To solve this we use the equation,
M1V1 = M2V2
where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.
.675 M x V1 = .25 M x 1.3 L
V1 = 0.48 L or 480 mL
If a chemist wants to make 1.3 L of 0.25 M solution of KOH by diluting a stock solution of 0.675 M KOH, the chemist would need to use 480 mL of the stock solution.
Answer:
125 = 5*4.186*m
m = 125 / 5*4.186 = 5.97g of water.
Explanation:
The water is increased by 5 degrees. This means that for every gram of water, it takes 5*4.186 J to increase the temperature by 5 degrees, aka 5*4.186 J/g
hope this help:)
b. Heat the polonium until it becomes a gas.
c. Expose the polonium sample to light.
d. Increase the amount of polonium.
Increase the amount of Polonium
NaOH + CH3COOH yields Na CH3COO + H2O
2HNO3 + Ca(OH)2 yields Ca(NO3)2 + 2H2O
H2SO4 + 2NaCl yields 2HCl + Na2SO4