MATHEMATICS HIGH SCHOOL

How do I apply the change of base formula to y=log (sub 3) x

Answers

Answer 1
Answer: y=\log_3x \Leftrightarrow y=(\log_cx)/(\log_c3)\text{ where } c\in \mathbb{R}_+\setminus\{1\}

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Which set of ordered pairs has point symmetry with respect to the origin (0,0) 1- (-12,5), (-5,12)
2- (-12,5), (12,-5)
3- (-12,5), (-12,-5)
4- (-12,5), (12,5)

Answers

(x;\ y)\xrightarrow {S_((0;0))}(-x;-y)\n\n(-12;\ 5)\xrightarrow{S_((0;0))}(12;-5)\n\nAnswer:2

Change 12.39% to a decimal

Answers


To change a number to percent, move the
decimal point 2 places that way ==> .

To change a percent to a number, move the
decimal point 2 places this way <== .

               12.39%  =  0.1239 .

Answer:

The answar is 0.1239

Step-by-step explanation:

The percent sign tells un to divide 12.39 by a hundred(12.39/100). Divide 12.39 by hundred and you get 0.1239

Which one is it please hurry. Thank you

Answers

Answer: I think it’s A if I am incorrect I am very sorry

Step-by-step explanation:
I think it’s A but sorry if I’m wrong

Solve for x. Evaluate and round your answer to 1 decimal place (tenths place). 10x=3588

Answers

Answer:

x =3.6

Step-by-step explanation:

10^x=3588\n\mathrm{If\:}f\left(x\right)=g\left(x\right)\mathrm{,\:then\:}\ln \left(f\left(x\right)\right)=\ln \left(g\left(x\right)\right)\n\ln \left(10^x\right)=\ln \left(3588\right)\nx\ln \left(10\right)=\ln \left(3588\right)\n\mathrm{Solve\:}\:x\ln \left(10\right)=\ln \left(3588\right):\quad x=(\ln \left(3588\right))/(\ln \left(10\right))\n\n= 3.55485\n=3.6

Simple interest.

2700=2200(1+r)^5

Answers

solve your equation step-by-step.

2700=2200(1+r)^5

Flip the equation.

2200(r+1)^5 = 2700

Divide both sides by 2200.

2200(r+1)^5 / 2200 = 2700 / 2200

(r+1)^5=27/22

Solve Exponent.

(r+1)^5=27/22

((r+1)5) ^1/5 = (27/22)^1/5 (Raise both sides to power)

r+1=1.041809

r+1−1=1.041809−1(Subtract 1 from both sides)

r = 0.041809

Check answers. (Plug them in to make sure they work.)

r = 0.041809 (Works in original equation)
2700=2200(r+1)^5\n(27)/(22)=(r+1)^5\n\sqrt[5]{(27)/(22)}=\sqrt[5]{(r+1)^5}\n(27)/(22)^(1)/(5)=r+1\nr=(27)/(22)^(0.2)-1\nr=1.0418-1\nr=0.0418

r = 0.0418

If a car covers 102 km in 6.8 liters of petrol , how much distance will it cover with 24.2 liters of petrol

Answers

x-distance\n\nFrom\ proportion:\n\n6.8\ \ \ -\ \ \ 102\n24.2\ \ -\ \ \ x\n\n6.8x=2468.4\ \ \ \ \ \ |:6.8\nx=363\n\nThis\ car\ can\ cover\ 363\ miles
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