the ball?

Answers

Answer:

The change in momentum, p = -4.539 kg-m/s

Explanation:

It is given that,

Mass of the ball, m = 0.89 kg

Initial speed of the ball, u = 3.8 m/s

Final speed of the ball, v = -1.3 m/s (as it rebounds)

Let p is the change in linear momentum of the ball. We know that the linear momentum is equal to the product of mass and velocity. It is given by :

$p=m(v-u)$

$p=0.89\ kg* ((-1.3)-3.8)\ m/s$

p = -4.539 kg-m/s

So, the change in linear momentum of the ball is 4.539 kg-m/s. Hence, this is the required solution.

How is the frequency of an electromagnetic wave related to energy?A) As the frequency of the wave decreases, its energy increases.
B) As the frequency of the wave fluctuates, its energy decreases.
C) As the frequency of the wave increases, its energy also increases.
D) As the frequency of the wave changes, its energy remains constant.

Answers

As the frequency of the wave increases, its energy also increases. The correct option is C.

The frequency of an electromagnetic wave is defined as the number of oscillations or cycles per unit of time.

The frequency of the wave, on the other hand, is directly proportional to energy.

The energy of an electromagneticwave is precisely proportional to its frequency, according to the equation E = hf, where E represents energy, h is Planck's constant, and f is the frequency of the wave.

Simply said, higher frequency waves have more energy than lower frequency waves.

This is true over the whole electromagneticspectrum, from radio waves to gamma rays. The energy carried by the wave rises as the frequency of the wave increases.

Thus, the correct option is C.

For more details regarding electromagnetic spectrum, visit:

brainly.com/question/23727978

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c) As the frequency of the wave increases, its energy also increases!

Water enters a baseboard radiator at 180 °F and at a flow rate of 2.0 gpm. Assuming the radiator releases heat into the room at a rate of 20,000 Btu/ hr., what is the temperature of the water leaving the radiator?

Answers

Answer:

Temperature of water leaving the radiator = 160°F

Explanation:

Heat released = (ṁcΔT)

Heat released = 20000 btu/hr = 5861.42 W

ṁ = mass flowrate = density × volumetric flow rate

Volumetric flowrate = 2 gallons/min = 0.000126 m³/s; density of water = 1000 kg/m³

ṁ = 1000 × 0.000126 = 0.126 kg/s

c = specific heat capacity for water = 4200 J/kg.K

H = ṁcΔT = 5861.42

ΔT = 5861.42/(0.126 × 4200) = 11.08 K = 11.08°C

And in change in temperature terms,

10°C= 18°F

11.08°C = 11.08 × 18/10 = 20°F

ΔT = T₁ - T₂

20 = 180 - T₂

T₂ = 160°F

A moving car has momentum. If it moves twice as fast what is it's momentum

Answers

as we know that P=mv .. where m is mass and v is velocity ..this relation shows that momentum has a direct relation with these two quantities .. so when velocity is increased twice
P' = mv
P'=m2v
P' = 2 mv here mv is P so
P'=2P
this shows that momentum will also be doubled by doubling the velocity :)

A motorbike is traveling to the left with a speed of 27.0 m s 27.0 s m 27, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction when the rider slams on the brakes. The bike skids 41.5 m 41.5m41, point, 5, start text, m, end text with constant acceleration before it comes to a stop. What was the acceleration of the motorbike as it came to a stop?

Answers

Answer:

Explanation:

Initial velocity , u = 27 m/s

displacement before stop, s = 41.5 m .

final velocity, v = 0

acceleration a = ?

v² = u² + 2 a s

0 = 27² + 2 x a x 41.5

a = - 27² / 2 x 41.5

= - 8.78 m /s

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On a horizontal frictionless surface a mass M is attached to two light elastic strings both having length l and both made of the same material. The mass is displaced by a small displacement Δy such that equal tensions T exist in the two strings, as shown in the figure. The mass is released and begins to oscillate back and forth. Assume that the displacement is small enough so that the tensions do not change appreciably. (a) Show that the restoring force on the mass can be given by F = -(2T∆y)/l (for small angles) (b) Derive an expression for the frequency of oscillation.