7kg of soybean oil which costs $4/kg was combined with 14kg of canola which costs $1/kg. Find the cost per kg of mixture.

Answers

Answer 1

Answer: (7*4 + 14*1)/(7+14) = 42/21 = $2/ kg of mixture;

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Round 24,732 to the
nearest thousand.

Answers

Answer:

25,000

Step-by-step explanation:

7 is greater than 5 so we need to round UP

Determine the values of x on which the function f(x)=2x^2-x-15/4x^2-12x is discontinuous and verify the type of discontinuity at each point.A.There is a vertical asymptote at 0 and a hole at 3.
B.There are vertical asymptotes at -5/2 & 0 and a hole at 3.
C.There is a vertical asymptote at 3 and a hole at 0.
D.There are vertical asymptotes at 0 & 3

Answers

We factor the function
f(x)= [ (2x + 5)(x-3) ]/[ 4x(x-3) ], x ≠ 3
f(x)= [ (2x + 5) ]/[ 4x ], x ≠ 3
A full cancellation of a denominator factor means that there will be a hole. The answer is that there is a vertical asymptote at 0 and a hole at 3.

Answer:

We factor the function

f(x)= [ (2x + 5)(x-3) ]/[ 4x(x-3) ], x ≠ 3

f(x)= [ (2x + 5) ]/[ 4x ], x ≠ 3

A full cancellation of a denominator factor means that there will be a hole. The answer is that there is a vertical asymptote at 0 and a hole at 3.

Step-by-step explanation:

FizzFizz soda comes in two varieties, regular and diet. If a researcher has 4 boxes of each, how many ways can he select 2 boxes of each for a quality control test?

Answers

Answer:

Let {A, B, C, D} be the set of boxes of regular sodas and {a, b, c, d} be the set of boxes of diet sodas. Denote $_MC_P$ the numbers of combinations of M boxes taken P boxes. Note that the specific combination, for example, AB from the set of boxes of regular sodas is the same as the combination BA. The number of ways to pick 2 boxes from each category is $_4C_2$ . Hence, the number of ways of picking 4 boxes in which he pick 2 boxes from each category is $_4C_2$ * $_4C_2$ = 6*6 = 36.

Find the perimeter of the figure. Answer exactly or round to at least 2 decimal places.-width is 5 and height is 5

Answers

all you have to do is add up the angles total will equal up to 32.85

That's a square and a semicircle so we should calculate the perimeter for each one and then add them together.

Let's start with the easy one: the square
The perimeter of a square = 4x where x = one side of the square
Since the width of the shape is 5, that means the other three sides of the square should also be five so:

perimeter of square = 4(5)
perimeter of square = 20 units

Now let's find the perimeter of the semicircle.
That equation is this:

perimeter of semicircle = 1/2(π x diameter) + diameter

We know that the width is 5 which means the diameter is 5.
Let's plug that in!

perimeter of semicircle = 1/2(π x 5) + 5

Multiplying pi by 5 and dividing it in half will give us a decimal, so we have to round that to the second place:

perimeter of semicircle = 1/2(5π) +5
perimeter of semicircle ≈ 7.85 + 5
perimeter of semicircle ≈ 12.85 units

Like we said at the beginning, this is two shapes in one so we have to add the perimeter of the square to the perimeter of the semicircle

perimeter of square = 20 units
perimeter of semicircle ≈ 12.85 units

20 + 12.85 = 32.85 units

So the perimeter of the shape = 32.85 units

Which fraction is greater than 2/3?

A. 1/12
B. 2/6
C. 5/12
D. 6/8