A swimming pool is 20 meters long and 12 meters wide the bottom of the pool is slanted so that the water depth is 1.3 at theshallow end and 4 meters deep at the deep end find the angle of depression of the bottom of the pool

Answers

Answer 1

Answer: Find the angle of depression of a swimming pool
=> has 20 meters long
=> has 12 meters wide
=> it is slanted at 1.3 meters depth
=> has 4 meters at the deep end.
Now, let’s start finding the tan:
=> tan x = oop/adj
=> tan x = 4 -1.3/20
=> 0.135
=> x = tan-1 0.135, this is equals to approximately 7.69 degrees.
Thus the angle of depression is approximately 7.69 degrees.

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HELPPPP PLEASE!!!!!!

Answers

Answer:

y = 20

Step-by-step explanation:

line RPN = 180 = 4y - 10 + 90 + y

180 - 90 + 10= 5y

100 = 5y

y = 100/5

y = 20

A, B & C form a triangle where ∠ BAC = 90°. AB = 13.5 mm and CA = 3.2 mm. Find the length of BC, giving your answer rounded to 1 DP.

Answers

Answer:

13.9

Step-by-step explanation:

Use Pythagorean Theorem:

Both of the lengths given are the legs,

13.5^2 + 3.2^2 = c^2

182.25 + 10.24 = c^2

192.49 = c^2

13.87 = c

F(x)= 2x+1/3x-4 H(x)=3x³-7EvaluateF(x)–¹And Fh(4)

Answers

$f(x) = (2x + 1)/(3x - 4)$
h(x) = 3x³ - 7

$f(x) = (2x + 1)/(3x - 4)$
$y = (2x + 1)/(3x - 4)$
$y(3x - 4) = (3x - 4)((2x + 1)/(3x - 4))$
$y(3x) - y(4) = 2x + 1$
$3xy - 4y = 2x + 1$
$3xy - 2x = 4y + 1$
$x(3y) - x(2) = 4y + 1$
$x(3y - 2) = 4y + 1$
$(x(3y - 2))/(3y - 2) = (4y + 1)/(3y - 2)$
$x = (4y + 1)/(3y - 2)$
$y = (4x + 1)/(3x - 2)$
$f^(-1)(x) = (4x + 1)/(3x - 2)$

f(h(4)) = 3x³ - 7
f(h(4)) = 3(4)³ - 7
f(h(4)) = 3(64) - 7
f(h(4)) = 192 - 7
f(h(4)) = 185

$f^(-1)(x) - f(h(4)) =(4x + 1)/(3x - 2) - 185$
$f^(-1)(x) - f(h(4)) =(4x + 1)/(3x - 2) = (185(3x - 2))/(3x - 2)$
$f^(1)(x) - f(h(4)) =(4x + 1)/(3x - 2) = (555x - 370)/(3x - 2)$
$f^(-1)(x) - f(h(4)) =((4x + 1) - (555x - 370))/(3x - 2)$
$\f^(-1)(x) - f(h(4)) =((4x - 555x) + (1 - 370))/(3x - 2)$
$f^(-1)(x) - f(h(4)) =(-551x - 369)/(3x - 2)$

What must be added to
2x² - 3 xy + 5yz to get x² - xy + y²

Answers

Answer:

-x² + y² + 2xy - 5yz

Step-by-step explanation:

"A" must be added to first expression to get the second one:

A + 2x² - 3 xy + 5yz = x² - xy + y²
A = ?

------------------------

A = x² - xy + y² - (2x² - 3 xy + 5yz) =
x² - xy + y² - 2x² + 3 xy - 5yz=
-x² + y² + 2xy - 5yz

a delivery truck traveled 324 miles on 18 gallons of gas how far can be traveled on 41 gallons of gas?

Answers

324 miles divided by 18 gallons = 18 miles per gallon (mpg)

Therefore, 41 gallons x 18 mpg = 738

Final answer:

The delivery truck can travel 738 miles on 41 gallons of gas, assuming it maintains the same fuel efficiency. This is calculated by first finding the mileage per gallon (miles driven divided by gallons used), then multiplying that by the number of gallons.

Explanation:

The situation given can be solved by using unit rate or sometimes referred to as proportion. The delivery truck traveled 324 miles on 18 gallons of gas. We'll first find out the mileage per gallon and then use that to compute how far it could go on 41 gallons.

First, we divide the total miles by the total gallons to get miles per gallon: 324 miles / 18 gallons = 18 miles per gallon.
Then, multiplies the miles per gallon by the quantity of gallons you want to know: 18 miles per gallon * 41 gallons = 738 miles.

So, a delivery truck that traveled 324 miles on 18 gallons of gas could travel 738 miles on 41 gallons of gas, assuming the truck maintains the same fuel efficiency.

Learn more about Proportion here:

brainly.com/question/32430980

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If 2=6 3=12 4=20 5=30 6=42 then 9=?

Answers

$2=6\n \n 2\cdot (2+1)=6\n \n 3=12\n \n 3\cdot (3+1)\cdot 12\n \n 4=20\n \n 4\cdot (4+1)=20\n \n 5=30\n \n 5\cdot (5+1)=30\n \n 6\cdot (6+1)=42\n \n x\cdot (x+1)={ x }^( 2 )+x\n \n for\quad x=9\n \n 9\cdot (9+1)=\quad { 9 }^( 2 )+9\quad =\quad 81+9\quad =\quad 90$

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