which of the following could be the first step in solving the equation below?5^x=21a. 1/5×5^x=1/5×21b. log5^x=log21c. log5^x=21d. sqrt[5]{ {5}^{x} } = sqrt[5]{21}

Answers

Answer 1
Answer:

ANSWER

\log _{}5^x\text{ = log21}

EXPLANATION

We want to find the very first step in solving the problem below:

5^x\text{ = 21}

If we wanted to jump steps, we could just state that the equation would become:

\log _521\text{ = x}

But that would be jumping a lot of steps and it is not among the options.

So, the very first step in solving this problem is to find the logarithm of both sides.

That is:

\log 5^x\text{ = log21}

That is the answer. (Option B)


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A team of 4 golfers scored 69,73,70, and 74 on the first round on apar 72 course. They reduced their team score by 3 on the second
round.
a) How many strokes above or below par was the team score on the
first round?

Answers

Answer: There are 2 strokes below par that the team has scored in the first round.

Step-by-step explanation:

Since we have given that

Scores of a team

69, 73, 70 and 74

on the first round on a part 72 course.

Now, we need to find the number of strokes above or below the par.

So, we will compare all the scores with 72.

So,

69-72 = -3(below par)

73-72 = 1 (above par)

70-72= - 2 (below par)

74-72 = 2 ( above par)

So, Number of strokes above or below par is given by

-3+1-2+2\n\n=-2

Hence, there are 2 strokes below par that the team has scored in the first round.

Cost to store: $140 Markup: 25% The selling price is $ .

Answers

Answer:

$175

Step-by-step explanation:

Cost to store: $140

Markup: 25%

  • The selling price= $140 + 25% = $140*1.25= $175

2. In an industrial training program, students have been averaging about 64 points on a standardized test. The lecture system was replaced by teaching machines with a lab instructor. There was some doubt as to whether the scores would decrease, increase, or stay the same. A sample of n = 60 students using the teaching machines was tested, resulting in a mean of 68 and a standard deviation of 12. Perform a hypothesis test to see if scores would decrease, increase, or stay the same. Use α = 0.05. Be sure to:1. State your hypotheses.
2. Find the value of the Test Statistic.
3. Find the p-value
4. State your decision (Reject or not)
5. State your conclusion.

Answers

Answer:

Case I

Null hypothesis:\mu = 64  

Alternative hypothesis:\mu \neq 64  

t=(68-64)/((12)/(√(60)))=2.582  

df=n-1=60-1=59  

Since is a two sided  test the p value would given by:  

p_v =2*P(t_((59))>2.582)=0.012  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v<\alpha so we can conclude that we have enough evidence to reject the null hypothesis.  

We can say that at 5% of significance the true mean is different from 64.

Case II

Null hypothesis:\mu \leq 64  

Alternative hypothesis:\mu > 64

The statistic not changes but the p value does and we have:

p_v =P(t_((59))>2.582)=0.006  

And we reject the null hypothesis on this case.

So we can conclude that the true mean is significantly higher than 64 at 5% of singnificance

Step-by-step explanation:

Data given and notation  

\bar X=68 represent the sample mean  

s=12 represent the sample standard deviation  

n=60 sample size  

\mu_o =64 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the population mean is different from 64 the system of hypothesis are :  

Null hypothesis:\mu = 64  

Alternative hypothesis:\mu \neq 64  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=(\bar X-\mu_o)/((s)/(√(n))) (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=(68-64)/((12)/(√(60)))=2.582  

P-value  

We need to calculate the degrees of freedom first given by:  

df=n-1=60-1=59  

Since is a two sided  test the p value would given by:  

p_v =2*P(t_((59))>2.582)=0.012  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v<\alpha so we can conclude that we have enough evidence to reject the null hypothesis.  

We can say that at 5% of significance the true mean is different from 64.

Now let's assume that we want to see if the mean is significantly higher than 64

Null hypothesis:\mu \leq 64  

Alternative hypothesis:\mu > 64

The statistic not changes but the p value does and we have:

p_v =P(t_((59))>2.582)=0.006  

And we reject the null hypothesis on this case.

So we can conclude that the true mean is significantly higher than 64 at 5% of singnificance

Can you help me find abcd please

Answers

Answer:

A.2 B.4 C.3 D.4 E.6

Step-by-step explanation:

1/2 ÷ 3/4 = 1/2 x 4/3 (flip 3/4 and keep 1/2)

If you multiply 1/2 x 4/3 you will get 4/6.

What is the solution to x^3 +4x^2 > x + 4

Answers

The solution consists of all of the true intervals is −4 < x < −1   x > 1.

−4<x<−1  or  x>1

Inequality Form: −4<x<−1  or  x>1

Interval Notation: (−4,−1)  ∪  (1,∞)

x^3 + 4x^2 > x + 4

Subtract x from both sides of the inequality.

x^3 + 4x^2 − x > 4

Convert the inequality to an equation.

x^3 + 4x^2 − x = 4

Move 4 to the left side of the equation by subtracting it from both sides.

x^3 + 4x^2>x+4

2 − x − 4 = 0

Factor the left side of the equation

(x + 4)(x + 1)(x − 1) = 0

If any individual factor on the left side of the equation is equal to, the entire expression will be equal to 0

x + 4 = 0

x + 1 = 0

x − 1 = 0

Set x + 4 equal to 0 and solve for x

x = −4

Set x + 1 equal to 0 and solve for x

What is inequality?

Inequality is the difference in social status, wealth, or opportunity between people or groups. People are concerned about social inequality.

x = −1

Set x + -1 equal to 0 and solve for x

x = 1

The final solution is all the values that make (x + 4)(x + 1)(x − 1) = 0  true

x = −4, −1, 1

Use each root to create test intervals.

x < −4

−4 < x < −1

−1 < x < 1

x > 1

Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the

inequality.

x < −4  ←False

−4 < x < −1  ←True

−1 < x < 1  ←False

x > 1  ←True

The solution consists of all of the true intervals.

−4 < x < −1 x > 1

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Simplify by using factoring: (2a+6b)(6b−2a)−(2a+6b)^2

Answers

The  simplified expression is -8a² - 24ab.

Given expression: (2a + 6b)(6b - 2a) - (2a + 6b)^2

First, let's expand the squared term (2a + 6b)^2:

(2a + 6b)(6b - 2a) - (2a + 6b)(2a + 6b)

Now, we have a common factor of (2a + 6b) in both terms, so let's factor it out:

(2a + 6b)[(6b - 2a) - (2a + 6b)]

Now, simplify the expression inside the brackets:

(2a + 6b)[6b - 2a - 2a - 6b]

Combining like terms within the brackets:

(2a + 6b)[-4a]

Now, multiply the remaining terms:

-4a(2a + 6b)

-8a² - 24ab

Therefore, the simplified expression is -8a² - 24ab.

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Answer:

-8a(a+3b)

Step-by-step explanation:

(2a+6b)(6b−2a)−(2a+6b)^2

(2a+6b) {(6b−2a)−(2a+6b)(2a+6b)}

2(a+3b) (6b-2a-2a-6b)

2(a+3b) (-4a)

-2(a+3b) x 4a

-2 x 4a (a+3b)

-8a(a+3b)