How many joules are needed to warm 45.0 grams of water from 30.0 degrees C to 75.0 degrees C?

Answers

Answer 1
Answer:

Answer : The amount of heat needed are, 8464.5 J

Explanation :

Formula used :

q=m* c* (T_(final)-T_(initial))

where,

q = heat gained = ?

m = mass of water = 45.0 g

c = specific heat of water = 4.18J/g^oC

T_(final) = final temperature = 75.0^oC

T_(initial) = initial temperature = 30.0^oC

Now put all the given values in the above formula, we get:

q=45.0g* 4.18J/g^oC* (75.0-30.0)^oC

q=8464.5J

Thus, the amount of heat needed are, 8464.5 J

Answer 2
Answer: q=m x Cp x ∆T

m is the mass of the water, Cp is the specific heat of water and ∆T is the change in temperature of the water (final-initial temperature). q is the energy involved in the reaction, measured in joules. 

q=(45.0) x (4.184 Jg^-1/°C^-1) x (45°C)
q=8472.6 Joules

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Answers

Explanation:

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Answers

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In chemistry class, Allen determined the effectiveness of various metals in releasing hydrogen gas from hydrochloric acid. Several weeks later, Allen read that a utilities company was burying lead next to iron pipes to prevent rusting. Allen hypothesized that less rusting would occur with the more active metals. He placed the following into 4 separate beakers of water: (a) 1 iron nail, (b) 1 iron nail wrapped with an aluminum strip, (c) 1 iron nail wrapped with a magnesium strip, and (d) 1 iron nail wrapped with a lead strip. He used the same amount of water, equal amounts (mass) of the metals, and the same type of iron nails. At the end of 5 days, he rated the amount of rusting as small, moderate, or large. He also recorded the color of the water. What is the independent variable?a) the amount of water
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Answers

Answer:

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Explanation:

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Answers

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Answers

it's simple.
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Answers

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