At what location in a circuit is the electrical potential energy the greatest

Answers

Answer 1

Answer:
It's not the potential energy. It's just the potential.

It's greatest at the positive terminal of the battery or power supply.

Related Questions

A block of metal initially at 25°C is submerged in water initially at 75°C in a coffee cup. Which of the following is true? a. The final temperature of the coffee cup will be less than 20°C. b. The final temperature of the coffee cup will be higher than 25°C but less than 75°C. c. The final temperature of the coffee cup will be more than 80°C. d. The final temperature of the coffee cup will be 80°C.
Somebody plz answer these 5 only thanks!!!Will mark as brainliest:D
A 25-gram paper cup falls from rest off the edgeof a tabletop 0.90 meter above the floor. If thecup has 0.20 joule of kinetic energy when it hitsthe floor, what is the total amount of energyconverted into internal (thermal) energy duringthe cup’s fall?(1) 0.02 J (3) 2.2 J(2) 0.22 J (4) 220 J
Sound waves in air are a series ofa. periodic disturbances. b. periodic condensations and rarefactions. c. high- and low-pressure regions. d. all of the above E. none of the above
The mass of a stroller and the child it carries is 23.7 kg. A man pushes the stroller with a force of 142 N at an angle of 38.0° to the vertical. The stroller experiences a friction force of 24.0 N due to the brake accidentally being on. What is the stroller's acceleration forward?A. 5.99 m/s2 B. 3.90 m/s2 C. 2.68 m/s2 D. 4.98 m/s2

Two boxes of masses m and 3m are stacked. The surface between the more massive box and the horizontal surface is smooth and the surface between the boxes is rough. If the less massive box does not slide on the more massive box, what is the static friction force on the less massive box?

Answers

Answer:

The friction coefficient is $(F)/(4mg)$ .

Explanation:

Given that,

Mass of first box = m

Mass of second box = 3m

Let the static friction force on the less massive box is $F_(1)$ .

Since the small box is not slide, they have the same acceleration.

We need to calculate the acceleration

Using balance equation

$F-F_(1)=3ma$ ....(I)

$F_(1)=ma$ ....(II)

Adding both the equation

$F=4 ma$

$a=(F)/(4m)$

Put the value of a in equation (II)

$F_(1)=m*(F)/(4m)$

$F_(1)=(F)/(4)$

We need to calculate the friction coefficient

Using formula of frictional force

$F=\mu mg$

$\mu=(F)/(4mg)$

Hence, The friction coefficient is $(F)/(4mg)$ .

If the less massive box does not slide on the more massive box, the static friction force on the less massive box is (D) F/4.
F = ma
F=(3m+m)a
a = F/4m

Here are the following choices:
A) F
B) F/2
C) F/3
D) F/4

A 24 kg box is being pulled across a floor by a horizontal rope. What is the Normal force?