Which equation represents an exponential function that passes through the point (2, 36)?f(x) = 4(3)x

f(x) = 4(x)3

f(x) = 6(3)x

f(x) = 6(x)3

Answers

Answer 1
Answer:

Answer:

The exponential function that passes through (2,36) is:

f(x)=4* 3^x.

Step-by-step explanation:

We are asked to find which function passes through the point (2,36).

i.e. we will put the input value '2' in the following given functions and check which gives the output value as '36'.

1)

f(x)=4* 3^x

now we put x=2.

f(2)=4* 3^2\n\nf(2)=4* 9\n\nf(2)=36

hence option 1 is correct.

2)

f(x)=4* x^3

Now we put x=2.

f(2)=4* 2^3\n\nf(2)=4* 8\n\nf(2)=32

Hence, option 2 is incorrect.

3)

f(x)=6* 3^x

Now we put x=2

f(2)=6* 3^2\n\nf(2)=6* 9\n\nf(x)=54

Hence, option 3 is incorrect.

4)

f(x)=6* x^3

Now we put x=2.

f(2)=6* 2^3\n\nf(2)=6* 8\n\nf(2)=48

Hence, option 4 is incorrect.

Hence, option 1) is correct.

i.e. The exponential function that passes through (2,36) is:

f(x)=4* 3^x

Answer 2
Answer:

Answer:

Option A. is the answer.

Step-by-step explanation:

In this question we can get the correct option by plugging in the coordinates of point (2, 36) in the functions given in all options.

Option A.

f(x)=4(3)^(x)

For (2, 36),

36=4(3)^(2)

36 = 4×9

36 = 36

It's true so the function passes through the point (2, 36).

Option B.

f(x)=4(x)^(3)

For, (2, 36)

36=4(2)^(3)

36 = 4×8

36 = 32

Which is not true.

Therefore, option B is not the answer.

Option C.

f(x)=6(3)^(x)

For(2, 36)

36=6(3)^(2)

36 = 6×9

36 = 54

It's not true.

Therefore, option C is not the nswer.

Option D.

f(x)=6(x)^(3)

For (2, 36),

36=6(2)^(3)

36 = 6×9

36 = 54

Which is not true.

Therefore, option D is not the answer.


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Answers

Answer:

Mr.Smith paid $29.4.

Step-by-step explanation:

Mr.Smith paid $24.5 plus additional 20% of $24.5, and to figure out the total amount that he paid, we need to know what is 20% of $24.50.

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The work of a student to solve a set of equations is shown:Equation 1: m = 8 + 2n
Equation 2: 3m = 4 + 4n


Step 1:
−3(m) = −3(8 + 2n) [Equation 1 is multiplied by −3.]
3m = 4 + 4n [Equation 2]

Step 2:
−3m = −24 − 6n [Equation 1 in Step 1 is simplified.]
3m = 4 + 4n [Equation 2]

Step 3:
−3m + 3m = −24 − 6n + 4n [Equations in Step 2 are added.]

Step 4:
0 = −24 − 2n

Step 5:
n = −12

In which step did the student first make an error?

Step 4

Step 3

Step 2

Step 1

Answers

The student first makes an error in the Step 3 where he addsequations in Step 2 to use the elimination method.

What is the elimination method?

To create an equation in one variable using the elimination method, you can either add or subtract the equations. To eliminate a variable, add the equations when the coefficients of one variable are in opposition, and subtract the equations when the coefficients of one variable are in equality.

How to solve this problem?

Notice that the student uses the elimination method to solve the equations. In Step 1, he makes the coefficients of m equal in both equations. In Step 2, he simplifies the previous step. In Step 3, he wants to add both equations to create an equation in one variable. But He forgot to add 4 of Equation 2. It's a mistake.

Therefore the student first makes an error in the Step 3 where he addsequations in Step 2 to use the elimination method.

Know more about the elimination method here -

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3. this is because you added un equal amounts to both sides.

Many bicycles have 26 inch diameter wheels. The low gear attached to your pedals has a radius of 2.2 inches. The low rear gear, driven by the chain attached to the front gear, has a diameter of 3 inches. How far does the bike travel in one rotation of the pedals, i.e. the front gear revolves once.

Answers

The circumference is 'Pi' times diameter.

So one rotation of the pedals will cause the front chain drive to complete one full turn, so it will move the chain the same distance as it's circumference.

So it will move the chain 
 (2.2 Pi )inches. Then the back drive has a circumference of  3pi inches, but it only turns 2.2pi inches. So it turns 2.2pi/3pi = 11/15 of a full rotation. Since the wheel turns at the same rate as the back chain drive, the wheel will turn  11/15 of a full turn as well.

And since the back wheel is 26 inches in diameter, it's circumference is 26pi
 inches. If it turned a full rotation, it would go this distance along the ground, but it is only going  11/15 of this distance, so it is going (11/15)x 26pi =(286/15)pi inches. Or approximately 59.8997 inches.

What is the integer for 3 people join?

Answers

The integer of 3 is negative (-3). Glad to help

6. The lengths of two sides of a triangle are 5 cm and 8 cm. Between what two measuresshould the length of the third side fall

Answers

Answer:

triangle inequality: the sum of the length of two sides of a triangle must always be greater than the length of the third side.

we know 2 sides whose sum = 5+8 = 13cm

the 3rd side must be <13 included

the length of the third side must be less than 13 cm, i.e. between 1 and 13 (it cannot be equal to 0 because in this case it does not exist)

Red kangaroos can reach speeds up to 50 feet per second. Use the linear graph at the left to answer the questions. What is the change in y-values from Point A to Point B? What is the change in x-values from Point A to Point B? What is the rate of change of the linear function in feet per second?

Answers

we are given points A and B

A=(3,150)

B=(4,200)

we can find points

x1=3 , y1=150

x2=4 , y2=200

(a)

the change in y-values from Point A to Point B is

=y_2-y_1

now, we can plug values

=200-150

=50feet...........Answer

(b)

the change in x-values from Point A to Point B is

=x_2-x_1

now, we can plug values

=4-3

=1second...........Answer

(c)

the rate of change of the linear function in feet per second is

=(y_2-y_1)/(x_2-x_1)

now, we can plug values

=(50)/(1)feet/sec

=50feet/sec.................Answer


The straight line graph indicates that rate of change of the distance traveled with time by the red kangaroo is a constant

  • The change in y-values from point A to point B is 50 feet.
  • The change in x-values from point A to point B is 1 second.
  • The rate of change of the linear function is 50 feet per second.

Reasons:

The y-values at point A = 150 feet

The y-values at point B = 200 feet

Change in y-values from point A to point B, Δy is given as follows;

Δy = y-values at point B - y-values at point A

Δy = 200 feet - 150 feet = 50 feet

Change in y-values from point A to point B, Δy = 50 feet

The x-values at point A = 3 seconds

The x-values at point B = 4 seconds

Change in x-values from point A to point B, Δx is given as follows;

Δx = x-values at point B - x-values at point A

Δx = 4 seconds - 3 seconds= 1 second

Change in x-values from point A to point B, Δx = 1 second.

The rate of change of the linear function is (\Delta y)/(\Delta x), therefore, we have;

Rate \ of \  change \  of \  the  \ linear  \ function = (\Delta y)/(\Delta x) = (50 \ feet)/(1 \ second) = 50 \ feet \ per \ second

Learn more here:

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