Complete combustion of 4.20 g of a hydrocarbon produced 12.9 g of CO2 and 6.15 g of H2O. What is the empirical formula for the hydrocarbon?

Answers

Answer 1
Answer: We calculate first the number of moles of CO2 and H2O produced by dividing the given masses by the molar masses of CO2 and H2O.
 moles CO2 = (12.9 g CO2) x (1 mole CO2 / 12 g CO2) = 1.075 moles.
 moles H2O = (6.15 g H2O) x (1 mole H2O / 18 g H2O) = 0.36 moles
Then, we count the number of C, H, and O moles. This gives us 1.075 moles C, 2.5 moles O and 0.72 moles H. The empirical formula is,
                             C1.075H0.72O2.5
Simplifying, 
                             C4H3O10

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You would like to make a 100 mL buffer solution at pH 8.00. Assuming you would like to accomplish this with a hypochlorous acid (HOCl) buffer (HOCl/NaOCl), Ka= 3.0 * 10-8. If the solution is 0.3 M in HOCl, what concentration of NaOCl would be necessary in the buffer solution to obtain a pH of 8.0?

Answers

Answer:

To obtain the pH of 8.0, the concentration of NaOCl needs to be 0.9 M in the 0.3 M HOCl solution

Explanation:

This problem can be solved by Henderson-Hasselbalch equation, which gives relation between the concentration of acid, its salt, pKa and the pH of the solution. This equation is given as,

pH=-log(K_a)+log([NaOCl])/([HOCl])

By placing the known variables in the above equation we get,

8=-log(3*10^(-8))+log([NaOCl])/(0.3)

8-7.52=log([NaOCl])/([0.3])

10^(0.48)=([NaOCl])/(0.3)

[NaOCl]=10^(0.48)*{0.3}

[NaOCl]=0.9 M

The above calculations show that the required concentration of NaOCl is 0.9 M.

Isopropyl methyl ether is slightly soluble with water because the oxygen atom of ethers with three or fewer carbon atoms can form a few hydrogen bonds with water.(A) True
(B) False

Answers

Isopropyl methyl ether is slightly soluble in water because the oxygen atom of ethers with 3 or lesser carbon atoms can form hydrogen bonds with water. Therefore, the given statement is true.

What is hydrogen bonding?

Hydrogen bonding is a special class of attractive intermolecular forces that arise because of the dipole-dipole interaction between hydrogen that is bonded to a highly electronegative atom and another highly electronegative atom that lies in the neighborhood of the hydrogen atom.

For example, in water, hydrogen is covalently bonded to the oxygen atom. Therefore, hydrogen bonding arises because of the dipole-dipole interactions between the hydrogen atom of one water molecule and the oxygen atom of another water molecule.

The solubility of ether in water depends upon the extent of the formation of hydrogen bonds with water. Ether which contains three carbon atoms is soluble in water due to these lower hydrocarbon atoms can form hydrogen bonding with water.  

But the solubility of hydrocarbons or ethers decreases as increase the number of carbon atoms. This is because higher ethers or ethers with more carbons have more hydrophobic parts. Therefore they cannot be soluble in water as they cannot form hydrogen bonds with water molecules.

Learn more about hydrogen bonding, here:

brainly.com/question/15099999

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Answer:

True

Hydrogen bond is a partial intermolecular bonding interaction between a lone pair on an electron rich donor atom, particularly the second-row elements nitrogen (N), oxygen (O), or fluorine (F), and the antibonding orbital of a bond between hydrogen (H) and a more

electronegative atom or group. Such an interacting system is generally denoted Dn–H···Ac, where the solid line denotes a polar covalent bond, and the dotted or dashed line indicates the hydrogen bond. The use of three centered dots for the hydrogen bond is specifically recommended by the IUPAC. While hydrogen bonding has both covalence and electrostatic contributions, and the degrees to which they contribute are currently debated, the present evidence strongly implies that the primary contribution is covelant.

Hydrogen bonds can be intermolecular (occurring between separate molecules) or

intramolecular (occurring among parts of the same molecule)

of all the hydrogen nuclei in the ocean, 0.0156 how much deuterium could be obtained from 1.0 gal of ordinary tap water

Answers

Answer:

Poop Butt.

Explanation: Poop Butt.

Which is more water soluble hexanoic acid or sodium hexanoate?

Answers

Answer:

Explanation:

Hexanoic acid [CH 3(CH 2) 4COOH] is barely soluble in water (about 1.0 g/100 g of water). Palmitic acid [CH 3(CH 2) 14COOH], with its large nonpolar hydrocarbon component, is essentially insoluble in water. The carboxylic acids generally are soluble in such organic solvents as ethanol, toluene, and diethyl ether.

hope this help ya~

When the reaction mixture is worked-up, it is first washed three times with 5% sodium bicarbonate, and then with a saturated nacl solution. explain why?

Answers

Solution:

After the reaction of mixture is worked-up Washing three times the organic  with sodium carbonate helps to decrease the solubility of the organic layer into the aqueous layer. This allows the organic layer to be separated more easily.

And then the reaction washed by saturated NACL we have The bulk of the water can often be removed by shaking or "washing" the organic layer with saturated aqueous sodium chloride (otherwise known as brine). The salt water works to pull the water from the organic layer to the water layer.

A cylinder is filled with 10.0L of gas and a piston is put into it. The initial pressure of the gas is measured to be 96.0kPa. The piston is now pulled up, expanding the gas, until the gas has a final volume of 45.0L. Calculate the final pressure of the gas. Be sure your answer has the correct number of significant digits.

Answers

Answer:

The final pressure of the gas is:- 21.3 kPa

Explanation:

Using Boyle's law  

{P_1}* {V_1}={P_2}* {V_2}

Given ,  

V₁ = 10.0 L

V₂ = 45.0 L

P₁ = 96.0 kPa

P₂ = ?

Using above equation as:

{P_1}* {V_1}={P_2}* {V_2}

{96.0\ kPa}* {10.0\ L}={P_2}* {45.0\ L}

{P_2}=\frac {{96.0}* {10.0}}{45.0}\ kPa

{P_2}=21.3\ kPa

The final pressure of the gas is:- 21.3 kPa