Please help me solve the equation
3x+10y=48
7x+4y=54

Answers

Answer 1

Answer: 3x+10y=48
7x+4y=54

multiply the first equation by 2 and the 2nd equation by 5 to remove y
6x+20y=96
35x+20y=270
29x=174
x=6

substitute to any equation
7x+4y=54
42+4y=54
4y=12
y=3

the value of x is 6 and the value of y is 3

Answer 2

Answer:

Answer: x=36/7

y=9/2

Step-by-step explanation:

1 Solve for yy in 3+10y=483+10y=48.

y=\frac{9}{2}y=

2 Substitute y=\frac{9}{2}y=

into 7x+4y=547x+4y=54.

7x+18=547x+18=54

3 Solve for xx in 7x+18=547x+18=54.

x=\frac{36}{7}x=

4 Therefore,

\begin{aligned}&x=\frac{36}{7}\\&y=\frac{9}{2}\end{aligned}

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Answers

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Answers

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$(m^(2) -m+3)+(m-1)$
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Answers

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consider solving the equation for x 3 (3x + 4) —5 = ax + b Which statements are true about the solution to the equation when substituting values for a and b as as specified? Select all that apply.A. If a=−3 and b=4 , then there is exactly one solution to the equation.B. If a=−9 and b=13 , then there is no solution to the equation.C. If a=9 and b=−2 , then there is no solution to the equation.D. If a=−3 and b=−5 , then there are infinitely many solutions to the equation.E. If a=9 and b=7 , then there is exactly one solution to the equation.

Answers

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What is the answer for 4x-5=5x-5