(B)The mean of matches won is more than the median of matches won.
(C)Most of the participants won many matches, but there were some participants who won very few matches compared to the others.
(D)Most of the participants won very few matches, but there were some participants who won many matches compared to the others.
Answer:
(C)- Most of the participants won many matches, but there were some participants who won very few matches compared to the others.
Step-by-step explanation:
The Box plot isshifted to the right this means it is right-skewed data thus left tail is much longer than right tail. Hence, Option (C) is correct.
Option (A) means than neither right tail is longer nor left, the box will remain in middle only. So it is incorrect.
Option (B) is incorrect because Box Plot doesn't give us idea about mean.
Option (D) is also not correct because if this happened then box will shifted to the left
Using 1 can of paint 3 walls can be painted.
The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units.
For example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.
12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.
As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.
This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.
Dan painted 3/4 of a wall using 1/4 of a can of paint.
So, 1/4 can used = 3/4 of wall
Then, in one can the amount of wall painted
= 3/4 x 4/1
= 3 walls.
Learn more about Unitary Method here:
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−40 < 5 over 9 (F − 32) < 125; −40 < F < 257
−40 < 5 over 9 (F − 32); −40 < F
5 over 9 (F − 32) < 125; F < 257
Answer; −40 < 5 over 9 (F − 32) < 125; −40 < F < 257
Answer:
Step-by-step explanation:
Given
Volume of spherical Balloon is given by
(a)Rate of change of balloon w.r.t to radius is given by
at
(b)Using the rate Volume change when radius increases from r=9 in. to r=9.5 in.
Answer:
see below
Step-by-step explanation:
We have to assume that the question is referring to the doubly-shaded length, the one that is 10 bright blue units long.
You can read the overall length of the shaded area as 5/4, from the markings.
For the next part, you need to count the number of units that are shaded bright blue (10) and the number that are shaded blue overall (15). As a fraction of those shaded blue overall, the ones shaded bright blue are 10/15 = 2/3.
So, the length shaded bright blue is 2/3 of the overall length of 5/4. It is represented by the product ...