How does a sedimentary rock turn into a metamorphic rock?

Answers

Answer 1
Answer: 1. weathering and erosion on Earth's surface is always breaking Rock down 2. Transport 3. Deposition 4. Compaction and cementation. 5. Metamorphism 6. rock melt

Related Questions

What mass of solute is needed to prepare each of the following solutions? a. 3.00 L of 0.125 M K2SO4 b. 550 mL of 0.015 M NaF c. 700 mL of 0.350 M C6H12O6
Would the remains of a living thing have more or less carbon 14 in it after being buried for 10000 years? Why? Please make the answer no more than 5 sentences
Why does a reaction slow down with time?
If the pressure of a 2.00 L sample of gas is 50.0 kPa, what pressure does the gas exert if its volume isdecreased to 20.0 mL?Which equation should you use?V1 V2T1 T2P1V1 = P2V2V1 V₂N1 N2
A box experiences a force of 2 N to the left and 3 N to the right. Which is true of the box's motion?A) The box will slow down. B) The box's velocity will be 1 m/s. C) The box's velocity will not change. D) The box will experience acceleration.

How many molecules are in 2.6 grams H4C

Answers

Molar mass of H4C = 1 * 4 + 12 = 16 g/mol

Number of moles:

n = m / mm

n = 2.6 / 16

n = 0.1625 moles

Number of molecules:

number of moles * 6.02x10²³

0.1625 * 6.02x10²³

= 9.78x10²² molecules

hope this helps!



if a chemist wants to make 1.3L of 0.25M solution of KOH by diluting a stock solution of 0.675 M KOH, how many milliliters of the stock solution would the chemist need to use?

Answers

To solve this we use the equation,

 

M1V1 = M2V2

 

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

 

.675 M x V1 = .25 M x 1.3 L

V1 = 0.48 L or 480 mL

If a chemist wants to make 1.3 L of 0.25 M solution of KOH by diluting a stock solution of 0.675 M KOH, the chemist would need to use 480 mL of the stock solution.

A sample of water is heated from 10.0 degrees Celcius to 15.0 degrees Celcius by the addition of 125 Joules of heat. What is the mass of the water?

Answers

Answer:

125 = 5*4.186*m

m = 125 / 5*4.186 = 5.97g of water.

Explanation:

The water is increased by 5 degrees. This means that for every gram of water, it takes 5*4.186 J to increase the temperature by 5 degrees, aka 5*4.186 J/g

hope this help:)

According to the work of the Curies, which action would increase the radioactivity of polonium?a. Dissolve the polonium in a solvent.
b. Heat the polonium until it becomes a gas.
c. Expose the polonium sample to light.
d. Increase the amount of polonium.

Answers

Answer;

Increase the amount of Polonium

Explanation;

  • Pierre and Marie Curies are known for their work in the study of radioactivity that led to the discoveries of new radioactive elements radium and polonium. Polonium was named after Marie's home country, Poland.
  • Polonium is a rare natural element, it may be found in uranium ores which is uneconomical to extract. Therefore, it is obtained from the bombarding of bismuth-209 with neutron to get bismuth-210, which then undergoes radioactive decay to form Polonium.
  • According to Curies increasing the amount of polonium would increase the radioactivity of Polonium element. Polonium undergoes alpha decay to emit alpha particle and is therefore used as a source of alpha particles.
Of Course D) Increase the amount of Polonium.
You want "Increase" the Radioactivity, And since Polonium is himself radioactive, you need to increase its amount.

Hope this Helps :)

Which of the following is not an acid-base neutralization reaction? (3 points)NH3 + HCl yields NH4Cl

NaOH + CH3COOH yields Na CH3COO + H2O

2HNO3 + Ca(OH)2 yields Ca(NO3)2 + 2H2O

H2SO4 + 2NaCl yields 2HCl + Na2SO4

Answers

fourth option...
H2SO4 + 2NaCl yields 2HCl + Na2SO4


is the correct answer...
because neutralisation reaction yields salt n water but here acid is produced so the solution isn't neutralized......



HOPE IT HELPS YOU '_'

How can you tell which ionic compounds will react in an aqueous solution

Answers

1.  Determine if the ionic substances can break apart into ions.
 - e.g. CaCO3 isn't very soluble, do it can't dissolve and dissociate.  If it can't pop apart, no ions.
2.  Swap the partners for all the other ions that you can get from step 1.  You can skip pairings with the same charge - a + can't get close to another + to react.
3.  Use solubility, acid/base, and redox rules to see if anything will happen with the ions in solution.