Shanna attends school for 1 week longer than 3/4 of the year. How many weeks in a year dies Shanna attend school ?

Answers

Answer 1
Answer:

Answer:

40 weeks

Step-by-step explanation:

We must find the relationship between weeks and years. Given that 52 weeks make a year, it means that 3/4 of the year would be equivalent to

= 3/4 * 52 weeks

= 39 weeks

Since we know that Shanna attends school for 1 week longer than 3/4 of the year, it means she added school for 1 week more than 39 weeks. The number of weeks she attended school is thus

= 39 +1

= 40 weeks

Answer 2
Answer: 3/4 of a year consist of three months per quarter

so 3/4 of a year is 9 months

each month have 4 weeks

multiply 9x4 to get 36, which is the number of weks there is in 3/4 of a year 
now add one week since Shanna attended one week longer 

and now you get 37 weeks Shanna attended school

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Miranda wants to give her 14-year-old daughter $20,000 when she turns 18. How much does she need to put in the bank now if the interest rate is 10 percent per year?

Answers

20,000 = P ( 1 + 0.1 )^4
20,000 = P * 1.1^4
20,000 = P * 1.461
P = 20,000 : 1.461 ≈ $13,689.25
Answer: Miranda needs to put now in the bank $13,689.25 

Which of the following is the equation of a line that passes through the point (1,4) and is parallel to the x-axis?A. x = 4
B. y = 4
C. y = 1
D. x = 1

Answers

A line parallel to the x-axis is y = constant

In this case, to pass through (1,4), y = 4.

Then the answer is option B.


24 21 is 60% of what number?

Answers

Answer:

could u explain it better

Answer: either I don't remember if you use the % or the number ok

Hope this helps

2421 × 60 = 145260

2421 × 60% = 1452.6

Step-by-step explanation:

2(3x+4y)=4x+12y
 solve

Answers

6x + 8y = 4x + 12y
6x - 4x = 12y - 8y
2x =  4y
x = 2y
is it x=2y?
Because  6x+8y=4x+12y
=>2x+8y=12y
and 2x=4y, so x=2y                         

How do I solve for x in the equation 5^x=3125? Also in 5^x=1/125, 9^x=243, 4^x=1/32, and 3*2^x=96?

Answers

remember
if x^m=x^n and x=x, m=n
also
x^-m=1/(x^m)
(x^m)^n=x^(mn)

try to match bases

5^x=3125
5^x=5^5
x=5

5^x=1/125
1/125=1/(5^3)=5^-3
5^x=5^-3
x=-3


9^x=234
3^(2x)=3^5
2x=5
x=2.5


4^x=1/32
1/32=1/(2^5)=2^-5
2^(2x)=2^-5
2x=-5
x=-2.5


3*2^x=96
first divide both sides by 3
2^x=32
2^x=2^5
x=5




5^x=3125
x=5

5^x=1/125
x=-3


9^x=234
x=2.5

4^x=1/32
x=-2.5

3*2^x=96
x=5

5^x=1/125

Take log of both sides

log(5^x)=log(1/125)

x*(log(5))= log(1/125)

x= log(1/125)/ log(25)

x=-3


9^x= 243

Take log of both sides


log(9^x)= log(243)

x*(log(9))= log(243)

x= log(243)/ log(9)

x= 2.5


4^x= 1/32

Take log of

log(4^x)=log(1/32)

x*(log(4))=log(1/32)

x= log(1/32)/log(4)

x= -2.5


3*2^x=96

Divide both sides by 3 so we can make it more simply

3(2^x)/3= 96/3

2^x= 32

Take log of

log(2^X)=log(32)

x(log(2))= log(32)

x= log(32)/log(2)

x=5


As you can see, I only used a simple way for all of them.


I hope that's help:0

One-fifth of a swarm of bees is resting on a kadaba bush and a third on a silindha bush; three timesthe difference between these two numbers is on a kutaja, and a single bee has flown off in the breeze drawn by the odor of a jasmine and a pandam. Tell me, beautiful maiden, how many bees are there?

Answers

Answer:

There are 15 bees.

Step-by-step explanation:

Let's call x the total number of bees. There is one fifth of that in one bush, which can be written as:

(1)/(5)x

there is one third on another, which is:

(1)/(3) x

the other one has three times the difference between the previous two:

3((1)/(3)x-(1)/(5)x)

So, if we add those three quantities plus one single bee that flew away, it all should add up to the total number of bees, which is x. So:

3((1)/(3)x-(1)/(5)x)+(1)/(3)x+(1)/(5)x+1=x

We will solve for x:

(3)/(3)x-(3)/(5)x+(1)/(3)x+(1)/(5)x+1=x

(15)/(15)x-(9)/(15)x+(5)/(15)x+(3)/(15)x+1=x

(14)/(15)x+1=x

We will move the positive x on the right of the equal as a negative one to the left:

(14)/(15)x-x+1=0

(14)/(15)x-(15)/(15)x+1=0

-(1)/(15)x+1=0

1=(1)/(15)x

15=x

We can prove this answer by replacing in the original equation:

3((1)/(3)15-(1)/(5)15)+(1)/(3)15+(1)/(5)15+1

3(5-3)+5+3+1

3(2)+9

6+9=15