What is 40 percent as a decimal?

Answers

Answer 1

Answer: Your answer= .4
To change 40% into a fraction, you have to move the decimal two spots to the left. If you are turning a decimal into a percent, you would move the decimal two spots to the right.

Answer 2

Answer:

Answer:

$\Large \boxed{0.4}$

Step-by-step explanation:

To write a percent for a decimal, move the decimal point two places to the right. Add the percent sign.

First, divide by 100.

40/100=0.4

Therefore, the correct answer is 0.4.

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Please help I need to know before tomorrow
Carmen buys 153 shares of Cawh Consolidated Banks, each of which pays a constant yearly dividend of $7.14. After six years, how much has Carmen received in dividends?a. $5,783.40 b. $1,820.70 c. $1,092.42 d. $6,554.52

Week 151. Sue wants to solve the following equation:
+5 = 12
What step should she take first?
A Multiply both sides by 6.
B. Subtract 12 by both sides.
C. Subtract 5 by both sides,
D. Add 5 to both sides.
MS7 12-1

Answers

I’m assuming the equation is something like x+5 = 12, so it would be C but if the equation is something like (x+5)/6 = 12 then its A

Answer:

huh what i dont get it huh lol this is what you get for stealing my points :)

Step-by-step explanation:

How Do I Find The Domain & Range Of
y=2x-4 ?

Answers

Both the domain and range of the function is in range -

( - ∞ , + ∞ )

We have the following function -

y = f(x) = 2x - 4

We have to identify its Domain and Range.

What do you mean by domain and range of a function?

For any function y = f(x), Domain is the set of all possible values of y that exists for different values of x. Range is the set of all values of x for which y exists.

Consider the equation given -

y = 2x - 4

If we compare it with the general equation of line -

y = mx + c

We get -

m = 2 and c = - 4

Now this graph of the equation y = mx + c represents a straight line.

Hence, both the domain and range of the function are-

( - ∞ , + ∞ )

To solve more questions on Domain and Range, visit the link below -

brainly.com/question/20207421

#SPJ2

The domain is how far left and right it goes on a graph, and the range is how far up and down it goes on a graph. Because this equation is linear (if you graphed it, it would be in a straight line), both the domain and range are infinity, because it keeps going up and to the right, the larger X gets, and smaller and to the left, the more negative X gets.

Can someone help me in this trig question, please? thanks A person is on the outer edge of a carousel with a radius of 20 feet that is rotating counterclockwise around a point that is centered at the origin. What is the exact value of the position of the rider after the carousel rotates 5pi/12

Answers

The exact value of the position of the rider after the carousel rotates 5π/12 is 5 (-√2 + √6), 5(√2 + √6).

The position

Since the position of the carousel is (x, y) = (20cosθ, 20sinθ) and we need to find the position when θ = 5π/12 = 5π/12 × 180 = 75°

So, substituting the value of θ into the positions, we have

(20cos75°, 20sin75°)

The value of 20cos75°

20cos75° = 20cos(45 + 30)

Using the compound angle formula

cos(A + B) = cosAcosB - sinAsinB

With A = 45 and B = 30

cos(45 + 30) = cos45cos30 - sin45sin30

= 1/√2 × √3/2 - 1/√2 × 1/2

= 1/2√2(√3 - 1)

= 1/2√2(√3 - 1) × √2/√2

= √2(√3 - 1)/4

= (√6 - √2)/4

= (-√2 + √6)/4

So, 20cos75° = 20 × (-√2 + √6)/4

= 5 (-√2 + √6)

The value of 20sin75°

20sin75° = sin(45 + 30)

Using the compound angle formula

sin(A + B) = sinAcosB + cosAsinB

With A = 45 and B = 30

sin(45 + 30) = sin45cos30 + cos45sin30

= 1/√2 × √3/2 + 1/√2 × 1/2

= 1/2√2(√3 + 1)

= 1/2√2(√3 + 1) × √2/√2

= √2(√3 + 1)/4

= (√6 + √2)/4

= (√2 + √6)/4

So, 20sin75° = 20 × (√2 + √6)/4

= 5(√2 + √6)

Thus, (20cos75°, 20sin75°) = 5 (-√2 + √6), 5(√2 + √6).

