What is momentum please help meeeee

Answers

Answer 1
Answer: the quantity of motion of a moving body, measured as a product of its mass and velocity.
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Answer 2
Answer: A golfer, putting on a green requires three strokes to “hole the ball.” During the first putt, the ball roles 5.0m due east. For the second putt, the ball travels 2.1m at an angle of 20 degrees north of east. The third putt is 0.50m due north. What displacement (magnitude

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The red sphere represents a proton. What is the atomic number of this atom

Answers

The atomic number is the number of protons of the atom.

So, just count the number of red spheres (protons) and that is the atomic number of the atom.

The protons are in the nucleus of the atom. Every single element is formed by a representative number of protons (atomic number).

For example, every hydrogen atom has one proton and its atomic number is one.

Every helium atom has two protons and its atomic number is two.

And so on. This permits you to order the elements in the periodic table in increasing atomic number.

There are no two elements with the same number of protons (atomic number) and all the atoms of a same element have the same number of protons.

The atom is apparently too small for us to see,
so we can't identify it.

Which is an example of a physical change* metal rusting
*silver tarnishing
* water boiling
* paper burning

Answers

Water boiling is an example of a physical change. The rest are chemical changes.  
Hope that helps!!

Explain why increasing the temperature of a gas in a closed, rigid container causes the pressure in the container to increase.

Answers

The atoms/ particles that are in the gas have gotten energy from the heat, because of that, they zoom around the container, putting pressure on it :) hope it helps :)

What is a/an Diorama???

Answers

A three-dimensional miniature or life-size scene in which figures, stuffed wildlife, or other objects are arranged in a naturalistic setting against a painted background.

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a three dimensional scene

How many years is a light year

Answers

A "light year" is not an amount of time. 

It's an amount of distance ... the distance that light travels
through space in one year.

1 light year  =  5,878,625,372,000 miles
                     (rounded to the nearest thousand miles)

1 light-year  =  9,460,730,473,000 kilometers 
                     (rounded to the nearest thousand kilometers)




10,108 earth years equals 1 light year

The magnitude of the gravitational field on the surface of a particular planet is 2g. The planet’s mass is half the mass of the Earth. What is the planet’s radius in terms of the radius Rg of Earth?

Answers

Final answer:

To find the planet's radius in terms of the radius Rg of Earth, use the equation g = GM/R^2 and substitute 2g for g. Solve for R to get R = sqrt(1/(2gMg)) * Rg.

Explanation:

To find the planet's radius in terms of the radius Rg of Earth, we need to understand the relationship between the gravitational field and the mass and radius of a planet. The magnitude of the gravitational field on the surface of a planet is given by g = GM/R2, where G is the gravitational constant, M is the mass of the planet, and R is its radius. For the planet in question, we are told that the magnitude of the gravitational field is 2g and its mass is half the mass of Earth. Since the gravitational field is 2g, we can substitute g with 2g in the equation and solve for R in terms of Rg:

2g = GM/R2 → 2gR2 = GM → 2gR2 = (GMg)/(2Rg) → R2/Rg = 1/(2gMg) → R = sqrt(1/(2gMg)) * Rg

Learn more about Gravitational field here:

brainly.com/question/36891747

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Final answer:

To find the radius of a planet with a gravitational field twice that of Earth's and half the mass, the radius is calculated to be half of Earth's radius.

Explanation:

The magnitude of the gravitational field strength g on a planet is given by the equation g = G(M/R^2), where G is the universal gravitation constant, M is the planet's mass, and R is the planet's radius. Given that the gravitational field on the surface of the particular planet is 2g where g is Earth's gravitational field, and the planet's mass is half of Earth's mass, we can derive the planet's radius in terms of Earth's radius Rg. Setting up the proportion (G(1/2M_Earth)/(R^2)) / (G(M_Earth)/(Rg^2)) = 2, and simplifying, we find that R^2 = (1/4)Rg^2. Taking the square root of both sides gives us the final relation R = (1/2)Rg.

Learn more about gravitational field strength here:

brainly.com/question/33710379

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