Describe the difference between polar covalent bonds and nonpolar covalent bonds using these two molecules - H2 and HCl. Which molecule contains a polar covalent bond and which molecule contains a nonpolar covalent bond? Explain your reasoning alongside describing the differences between the types of bonds.

Answers

Answer 1

Answer:

Polar covalent bonds are between atoms with different electronegativities, whereas nonpolar covalent bonds are between atoms with the same electronegativity.

This means that HCl is a polar covalent bond, whereas H2 is a nonpolar covalent bond.

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Nitrogen gas has the chemical formula N2. One molecule of nitrogen gas is made up ofA. one atom of nitrogen and one atom of oxygen.B. two atoms of nitrogen and one atom of oxygen.C. two atoms of nitrogen.D. one atom of nitrogen.
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Chemical changes ________ involve the breaking and making of chemical bonds.A) AlwaysB) NeverC) SometimesFill in the blank
Persamaan kimia bagi magnesium
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Q4. What are the different ways in which human being use rocks ?

Answers

Answer:

To hit someone on the head

Explanation:

self protection

Calculate the number of moles56.75 g of Al(NO3)3
8.35 g of Al2(SO4)3
3.8 g of FeSO4

Answers

number of moles = mass /molar mass

The half-life of radioactive substance is 2.5 minutes. what fraction of the origional radioactive remains after 10 mins

Answers

The answer is 1/16.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. $(1/2)^(n) = x$ ,
where:
n - a number of half-lives
x - a remained fraction of a sample

2. $t_(1/2) = (t)/(n)$
where:
$t_(1/2)$ - half-life
t - total time elapsed
n - a number of half-lives

So, we know:
t = 10 min
$t_(1/2)$ = 2.5 min

We need:
n = ?
x = ?

We could first use the second equation to calculate n:
If:
$t_(1/2) = (t)/(n)$ ,
Then:
$n = (t)/( t_(1/2) )$
⇒ $n = (10 min)/(2.5 min)$
⇒ $n=4$

Now we can use the first equation to calculate the remained fraction of the sample.
$(1/2)^(n) = x$
⇒ $x=(1/2)^4$
⇒ $x= (1)/(16)$

What happens in a reduction half-reaction?elements gain electrons
elements lose electrons
oxygen is added
oxygen is lost

Answers

Answer: Option (a) is the correct answer.

Explanation:

A reduction-half reaction is defined as the reaction in which there occurs gain of one or more number of electrons by a specie or element.

Or, in a reduction-half reaction there occurs loss of oxygen if it is present in a reaction.

But in a reduction-half reaction loss of electrons will always take place.

For example, $CuO + Mg \rightarrow Cu + MgO$

Reduction-half reaction: $Cu^(2+) + 2e^(-) \rightarrow Cu$

So here, oxidation state of copper is changing from +2 to 0. Also, loss of oxygen is occurring in the reaction equation.

Oxidation-half reaction: $Mg \rightarrow Mg^(2+) + 2e^(-)$

Thus, we can conclude that in a reduction half-reaction elements gain electrons.

The answer is elements gain electrons. Oxidation reduction is elements lose electrons. And oxygen is added/lost can be a type of oxidation/reduction reaction.

When an individual has an energy surplus, he or she stores the extra energy as: A. nucleic acids. B. lipids. C. None of the answer options is correct. D. carbohydrates. E. proteins.

Answers

Answer: B. lipids

Explanation:

When an individual has an energy surplus, the extra energy is stored in the body as lipids. Lipids are used for energy in the long term

N2O4(g) 2NO2(g) Which of the following represents the Keq value? 0.18 0.0067 0.131 0.0046

Answers

Keq= [NO2]^2/[N2O4] at equilibrium. Do you see how I got that formula?

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