The atoms in non metals tend to _____ electrons. Is it gain?

Answers

Answer 1

Answer: YES! good job
they do tend to gain electrons!

Answer 2

Answer: Non metals gain electrons

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What is my skeletal system made of

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your skeletal system consists of all the 206 bones and the 360 joints in the human body. This includes the cells, protein fibers and minerals that make up your bones.

Find the ΔH for the reaction below, given the following reactions and subsequent ΔH values: PCl5(g) → PCl3(g) + Cl2(g) P4(s) + 6Cl2(g) → 4PCl3(g) ΔH = -2439 kJ
4PCl5(g) → P4(s) + 10Cl 2(g) ΔH = 3438 kJ

Answers

The value of ΔH will be 249.75 KJ.

To obtain the reaction :

PCl5(g) → PCl3(g) + Cl2(g)

We have to add the given reactions and then divide it by 4.

(i) adding the reactions

P4(s) + 6Cl2(g) → 4PCl3(g) ΔH = -2439 kJ

4PCl5(g) → P4(s) + 10Cl 2(g) ΔH = 3438 kJ

we get:

4PCl5(g) → 4PCl3(g) + 4Cl2(g), ΔH = 3438 - 2439

(ii) dviding by 4

PCl5(g) → PCl3(g) + Cl2(g) , ΔH = (3438 - 2439)/4

ΔH = 249.75 kJ is the required enthapy.

Learn more about enthalpy:

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Answer:

The value of $\Delta H$ for the desired reaction will be 249.75 KJ.

Explanation:

The desired reaction is shown below

$\textrm{PCl}_(5)\left ( g \right )\rightarrow \textrm{PCl}_(3)\left ( g \right )+\textrm{Cl}_(2)\left ( g \right )$

The desired reaction can be obtained by adding the given reactions and then dividing both sides by 4.

$P_(4)\left ( s \right )+6Cl_(2)\left ( g \right )\rightarrow 4PCl_(3)\left ( g \right ) \n4PCl_(5)\left ( g \right )\rightarrow P_(4)\left ( s \right )+10Cl_(2)\left ( g \right )$

Net Enthalpy change for the desired reaction

$\displaystyle (3438-2439)/(4) \textrm{ KJ} = 249.75 \textrm{ KJ}$

$\Delta H = 249.75 \textrm{ KJ}$

write equations to show the chemical processes which occur when the first ionization and the second ionization energies of lithium are measured?

Answers

Answer:

First ionization of lithium:

$\text{Li}\;(g)\to \text{Li}^(+) \; (g) + \text{e}^(-)$ .

Second ionization of lithium:

$\text{Li}^(+)\;(g) \to\text{Li}^(2+) \;(g) + \text{e}^(-)$ .

Explanation:

The ionization energy of an element is the energy required to remove the outermost electron from an atom or ion of the element in gaseous state. (Refer to your textbook for a more precise definition.) Some features of the equation:

Start with a gaseous atom (for the first ionization energy only) or a gaseous ion. Write the gaseous state symbol $(g)$ next to any atom or ion in the equation.
The product shall contain one gaseous ion and one electron. The charge on the ion shall be the same as the order of the ionization energy. For the second ionization energy, the ion shall carry a charge of +2.
Charge shall balance on the two sides of the equation.

First Ionization Energy of Li:

The products shall contain a gaseous ion with charge +1 $\text{Li}^(+)\;(g)$ as well as an electron $\text{e}^(-)$ .
Charge shall balance on the two sides. There's no net charge on the product side. Neither shall there be a charge on the reactant side. The only reactant shall be a lithium atom which is both gaseous and neutral: $\text{Li}\;(g)$ .

Hence the equation: $\text{Li}\;(g) \to \text{Li}^(+)\;(g) + \text{e}^(-)$ .

Second Ionization Energy of Li:

The product shall contain a gaseous ion with charge +2: $\text{Li}^(2+)\;(g)$ as well as an electron $\text{e}^(-)$ .
Charge shall balance on the two sides. What's the net charge on the product side? That shall also be the charge on the reactant side. What will be the reactant?

The equation for this process is $\text{Li}^(+) \; (g) \to \text{Li}^(2+)\;(g) + \text{e}^(-)$ .

Final answer:

The first ionization energy of lithium is represented by the equation: Li(g) -> Li+(g) + e-, with an energy of +54.4 eV. The second ionization energy is represented by the equation: Li+(g) -> Li2+(g) + e-, with an energy of 30.6 eV. These equations demonstrate the process of ionization.

Explanation:

The ionization energy of an element is the energy required to remove an electron from a gaseous atom or ion. The first ionization energy of lithium is represented by the equation: Li(g) -> Li+(g) + e-, the energy required for this process is +54.4 eV.

The second ionization energy refers to the energy required to remove the second electron. For lithium, the second ionization energy is represented by the equation: Li+(g) -> Li2+(g) + e-, the energy needed for ionizing the second electron is 30.6 eV.

The equations represent the processes which occur when the first ionization and the second ionization energies of lithium are measured.

Learn more about Ionization Energies of Lithium here:

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What is alloys? write the composition of bronze and brass

Answers

Brass is comprised of copper and zinc.
Bronze is comprised of copper and tin.

An alloy is a mixture of 2 or more metals or nonmetals or a metal and a nonmetal. Alloys are made, in order to suit the desired properties, which other metals/nonmetals don't have. Alloys are made by mixing the metal/nonmetal powders or by mixing them in molten state, etc..
Bronze consists of Copper & Tin
Brass consists of Copper & Zinc.
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List 4 clues that a chemical reaction is occurring

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