MATHEMATICS HIGH SCHOOL

Where would the square root of 130 be located on the number line

Answers

Answer 1
Answer: √(130)=\boxed{11.40175425099138}\ it\ would\ be\ located\ in\ between\ 11\ and\ 12.

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Log(8)a/2. Expand the logarithmic expression.

Answers

log(8a/2) = log8 + log a - log 2

The simple rules here are: If logarithms (as in this case) have same basis, factors inside logarithm can be written as sum of logarithms or difference between logarithms (first if factors are multiplying and second if factors are dividing)

What is the slope of any line parallel to the line8x + 9y = 3 in the standard (x,y) coordinate plane?

Answers

The slope of any line parallel to that line is -8/9
parallel -8/9 hope that helpd

Evaluate a + b for a = 2 and b = 3.
1
5
6

Answers


a = 2
b = 3.156

   (a + b)  =  (2) + (3.156)  =  5.156
just add if it were normal 2 + 3 = 5 and just out the .156

answer is 5.156

Which graph best represents the following expression?
is my answer correct?

Answers

abs(x - 1) > 2

Result one

x - 1 > 2

x > 2 + 1

x > 3 but it does not include 3 so you were right about that.

x - 1 < - 2

x < -2 + 1

x < - 1

Looks like D to me.

Note these questions when they work will give you 2 answers. The second one is always a sign switch.

Again try 2 values. Try 0 and - 2 for x

I do not understand how to do this. What should I notice? "Explain why this makes sense" ?

Answers

I am sorry I do not understand the question of what  it is asking.

Solve the following equation. Remember to check for extraneous solutions 7/(b+3) + 5/(b-3) = (10b-2)/(b²-9).

Answers

Answer:

b= 2 is the solution for the given equation.

Step-by-step explanation:

Here, the given expression is:

(7)/((b+3))  + (5)/((b-3)) = (10b -2)/((b^(2) -9))

Simplifying Left side, we get

(7)/((b+3))  + (5)/((b-3))

= (7(b-3) + 5(b+3))/((b+3)(b-3))

Also, by ALGEBARIC IDENTITY:x^(2) -y^(2) = (x+y)(x-y)

So, (b+3)(b-3) = b^(2) -9

So, LHS becomes (7(b-3) + 5(b+3))/(b^(2) -9)

Compare both Left side, Right side we get

(7(b-3) + 5(b+3))/(b^(2) -9) =   (10b -2)/((b^(2) -9))

or, 7(b-3) + 5(b+3) = 10b -2

⇒ 7b - 21 + 5b + 15 = 10b -2

or, 12b - 10b = 6-2

or, 2b = 4 ⇒ b = 4/2 = 2

⇒ b= 2 is the solution for the given equation.
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