So, the exact value of the position of the rider after the carousel rotates 5π/12 is 5 (-√2 + √6), 5(√2 + √6).

Learn more about position here:

brainly.com/question/11001232

$\bf \textit{the position of the rider is clearly }20cos\left( (5\pi )/(12) \right)~~,~~20sin\left( (5\pi )/(12) \right)\n\n-------------------------------\n\n\cfrac{5}{12}\implies \cfrac{2+3}{12}\implies \cfrac{2}{12}+\cfrac{3}{12}\implies \cfrac{1}{6}+\cfrac{1}{4}\n\n\n\textit{therefore then }\qquad \cfrac{5\pi }{12}\implies \cfrac{1\pi }{6}+\cfrac{1\pi }{4}\implies \cfrac{\pi }{6}+\cfrac{\pi }{4}\n\n-------------------------------$

$\bf \textit{Sum and Difference Identities}\n\nsin(\alpha + \beta)=sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta)\n\ncos(\alpha + \beta)= cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta)\n\n-------------------------------\n\ncos\left( (\pi )/(6)+(\pi )/(4) \right)=cos\left( (\pi )/(6)\right)cos\left((\pi )/(4) \right)-sin\left( (\pi )/(6)\right)sin\left((\pi )/(4) \right)$

$\bf cos\left( (\pi )/(6)+(\pi )/(4) \right)=\cfrac{√(3)}{2}\cdot \cfrac{√(2)}{2}-\cfrac{1}{2}\cdot \cfrac{√(2)}{2}\implies \cfrac{√(6)}{4}-\cfrac{√(2)}{4}\implies \boxed{\cfrac{√(6)-√(2)}{4}}\n\n\nsin\left( (\pi )/(6)+(\pi )/(4) \right)=sin\left( (\pi )/(6)\right)cos\left( (\pi )/(4) \right)+cos\left( (\pi )/(6)\right)sin\left((\pi )/(4) \right)$

$\bf sin\left( (\pi )/(6)+(\pi )/(4) \right)=\cfrac{1}{2}\cdot \cfrac{√(2)}{2}+\cfrac{√(3)}{2}\cdot \cfrac{√(2)}{2}\implies \cfrac{√(2)}{4}+\cfrac{√(6)}{4}\implies \boxed{\cfrac{√(2)+√(6)}{4}}\n\n-------------------------------\n\n20\left( \cfrac{√(6)-√(2)}{4} \right)\implies 5(-√(2)+√(6))\n\n\n20\left( \cfrac{√(2)+√(6)}{4} \right)\implies 5(√(2)+√(6))$

Juan Ramirez sells suits in a major department store on weekends. He earns a commission of 5 percent on the first ten suits, and if he sells more than ten, he earns an additional 3 percent on the additional suits.
Last weekend Juan sold thirteen $250 suits. What was his commission?

Answers

Commission on the first ten suits: p=5%=0.05
10 * 250 * 0.05 = 2500 * 0.05 = $125
Commission on additional 3 suits:p=5+3=8%=0.08
3 * 250 * 0.08= 750 * 0.08 = $60
In total: 125 + 60 = $185
Answer: His commission was $185.

N x 7 = 49 what is the missing added?

Answers

The missing added is N=7. 7×7= 49

7*7 = 49
or 49÷7 = 7
So, 7 is missing.

The cost of a taxi ride is 5 dollars plus 50 cents per mile. write an algebraic expression that models the cost of a taxi ride of m miles. A. m(5+0.5)
B.5+ 0.5/m
C.5+0.5m
D.5m+0.5

Answers

Answer:

Option C. 5 + 0.5m

Step-by-step explanation:

The cost of a taxi ride is = $5.00

with per mile charges = 50 cents = 0.5 dollar

If the taxi ride of m miles, to find the cost of a taxi ride, the expression will be

$5 + m($0.5)

Therefore Option C., 5 + 0.5m is the correct answer.

Simple.....

you have 5 dollars that it costs PLUS 0.50 PER mile.

Writing your equation...

0.5m (m=per mile extra)

5(how much it initially costs)

0.5m+5

Thus, your answer, C.

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