An average person can reach a maximum height of about 60 cm when jumping straight up from a crouched position. during the jump itself, the person's body from the knees up typically rises a distance of around 50 cm. to keep the calculations simple and yet get a reasonable result, assume that the entire body rises this much during the jump.

Answers

Answer 1

Answer:

Final answer:

The question is related to Physics and deals with kinematic equations. With the supplied information, one can calculate elements such as velocity or applied force in the jump.

Explanation:

The subject of the question pertains to the field of Physics, specifically the area of kinematic equations which deal with the motion of objects. The provided information in the question pertains to the rise of a person's body during a jump. Given the average height of 60cm that a person typically attains and the approximate rise of the body from the knees up being 50cm, these figures can be used in a Physics context to determine different factors of the jump such as velocity or force applied.

For example, using the equation of motion (height = 0.5 * gravity * time^2) where gravity is around 9.8 m/s^2, you can calculate the time taken to reach maximum height. We can calculate this using the initial velocity combined with the gravity force. Furthermore, the force applied can be calculated knowing the mass of the person and the acceleration (which is the initial velocity divided by the time).

Learn more about Kinematic Equations here:

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When the orientation of the Moon is just right, the high tides from the lunar bulge and the solar bulge line up, causing a very strong "Spring tide" --- an especially high high tide and a very low low tide. At what Moon phase(s) will you see a Spring tide?

Answers

Answer:

The correct answer is we see a Spring tide just after a full moon or no moon phase i.e. twice each lunar month.

Explanation:

A spring tide is popularly known as the "King Tide". As the name suggest, it has nothing to do with the season of spring. It gets its name from the idea of "springing forth". During a spring tide, the tidal range i.e. the difference between high and low water, is maximum. This happens when sun and the moon are on the same side of the earth (new moon) as well as when sun and moon are on the opposite side of the earth (full moon).

A spring gains 2.34 joules of elastic potentialenergy as it is compressed 0.250 meter from its
equilibrium position. What is the spring constant
of this spring?
(1) 9.36 N/m (3) 37.4 N/m
(2) 18.7 N/m (4) 74.9 N/m

Answers

The correct answer to the question is: 4) 74.9 N/m.

EXPLANATION:

As per the question, the stretched length of the spring is given as x = 0.250 m.

The potential energy gained by the spring is given as 2.34 joules.

We are asked to calculate the spring constant of the spring.

The potential energy gained by the spring is nothing else than the elastic potential energy .

The elastic potential energy of the spring is calculated as -

Potential energy P.E = $(1)/(2)kx^2$

⇒k = $(2P.E)/(x^2)$

= $(2* 2.34)/((0.250)^2)\ N/m$

= 74.88 N/m

= 74.9 N/m. [ans]

Hence, the force constant of the spring is 74.9 N/m.

Elastic energy equals 1/2 k(spring constant) *Δx^2(change in position) so you set the energy of the spring equal to the 1/2kΔx^2 and solve for K. 2.34=1/2k(.250)^2 which gives you a spring constant of 74.9 N/m.

An object is located 51 millimeters from a diverging lens. The object has a height of 13 millimeters and the image height is 3.5 millimeters. How far in front of the lens is the image located? A. 1.12 millimeters
B. 13.7 millimeters
C. 51 millimeters
D. 189 millimeters

Answers

The correct answer is letter B. 13.7 millimeters. An object is located 51 millimeters from a diverging lens. The object has a height of 13 millimeters and the image height is 3.5 millimeters.

mi / mo = hi / ho
mi / 51 = 3.5 /13
178.5 = 13 mi
mi = 13.7 mm

In a transverse wave that travels through a medium, the molecules of the medium vibrateA. at right angles to the direction in which the wave travels.
B. at twice the velocity of the molecules in a longitudinal wave.
C. with smaller amplitudes than the molecules in a longitudinal wave.
D. in the direction in which the wave travels

Answers

So we wan't to know how the molecules of the medium vibrate when a transverse wave propagates trough that medium. A transverse wave is a wave whos oscilations are perpendicular to the direction of it's propagation. So the molecules in a medium will vibrate perpendicular to the direction of propagation of the wave. So if the wave is moving in the x-direction, the molecules will vibrate in the y-z plane. The correct answer is A. at right angles to the direction in which the wave propagates.

Help Please ! A fisherman casts his lure at an angle of 33 degrees above the horizontal. The lure reaches a maximum height of 2.3 m. Assuming no frictional forces, what was the initial velocity the fisherman gave the lure when he cast it? 12.34 m/s

28.45 m/s

34.91 m/s

21.29 m/s

Answers

The initial velocity is 12.34 m/s

Explanation:

The vertical component of the initial velocity determines the maximum height.

The formula to apply is : v²=u²+2as , where

v=y-component, final velocity = 0 m/s

u= y-component of the initial velocity = ?

s= distance traveled = 2.3 m

a=acceleration due to gravity = -9.81 m/s²

Using the values in the equation

v²=u²+2as

0²=u²+2×2.3×-9.81

0=u²-45.126

45.126=u²

√45.126= u

6.7175 m/s

The vertical component of velocity is given by;

velocity*sin(angle with horizontal)

velocity=6.7175 / sin 33°

=12.338 m/s

=12.34 m/s

Learn More

Finding Initial velocity :brainly.com/question/1858995

Keywords : angle, maximum height, initial velocity, friction

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What determines all the star's properties such as its temperature, size, brightness and life span?a. Weight b. Mass c. Diameter d. Luminosity

Answers

The correct answer to the question that is stated above is letter d. Luminosity.
Luminosity is the total energy that star produce in one second, depending on both the radius of the star and on its surface temperature. Thus, all the star's properties such as its temperature, size, brightness and life span is determined by its luminosity.

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