Will amplitude change if the pitch gets louder

Answers

Answer 1

Answer:
The wording of the question is fundamentally defective,
and the question is therefore unanswerable. (But I'll
gladly accept your points anyway.)

"Amplitude" is the origin of the subjective impression of loudness.
"Pitch" is not.

There is no such concept as the 'loudness' of a pitch.

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What is the term used to describe the energy needed to get a reaction started

Answers

Activation Energy is the amount of energy needed to get a reaction started.

What is true about discipline

Answers

discipline will inprove your profoments - mithbusters

Determine the change in velocity of a car that starts at rest and has a final velocity of 20m/s north

Answers

The change in velocity of a car that starts at rest and has a final velocity of 20 meters/second north would be 20 meters/second.

What is acceleration?

The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².

As given in the problem we have to find the change in velocity of a car that starts at rest and has a final velocity of 20m/s north,

the final velocity of the car = 20 meters/second north

Change in the velocity = final velocity - initial velocity

=20 - 0

= 20 meter/second

Thus, the change in the velocity would be 20 meters/second

Learn more about acceleration from here

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Im not too sure if I just dont understand but if something starts at rest, its not moving so Vi would be 0m/s and if the final velocity would be 20m/s North. Than the change would be 20m/s, its not asking for displacment so you don't need direction. I got my answer from doing Change in Velocity = Final velocity - Initial velocity

Ryan left the science museum and drove south at 53 km/h. How far has he traveled after 8 minutes

Answers

Answer:

7 km

Explanation:

53 km in 1 hour/ 60 minutes. .89 km a minute.

The car salesman tells you that the car can go from a stopped position to 60 miles per hour in 6 seconds. He is giving you the car's rate of

Answers

he is giving you the car rate speed

Driving home from school one day, you spot a ball rolling out into the street (Figure 5-21). You brake for 1.20 s, slowing your 950-kg car from 16.0 m/s to 9.50 m/s.a) What was the average force exerted on your car during braking?
b) How far did you travel while braking?

Answers

a ) v = v o + a t ( the acceleration will be negative )
9.50 = 16.0 + a * 1.2
a * 1.2 = -16.0 + 9.50
a * 1.2 = - 6.5
a = - 6.5 : 1.2
a = - 5.4167 m/s²
F = m * a = 950 kg * 5.4167 m/s²
F = 5,145.8 N ( the average force exerted on a car during braking )
b ) d = v o - a t² / 2
d = 16.0 * 1.2 - ( 5.4167 * 1.2² / 2 ) =
= 19.20 - 3.90 = 15.30 m

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