During a bike challenge,riders have to collect various colored ribbons. Each 1/2 mile they collect a red ribbon, each 1/8 mile they collect a green ribbon, and each 1/4 they collect a blue ribbon. Which colors of ribbon will be collected at the 3/4 mile marker?Explain.

Answers

Answer 1
Answer: At the 3/4 marker, the rider can collect a green ribbon and a blue ribbon.

Because 3/4 is the 3rd stop for a blue ribbon and 3/4 is the 6th stop for a green ribbon.


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What is the value of the ratio of the surface area to the volume of the right prism? A. 0.39 B. 0.82 C. 0.97 D. 1.04
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Explain howto use partial quotients to divide 235 by 5
The safe fluoride-to-water ratio is 0.5 to 1.4 parts per million (ppm) gallons. What is the range in parts of fluoride that could be added to 500,000 gallons of water?

Trees are planted along a road that is 2 kilometers 50 meters long. Elven trees are planted at an equal distance apart along the road. What is the distance in meters between each tree?

Answers

Dear Lallenbrett, let's find the kilometers in meters which is 2,050 meters. Since there are 10 spaces in between, we do 2050/10= 250 meters in between each tree.

Final answer:

The distance between each tree planted along the 2 kilometers and 50 meters road is 205 meters. This is achieved by dividing the length of the road (2050 meters) by the number of spaces between the trees (10).

Explanation:

To solve this problem, first, we need to understand that a kilometer is equal to 1000 meters. Therefore, 2 kilometers 50 meters is equal to 2050 meters. Given that the 11 trees are planted at an equal distance apart along the 2050 meter road, we would have to divide the total road length by the number of spaces between the trees. The number of spaces is always one less than the number of trees, so we have 11-1 = 10 spaces. Therefore, the distance between each tree is 2050 meters divided by 10, which equals to 205 meters.

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Complete 2x+21= using only the communtative property of addition​

Answers

Answer:

-9.5

Step-by-step explanation:

2x + 21 =

2x + 20 = 1 (C.P)

2x = 1-20

2x = - 19

x= - 19/2

x = - 9. 5

The pre-image point B(-4, 3) is translated to B'(-1, 1). What was the translation used?A. ( x + 3, y + 2)
B. ( x - 3, y - 2)
C. ( x + 3, y - 2)
D. ( x - 3, y + 2)

Answers

the answer is C. youre welcome

Answer:

C. ( x +3, y -2)

Ellis used 48 ounces of rye flour in a bread write an expression you could use to find how many pounds of rye flour Ellis used

Answers

48/16 = 3oz 1 pound = 16 ounces Hence, ounces/16 = pounds

What is the smallest negative integer? Explain.

Answers

There is an INFINITE amount of numbers out there, including BOTH positive and negative.
So, the more closer you go to infinite (that is toward bigger numbers EX: -100,000,000) the smaller the number gets while in the positive direction, the closer the numbers are close to 0, the numbers are small (EX: 1)
Since there is an infinite amount of numbers, there is not really a definite answer to this question.

Luke spendsA total of $41 on three drinks and 10 bags of popcorn Christopher spend a total of $11 on two drinks and two bags of popcorn right assessment equations that can be used to find the price of one using these equations determine the state the price of the bag of popcorn to the nearest cent

Answers

System of equations that can be used to find the price of one drink and the price of one bag of popcorn is:

3d + 10p = 41

2d + 2p = 11

Price of a bag of popcorn is $ 3.5

Solution:

Let "d" be the price of one drink

Let "p" be the price of 1 bag of popcorn

Luke spends total of $41 on three drinks and 10 bags of popcorn

3 drinks x price of one drink + 10 bags of popcorn x price of 1 bag of popcorn = 41

3 * d + 10 * p = 41

3d + 10p = 41 ------ eqn 1

Christopher spend a total of $11 on two drinks and two bags of popcorn

2 drinks x price of one drink + 2 bags of popcorn x price of 1 bag of popcorn = 11

2 * d + 2 * p = 11

2d + 2p = 11 ------- eqn 2

Eqn 1 and eqn 2 represents system of equations that can be used to find the price of one drink and the price of one bag of popcorn

Let us solve eqn 1 and eqn 2 to find values of "d" and "p"

Multiply eqn 2 by 5

10d + 10p = 55 --- eqn 3

Subtract eqn 3 from eqn 1

3d + 10p = 41

10d + 10p = 55

(-) ------------------------

-7d = -14

d = 2

From eqn 2,

2d + 2p = 11

2(2) + 2p = 11

4 + 2p = 11

2p = 7

p = 3.5

Thus price of 1 bag of popcorn is $ 3.5 and price of one drink is $ 2