discuss the relationship between the size and weight of an object and the amount of friction that is present

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Answer 1

Answer: As both size and weight of an object increase, so will the amount of friction. The bigger size an object is, the more surface area it will have, and the heavier an object is, the more pressure it will place on something else. Both these factors lead to increased friction.

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As the temperature of a gas decreases, what change occurs in the amount of kinetic energy?

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Solid particles have the least amount of energy, and gas particles have the greatest amount of energy. The temperature of a substance is a measure of the average kinetic energy of the particles. A change in phase may occur when the energy of the particles is changed.

an, 13 Students set up two environments see which one best supports growth of hibiscus flowers. One environment is created as a desert, using The plant is exposed to high temperatures. The a tropical other environment is create exposing the forest, using soil and the plant to high temperatures. What is variable used in the investigation? 5.2(A) CA The temperature The environmen The type of flower The amount of sunlight in D

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B. The Enviroment. The Soil and Humidity are differant. They both have high tematures, they use the same flowers in both, Hibiscus. The tropical environent should help the Hiviscus grow better.

Define chemical change and give an example

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Definition-A formation of new chemical substances.
Example- Sugar undergoes a chemical change when it is cooked to make caramel. :3

Hope I helped! Sorry if it's bad.

Chemical changes are the chemical properties associated with a specific matter.

Examples include toxicity, reactivity, stability, flammability, etc.

A 93-L sample of dry air is cooled from 145 oC to -22 oC at a constant pressure of 2.85 atmospheres). What is the final volume?

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Answer:

56 L

Explanation:

We're dealing with a gas in this problem. We may, therefore, apply the ideal gas law for this problem:

$pV = nRT$

We now that we have a constant pressure. Besides, R, the ideal gas law constant, is also a constant number. Let's rearrange the equation so that we have all constant variables on the right and all changing variables on the left:

$(V)/(T) = (nR)/(p) = const$